Chapter 1: Problem 59
Find any intercepts of the graph of the given equation. Determine whether the graph of the equation possesses symmetry with respect to the \(x\) -axis, \(y\) -axis, or origin. Do not graph. \(y=\frac{x^{2}-x-20}{x+6}\)
Short Answer
Expert verified
The intercepts are (0, -10/3), (5, 0), and (-4, 0). There is no symmetry.
Step by step solution
01
Find the y-intercept
To find the y-intercept, set \(x = 0\) in the equation \(y = \frac{x^2 - x - 20}{x + 6}\). This simplifies to \(y = \frac{0^2 - 0 - 20}{0 + 6} = \frac{-20}{6} = -\frac{10}{3}\). Therefore, the y-intercept is \( (0, -\frac{10}{3}) \).
02
Find the x-intercepts
To find the x-intercepts, set \(y = 0\), which implies \(\frac{x^2 - x - 20}{x + 6} = 0\). The numerator must be zero, so solve \(x^2 - x - 20 = 0\). Factor this as \((x - 5)(x + 4) = 0\), thus \(x = 5\) and \(x = -4\). Therefore, the x-intercepts are \((5, 0)\) and \((-4, 0)\).
03
Test for symmetry with respect to the x-axis
Replace \(y\) with \(-y\) in the original equation and see if the equation remains the same. This gives \(-y = \frac{x^2 - x - 20}{x + 6}\), which is not the same as the original equation. Therefore, the graph is not symmetric with respect to the x-axis.
04
Test for symmetry with respect to the y-axis
Replace \(x\) with \(-x\) in the original equation and check if the equation remains unchanged. This results in \(y = \frac{(-x)^2 - (-x) - 20}{-x + 6} = \frac{x^2 + x - 20}{-x + 6}\), which is different from the original equation, indicating no symmetry with respect to the y-axis.
05
Test for symmetry with respect to the origin
Replace \(x\) with \(-x\) and \(y\) with \(-y\) in the original equation. This leads to \(-y = \frac{(-x)^2 - (-x) - 20}{-x + 6} = \frac{x^2 + x - 20}{-x + 6}\), which differs from the original. Therefore, the graph does not have symmetry with respect to the origin.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
y-intercept
The y-intercept of a graph is the point where the graph intersects the y-axis. To find this point, you set the value of \( x \) to zero in the equation. This is because any point on the y-axis has an x-coordinate of zero.
For our equation, \( y = \frac{x^2 - x - 20}{x + 6} \), when \( x = 0 \), the equation becomes:
For our equation, \( y = \frac{x^2 - x - 20}{x + 6} \), when \( x = 0 \), the equation becomes:
- \( y = \frac{0^2 - 0 - 20}{0 + 6} \)
- \( y = \frac{-20}{6} \)
- \( y = -\frac{10}{3} \)
x-intercepts
The x-intercepts are the points where the graph intersects the x-axis. At these points, the value of \( y \) is zero. To find them, set the output or \( y \) equal to zero and solve the equation for \( x \).
In our function \( y = \frac{x^2 - x - 20}{x + 6} \), setting \( y = 0 \) implies:
In our function \( y = \frac{x^2 - x - 20}{x + 6} \), setting \( y = 0 \) implies:
- \( \frac{x^2 - x - 20}{x + 6} = 0 \)
- The numerator must be zero: \( x^2 - x - 20 = 0 \)
- Factoring gives \((x - 5)(x + 4) = 0\)
- Thus, \( x = 5 \) and \( x = -4 \).
symmetry of graphs
Symmetry in graphs can occur with respect to the x-axis, y-axis, or the origin. Testing for symmetry helps us understand the shape and structure of the graph without actually plotting it.
- To check symmetry about the x-axis, replace \( y \) with \( -y \). If the equation remains unchanged, the graph is symmetric with respect to the x-axis. Our function gives \( -y = \frac{x^2 - x - 20}{x + 6} \), which is not equal to the original equation, so there is no symmetry about the x-axis.
- For symmetry about the y-axis, replace \( x \) with \( -x \). If it remains the same, then symmetry exists. For our equation, it results in \( y = \frac{x^2 + x - 20}{-x + 6} \), which is different, indicating no symmetry about the y-axis.
- For symmetry about the origin, replace both \( x \) and \( y \) with \( -x \) and \( -y \) respectively. The equation becomes \( -y = \frac{x^2 + x - 20}{-x + 6} \), which also differs from the original, showing no origin symmetry.
solving quadratic equations
Quadratic equations are of the form \( ax^2 + bx + c = 0 \) and can often be solved by factoring. In other cases, the quadratic formula or completing the square might be necessary. Here, we needed to find x-intercepts by solving a quadratic equation. Let's break it down.
The quadratic equation from our example is \( x^2 - x - 20 = 0 \). To solve it:
Understanding how to handle quadratic equations is fundamental for finding intercepts and analyzing the behavior of polynomials within rational functions. It's a key skill in algebra that enriches your problem-solving toolkit.
The quadratic equation from our example is \( x^2 - x - 20 = 0 \). To solve it:
- First, attempt to factor it into two binomials.
- Notice that \((x - 5)(x + 4) = 0\), meaning the root solutions are \(x = 5\) and \(x = -4\).
Understanding how to handle quadratic equations is fundamental for finding intercepts and analyzing the behavior of polynomials within rational functions. It's a key skill in algebra that enriches your problem-solving toolkit.