/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Find the partial fraction decomp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the partial fraction decomposition for each rational expression. \(=\) $$\frac{2 x+4}{x^{3}-2 x^{2}}$$

Short Answer

Expert verified
\(\frac{2x + 4}{x^2 (x - 2)} = \frac{-2}{x} + \frac{-2}{x^2} + \frac{2}{x - 2}\)

Step by step solution

01

- Factorize the Denominator

First, factor the denominator. The given denominator is \(x^3 - 2x^2\). Factor out the common factor \(x^2\): \[x^3 - 2x^2 = x^2(x - 2)\]
02

- Set Up the Partial Fraction

Next, express the given rational expression as a sum of partial fractions. We now write: \[\frac{2x + 4}{x^2(x - 2)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x - 2}\]
03

- Multiply through by the Common Denominator

Multiply both sides by the common denominator \(x^2(x - 2)\) to clear the fractions: \[2x + 4 = A x (x - 2) + B(x - 2) + C x^2\]
04

- Expand and Combine Similar Terms

Expand and combine like terms: \[2x + 4 = A x^2 - 2A x + B x - 2B + C x^2\] Combine like terms: \[2x + 4 = (A + C)x^2 + (-2A + B)x - 2B\]
05

- Set Up the System of Equations

Compare coefficients of \(x^2\), \(x\), and the constant term from both sides to create a system of linear equations: \[A + C = 0 \] \[-2A + B = 2 \] \[-2B = 4 \]
06

- Solve the System

Solve the system of equations: From \(-2B = 4\), solve for \(B\): \[B = -2\] Substitute \(B\) into \(-2A + B = 2\): \[-2A - 2 = 2 \Rightarrow -2A = 4 \Rightarrow A = -2\] Substitute \(A\) into \(A + C = 0\): \[-2 + C = 0 \Rightarrow C = 2\]
07

- Write the Partial Fraction Decomposition

Substitute \(A\), \(B\), and \(C\) back into the partial fractions: \[\frac{2x + 4}{x^2 (x - 2)} = \frac{-2}{x} + \frac{-2}{x^2} + \frac{2}{x - 2}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring polynomials is an essential skill in algebra that simplifies complex expressions. To factor a polynomial, you break it down into simpler terms, which, when multiplied together, give you the original polynomial. In our exercise, we faced the expression \(x^3 - 2x^2\). The first step was to factor out the common term in this polynomial.
We noticed that both terms in \(x^3 - 2x^2\) share a common factor of \(x^2\). By factoring this out, we get:
\[x^3 - 2x^2 = x^2(x - 2)\]
Factoring helps us simplify the equation and makes further steps like partial fraction decomposition more manageable. Recognizing common factors quickly comes with practice. When factorizing, always look for common factors first, as they are usually the easiest to identify.
Rational Expressions
Rational expressions are fractions that have polynomials in their numerator and denominator. Our problem involves the rational expression \(\frac{2x + 4}{x^2(x - 2)}\). These expressions are crucial because they often appear in higher-level math and science.
When working with rational expressions, particularly when simplifying or decomposing them, always start with the factorization of the polynomials involved. This helps you understand the expression better. For partial fraction decomposition, recognizing the different types of factors in the denominator is vital.
In our exercise, after factorizing the denominator as \(x^2(x - 2)\), we expressed the rational expression as a sum of simpler fractions:
\[\frac{2x + 4}{x^2(x - 2)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x - 2}\]
This setup allowed us to use algebraic techniques to solve for the constants \(A\), \(B\), and \(C\). Substituting these constants helped us simplify the complex rational expression into simpler fractions, making it easier to work with.
Linear Equations
Linear equations are equations of the first degree, meaning they involve variables raised to the power of one. In the process of partial fraction decomposition, solving a system of linear equations is an essential step.
We first expanded and combined like terms in the rational expression:
\[2x + 4 = (A + C)x^2 + (-2A + B)x - 2B\]
By comparing the coefficients of \(x^2\), \(x\), and the constant term from both sides, we created a system of linear equations:
\[A + C = 0 \]
\[-2A + B = 2 \]
\[-2B = 4 \]
Solving this system required simple algebraic manipulation. Eventually, we determined:
\[B = -2\]
\[A = -2\]
\[C = 2\]
This systematic approach to solving linear equations ensures that we get the correct constants for the partial fractions, aiding in the simplification of the rational expression.
Mastering linear equations is vital, as they are a fundamental part of algebra and appear frequently in various mathematical problems and real-life applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use Cramer's rule to solve each system of equations. If \(D=0,\) use another method to determine the solution set. $$\begin{aligned} &5 x+4 y=10\\\ &3 x-7 y=6 \end{aligned}$$

Storage Capacity An office manager wants to buy some filing cabinets. He knows that cabinet A costs \(\$ 10\) each, requires \(6 \mathrm{ft}^{2}\) of floor space, and holds \(8 \mathrm{ft}^{3}\) of files. Cabinet B costs \(\$ 20\) each, requires \(8 \mathrm{ft}^{2}\) of floor space, and holds \(12 \mathrm{ft}^{3}\) of files. He can spend no more than \(\$ 140\) due to budget limitations, and his office has room for no more than \(72 \mathrm{ft}^{2}\) of cabinets. He wants to maximize storage capacity within the limits imposed by funds and space. How many of each type of cabinet should he buy?

Solve each problem. A cashier has a total of 30 bills, made up of ones, fives, and twenties. The number of twenties is 9 more than the number of ones. The total value of the money is \(\$ 351 .\) How many of each denomination of bill are there?

Solve each problem. The Fan Cost Index (FCI) is a measure of how much it will cost a fam- ily of four to attend a professional sports event. In \(2010,\) the FCI prices for Major League Baseball and the National Football League averaged \(\$ 307.76 .\) The FCI for baseball was \(\$ 225.56\) less than that for football. What were the FCIs for these sports? (Source: Team Marketing Report.)

Use Cramer's rule to solve each system of equations. If \(D=0,\) use another method to determine the solution set. $$\begin{array}{l} 2 x-3 y+z-8=0 \\ -x-5 y+z+4=0 \\ 3 x-5 y+2 z-12=0 \end{array}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.