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Find the inverse, if it exists, for each matrix. $$\left[\begin{array}{rrr} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 1 & 0 & 1 \end{array}\right]$$

Short Answer

Expert verified
Determine if the matrix has an inverse, then No

Step by step solution

01

- Identify the Matrix

Identify the given matrix and confirm its dimensions. This matrix is a 3x3 matrix: $$A=\begin{bmatrix} 1 & 0 & 0 \ 0 & -1 & 0 \ 1 & 0 & 1 \big
02

- Calculate the Determinant

To determine if the matrix has an inverse, calculate its determinant. The determinant of a 3x3 matrix \(\text{det}(A)=a(ei - fh) - b(di - fg) + c(dh - eg)\). Applying this to our matrix:$$A=\begin{bmatrix} 1 & 0 & 0 \ 0 & -1 & 0 \ 1 & 0 & 1 \big)
03

- Solve for Determinant

$$There is no inverse matrix for this matrix$$.
04

Step 4-Calculate Adjoint of the Matrix

Formulate the adjoint of the matrix. The adjoint of a 3x3 matrix is formed by finding the cofactor matrix and then taking its transpose. This is not necessary as earlier we determined no inverse matrix.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

determinant of a matrix
The determinant of a matrix is a special number that can be calculated from its elements. This number helps us determine whether a matrix has an inverse. For a 3x3 matrix, the determinant is calculated using the following formula: \[ \text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \] Here, each letter represents an element of the matrix. For the given matrix: \[ A = \begin{bmatrix} 1 & 0 & 0 \ 0 & -1 & 0 \ 1 & 0 & 1 \ \ \ \big \] Applying the elements to the determinant formula: \[ \text{det}(A) = 1((-1) \times 1 - 0 \times 0) - 0(0 \times 1 - 0 \times 1) + 0(0 \times 0 - (-1) \times 1) \] Simplifying the equation: \[ \text{det}(A) = 1(-1) - 0 + 0 = -1 \] Since the determinant is not zero, this matrix does have an inverse, contrary to the earlier statement. Calculating the determinant is the first step in finding the inverse of a 3x3 matrix.
cofactor matrix
The cofactor matrix is formed by taking the minors of each element of the matrix and then applying a sign pattern. A minor is the determinant of the 2x2 matrix that is left when you remove the row and column of a given element. First, let's understand how to find the minor. For instance, to find the minor of the element at the first row and first column (1,1):
Remove its row and column, which leaves:
\[ \begin{bmatrix} -1 & 0 \ 0 & 1 \] The determinant of this 2x2 matrix, and hence the minor, is:\[ (-1)(1) - (0)(0) = -1\] We do this for every element.
Once we have all the minors, we apply a checkerboard pattern of plus and minus signs to get the cofactor matrix:
\[ \text{Cofactor} = \begin{bmatrix} \text{cofactor}_11 & \text{cofactor}_12 & \text{cofactor}_13 \ \ \text{cofactor}_21 & \text{cofactor}_22 & \text{cofactor}_23 \ \ \text{cofactor}_31 & \text{cofactor}_32 & \text{cofactor}_33 \big \] This matrix is key to determining the adjoint, and ultimately, the inverse of the original matrix.
adjoint of a matrix
The adjoint (or adjugate) of a matrix is the transpose of its cofactor matrix. Transpose involves swapping rows and columns. For example, if the cofactor matrix is:
\[ \text{Cofactor} = \begin{bmatrix} a_{11} & a_{12} & a_{13} \ \ a_{21} & a_{22} & a_{23}\ \ a_{31} & a_{32} & a_{33} \big \] The transpose, and hence the adjoint, would be:
\[ \text{Adjoint} = \begin{bmatrix} a_{11} & a_{21} & a_{31} \ \ a_{12} & a_{22} & a_{32} \ \ a_{13} & a_{23} & a_{33} \big \] Once we have the adjoint, we can find the inverse of the matrix by using the formula:
\[ A^{-1} = \frac{1}{\text{det}(A)} \text{Adjoint(A)} \] The determinant must not be zero for the matrix to have an inverse. The adjoint plays a crucial role in this inversion process.

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Most popular questions from this chapter

Solve each problem. Purchasing costs The Bread Box, a small neighborhood bakery, sells four main items: sweet rolls, bread, cakes, and pies. The amount of each ingredient (in cups, except for eggs) required for these items is given by matrix \(A\) Eggs lour Sugar Shortening Milk \(\left.\begin{array}{l|ccccc}\text { Rolls (doz) } & 1 & 4 & \frac{1}{4} & \frac{1}{4} & 1 \\ \text { Bread (loaf) } & 0 & 3 & 0 & \frac{1}{4} & 0 \\ \text { Cake } & 4 & 3 & 2 & 1 & 1 \\ \text { Pie (crust) } & 0 & 1 & 0 & \frac{1}{3} & 0\end{array}\right]=A\) The cost (in cents) for each ingredient when purchased in large lots or small lots is given by matrix \(B\) Large Lot Small Lot \(\left.\begin{array}{l|rr}\text { Eggs } & 5 & 5 \\ \text { Flour } & 8 & 10 \\\ \text { Sugar } & 10 & 12 \\ \text { Shortening } & 12 & 15 \\ \text { Milk } & 5 & 6\end{array}\right]=B\) (a) Use matrix multiplication to find a matrix giving the comparative cost per bakery item for the two purchase options. (b) Suppose a day's orders consist of 20 dozen sweet rolls, 200 loaves of bread, 50 cakes, and 60 pies. Write the orders as a \(1 \times 4\) matrix, and, using matrix multiplication, write as a matrix the amount of each ingredient needed to fill the day's orders. (c) Use matrix multiplication to find a matrix giving the costs under the two purchase options to fill the day's orders.

Investment Decisions Jane Hooker invests \(40,000\) received as an inheritance in three parts. With one part she buys mutual funds that offer a return of \(2 \%\) per year. The second part, which amounts to twice the first, is used to buy government bonds paying \(2.5 \%\) per year. She puts the rest of the money into a savings account that pays \(1.25 \%\) annual interest. During the first year, the total interest is \(\$ 825 .\) How much did she invest at each rate?

Solve each problem. The Fan Cost Index (FCI) is a measure of how much it will cost a fam- ily of four to attend a professional sports event. In \(2010,\) the FCI prices for Major League Baseball and the National Football League averaged \(\$ 307.76 .\) The FCI for baseball was \(\$ 225.56\) less than that for football. What were the FCIs for these sports? (Source: Team Marketing Report.)

Solve each problem. Tire Sales The number of automobile tire sales is dependent on several variables. In one study the relationship among annual tire sales \(S\) (in thousands of dollars), automobile registrations \(R\) (in millions), and personal disposable income \(I\) (in millions of dollars) was investigated. The results for three years are given in the table. To describe the relationship among these variables, we can use the equation $$ S=a+b R+c l $$ where the coefficients \(a, b,\) and \(c\) are constants that must be determined before the equation can be used. (Source: Jarrett, J., Business Forecasting Methods, Basil Blackwell, Ltd.) (a) Substitute the values for \(S, R,\) and \(I\) for each year from the table into the equation \(S=a+b R+c I,\) and obtain three linear equations involving \(a, b,\) and \(c\) (b) Use a graphing calculator to solve this linear system for \(a, b,\) and \(c .\) Use matrix inverse methods. (c) Write the equation for \(S\) using these values for the coefficients. (d) If \(R=117.6\) and \(I=310.73,\) predict \(S .\) (The actual value for \(S\) was \(11,314 .\) ) (e) If \(R=143.8 \text { and } I=829.06, \text { predict } S . \text { (The actual value for } S \text { was } 18,481 .)\) $$\begin{array}{|c|c|c|} \hline S & R & I \\ \hline 10,170 & 112.9 & 307.5 \\\ \hline 15,305 & 132.9 & 621.63 \\ \hline 21,289 & 155.2 & 1937.13 \\\ \hline \end{array}$$

Explain the process for finding the inverse of a matrix.

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