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Use the determinant theorems to find the value of each determinant. $$\left|\begin{array}{lll} 1 & 6 & 7 \\ 0 & 6 & 7 \\ 0 & 0 & 9 \end{array}\right|$$

Short Answer

Expert verified
The determinant is 54.

Step by step solution

01

Recognize the Upper Triangular Matrix

Notice that the given matrix is an upper triangular matrix because all elements below the main diagonal (from top-left to bottom-right) are zeros.
02

Apply Determinant Theorem for Upper Triangular Matrix

For an upper triangular matrix, the determinant is the product of the diagonal elements. This means you need to multiply the values on the main diagonal.
03

Multiply the Diagonal Elements

Identify the diagonal elements: 1, 6, and 9. Multiply them together to find the determinant: \[ 1 \times 6 \times 9 = 54 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

understanding an upper triangular matrix
An upper triangular matrix is a type of matrix where all the elements below the main diagonal are zero. The main diagonal runs from the top-left to the bottom-right of the matrix. Understanding what qualifies as an upper triangular matrix is crucial because it simplifies many mathematical operations, including determinant calculation.

Here is the given matrix:

\[\left|\begin{array}{lll} 1 & 6 & 7 \ 0 & 6 & 7 \ 0 & 0 & 9 \end{array}\right|\]

Notice that all entries below the main diagonal (which are shaded if you visualize the matrix) are zeros:
  • The element at (2,1) is 0.
  • The element at (3,1) is 0.
  • The element at (3,2) is 0.
This structure makes the matrix an upper triangular matrix.

Being familiar with these matrices helps simplify calculations and save time in larger linear algebra problems.
determinant calculation of a triangular matrix
Calculating the determinant of a triangular matrix (which includes both upper and lower triangular matrices) is straightforward. For a triangular matrix, the determinant is simply the product of the diagonal elements. This is a significant simplification over the more general determinant calculation methods that usually require row reductions or cofactor expansions.

In this problem, the matrix is upper triangular, so we apply the following determinant theorem:
  • Identify the diagonal elements of the matrix.
  • Multiply these diagonal elements together.
For our matrix:
  • The diagonal elements are 1, 6, and 9.
  • So, the determinant is calculated as:
\[1 \times 6 \times 9 = 54\]

This allows us to quickly determine that the determinant of the given matrix is 54.

Learning this method is useful because it dramatically reduces the complexity of determinant calculations in specific cases.
matrix properties that help in determinant theorems
Understanding matrix properties is fundamental when working with determinants. Here we will touch on some key properties that are particularly helpful in this context:

  • Properties of Triangular Matrices: Both upper and lower triangular matrices allow for straightforward determinant calculations due to the zero elements below or above the main diagonal.

  • Zero Rows or Columns: If a matrix has a row or column consisting entirely of zeros, its determinant is zero. This is a quick check to avoid unnecessary calculations.

  • Equal Rows or Columns: If two rows or columns of a matrix are identical, the determinant is zero. This property can be handy in verifying your work or simplifying a solution.

  • Row Swaps: Swapping two rows (or columns) of a matrix multiplies the determinant by -1. This is relevant when rearranging matrices during calculations.

These properties and others help in understanding the broader subject of linear algebra and make solving determinant problems more manageable. Leveraging these properties simplifies many operations and avoids much manual computation.

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Most popular questions from this chapter

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Given \(A=\left[\begin{array}{rr}4 & -2 \\ 3 & 1\end{array}\right], B=\left[\begin{array}{rr}5 & 1 \\ 0 & -2 \\ 3 & 7\end{array}\right],\) and \(C=\left[\begin{array}{rrr}-5 & 4 & 1 \\ 0 & 3 & 6\end{array}\right],\) find each product when possible. $$A^{2}$$

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