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Use the Gauss-Jordan method to solve each system of equations. For systems in two variables with infinitely many solutions, give the solution with y arbitrary. For systems in three variables with infinitely many solutions, give the solution with z arbitrary. $$\begin{aligned}&x-z=-3\\\&y+z=9\\\&x+z=7\end{aligned}$$

Short Answer

Expert verified
The solution is: \( x = 2 \), \( y = 4 \), \( z = 5 \)

Step by step solution

01

Write the augmented matrix

Write the system of equations as an augmented matrix. \[\begin{bmatrix} \ 1 & 0 & -1 & | & -3 \ \ 0 & 1 & 1 & | & 9 \ \ 1 & 0 & 1 & | & 7 \end{bmatrix} \]
02

Make the leading coefficient of the first row a 1

It is already a 1.
03

Eliminate the first column below the leading 1

Subtract row 1 from row 3: \[\begin{bmatrix} 1 & 0 & -1 & | & -3 \ 0 & 1 & 1 & | & 9 \ 0 & 0 & 2 & | & 10 \end{bmatrix} \]
04

Normalize the third row

Divide row 3 by 2: \[\begin{bmatrix} 1 & 0 & -1 & | & -3 \ 0 & 1 & 1 & | & 9 \ 0 & 0 & 1 & | & 5 \end{bmatrix} \]
05

Eliminate the third column in the first and second rows

Add row 3 to row 1, and subtract row 3 from row 2: \[\begin{bmatrix} 1 & 0 & 0 & | & 2 \ 0 & 1 & 0 & | & 4 \ 0 & 0 & 1 & | & 5 \end{bmatrix} \]
06

Write the solution of the system

The system is now in the form of an identity matrix, which gives us: \[ x = 2, \ y = 4, \ z = 5 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Augmented Matrix
In linear algebra, an augmented matrix is a key concept used to solve systems of equations. An augmented matrix is created by appending the columns of two matrices, often representing the coefficients of variables in a system of equations and the constants on the other side of the equation. For example, let's consider the system of equations given in the exercise: \( \begin{aligned}&x - z = -3\&y + z = 9\&x + z = 7\text{ } \end{aligned} \). To form the augmented matrix for this system:
\[ \begin{bmatrix} 1 & 0 & -1 & | & -3 \ 0 & 1 & 1 & | & 9 \ 1 & 0 & 1 & | & 7 \ \end{bmatrix} \].
The vertical bar separates the coefficients of the variables from the constants. The first column represents the coefficients of x, the second column for y, and the third for z. The numbers on the right of the vertical bar are the constants from each equation. The augmented matrix is a helpful tool because it allows us to apply methods like the Gauss-Jordan elimination more systematically to find solutions.
System of Equations
A system of equations consists of multiple equations that share common variables, and the goal is to find values for these variables that satisfy all the equations simultaneously. In our exercise: \( \begin{aligned}&x - z = -3\&y + z = 9\&x + z = 7\text{ } \end{aligned} \), we are asked to solve three equations with three variables (x, y, and z). There are several methods to solve such systems, including substitution, elimination, and matrix methods like the Gauss-Jordan method. Each equation provides a different piece of the puzzle, working together to narrow down the possible solutions:
  • Substitution entails solving one of the equations for one variable and then substituting that solution into the other equations.
  • Elimination involves adding or subtracting equations to eliminate one variable, making it easier to solve for others.
  • Matrix methods convert the system of equations into a more manageable form.

Understanding how to handle systems of equations is fundamental in linear algebra and is widely used in various scientific fields and real-world applications.
Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, vector spaces, linear transformations, and systems of linear equations. It provides the foundational framework needed to solve sets of linear equations like the one in the exercise. Core topics in linear algebra include:
  • Vectors and Scalars: Basic elements used to form vector spaces.
  • Matrices: Rectangular arrays of numbers that can represent systems of equations.
  • Determinants: A scalar value that can be computed from a square matrix and provides useful properties about the matrix.
  • Vector Spaces: Collections of vectors where vector addition and scalar multiplication are defined.

In the context of solving systems of equations, the Gauss-Jordan method is a powerful algorithm that transforms an augmented matrix into reduced row-echelon form. This process simplifies the system, revealing the solutions directly. For instance, in our example, after applying the Gauss-Jordan method, we turn the given system into an identity matrix, making it clear that the solutions are: \( x = 2, \ y = 4, \ z = 5. \)
By mastering linear algebra techniques, you gain the tools to solve complex mathematical problems and develop a deeper understanding of mathematical structures.

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Solve each problem. Several years ago, mathematical ecologists created a model to analyze population dynamics of the endangered northern spotted owl in the Pacific Northwest. The ecologists divided the female owl population into three categories: juvenile (up to \(1 \text { yr old }),\) subadult \((1\) to 2 yr old ) and adult (over 2 yr old). They concluded that the change in the makeup of the northern spotted owl population in successive years could be described by the following matrix equation. $$ \left[\begin{array}{c} j_{n+1} \\ s_{n+1} \\ a_{n+1} \end{array}\right]=\left[\begin{array}{rrr} 0 & 0 & 0.33 \\ 0.18 & 0 & 0 \\ 0 & 0.71 & 0.94 \end{array}\right]\left[\begin{array}{c} j_{n} \\ s_{n} \\ a_{n} \end{array}\right] $$ The numbers in the column matrices give the numbers of females in the three age groups after \(n\) years and \(n+1\) years. Multiplying the matrices yields the following. \(j_{n+1}=0.33 a_{n}\) Each year 33 juvenile females are born for each 100 adult females. \(s_{n+1}=0.18 j_{n}\) Each year 18\% of the juvenile females survive to become subadults. \(a_{n+1}=0.71 s_{n}+0.94 a_{n} \quad\) Each year \(71 \%\) of the subadults survive to become adults, and \(94 \%\) of the adults survive. (a) Suppose there are currently 3000 female northern spotted owls made up of 690 juveniles, 210 subadults, and 2100 adults. Use the matrix equation on the preceding page to determine the total number of female owls for each of the next 5 yr. (b) Using advanced techniques from linear algebra, we can show that in the long run, $$ \left[\begin{array}{c} j_{n+1} \\ s_{n+1} \\ a_{n+1} \end{array}\right] \approx 0.98359\left[\begin{array}{c} j_{n} \\ s_{n} \\ a_{n} \end{array}\right] $$ What can we conclude about the long-term fate of the northern spotted owl? (c) In the model, the main impediment to the survival of the northern spotted owl is the number 0.18 in the second row of the 3 \(\times 3\) matrix. This number is low for two reasons. The first year of life is precarious for most animals living in the wild. In addition, juvenile owls must eventually leave the nest and establish their own territory. If much of the forest near their original home has been cleared, then they are vulnerable to predators while searching for a new home. Suppose that, thanks to better forest management, the number 0.18 can be increased to \(0.3 .\) Rework part (a) under this new assumption.

Given \(A=\left[\begin{array}{rr}4 & -2 \\ 3 & 1\end{array}\right], B=\left[\begin{array}{rr}5 & 1 \\ 0 & -2 \\ 3 & 7\end{array}\right],\) and \(C=\left[\begin{array}{rrr}-5 & 4 & 1 \\ 0 & 3 & 6\end{array}\right],\) find each product when possible. $$C A$$

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