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Decide whether or not the given matrices are imerses of each other. (Hint: Check to see whether their products are the identity matrix \(I_{n-}\) ) $$\left[\begin{array}{lll} 1 & 3 & 3 \\ 1 & 4 & 3 \\ 1 & 3 & 4 \end{array}\right] \text { and }\left[\begin{array}{rrr} 7 & -3 & -3 \\ -1 & 1 & 0 \\ -1 & 0 & 1 \end{array}\right]$$

Short Answer

Expert verified
Yes, the matrices are inverses of each other as their product is the identity matrix.

Step by step solution

01

Understand the Problem

To determine if two matrices are inverses of each other, you must check whether their product is the identity matrix.
02

Define the Matrices

The given matrices are: \[ A = \begin{pmatrix} 1 & 3 & 3 \ 1 & 4 & 3 \ 1 & 3 & 4 \ \ B = \begin{pmatrix} 7 & -3 & -3 \ -1 & 1 & 0 \ -1 & 0 & 1 \ \ \right) \]
03

Compute the Product of A and B

Multiply the matrices A and B.\[ AB = \begin{pmatrix} 1 & 3 & 3 \ 1 & 4 & 3 \ 1 & 3 & 4 \ \right)\begin{pmatrix} 7 & -3 & -3 \ -1 & 1 & 0 \ -1 & 0 & 1 \ \ = \begin{pmatrix} (1*7 + 3*(-1) + 3*(-1)) & (1*(-3) + 3*1 + 3*0) & (1*(-3) + 3*0 + 3*1) \ (1*7 + 4*(-1) + 3*(-1)) & (1*(-3) + 4*1 + 3*0) & (1*(-3) + 4*0 + 3*1) \ (1*7 + 3*(-1) + 4*(-1)) & (1*(-3) + 3*1 + 4*0) & (1*(-3) + 3*0 + 4*1) \ \ \right) = \begin{pmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \ \right) \]
04

Interpret the Result

The product of matrices A and B is the identity matrix. This shows that A and B are indeed inverses of each other.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a key operation where you multiply two matrices to get another matrix. To multiply matrices, you follow a specific set of steps:
First, ensure that the number of columns in the first matrix (Matrix A) is equal to the number of rows in the second matrix (Matrix B).
The product of two matrices is found by taking the dot product of the rows of the first matrix with the columns of the second matrix. This involves multiplying corresponding entries and then summing up these products.
For example, if you have Matrix A as \(\begin{pmatrix}1 & 3 & 3 \ 1 & 4 & 3 \ 1 & 3 & 4 \end{pmatrix}\) and Matrix B as \(\begin{pmatrix}7 & -3 & -3 \ -1 & 1 & 0 \ -1 & 0 & 1 \end{pmatrix}\), then you multiply them as follows:
For the first entry in the resulting matrix, multiply the first row of A by the first column of B and add them up: \(1*7 + 3*(-1) + 3*(-1) = 1\).
Repeat this process for each entry to form the resulting matrix.
Identity Matrix
An identity matrix is a special type of square matrix where all the elements of the principal diagonal are ones, and all other elements are zeros.
For instance, the 3x3 identity matrix is represented as: \(I = \begin{pmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{pmatrix}\).
The identity matrix plays a crucial role in matrix operations because it acts like the number 1 in matrix multiplication.
When you multiply any matrix by the identity matrix, you get the original matrix back: \(A \cdot I = A\). This property is helpful in determining whether two matrices are inverses of each other.
Inverse Matrices
Inverse matrices are an important concept in linear algebra. For a matrix A, its inverse is denoted by \(A^{-1}\).
The inverse of a matrix exists only if the matrix is square (i.e., it has the same number of rows and columns) and if it has a non-zero determinant.
Two matrices A and B are said to be inverses if their product is the identity matrix: \(A \cdot B = I\) and \(B \cdot A = I\).
In the given exercise, the product of matrices A and B was calculated and shown to be the identity matrix, demonstrating that A and B are inverses. This means all the elements of A and B work perfectly together to bring back the identity matrix when multiplied, signifying they undo each other's effect.

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Most popular questions from this chapter

$$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right], \quad B=\left[\begin{array}{ll} b_{11} & b_{12} \\ b_{21} & b_{22} \end{array}\right], \quad \text { and } \quad C=\left[\begin{array}{ll} c_{11} & c_{12} \\ c_{21} & c_{22} \end{array}\right] $$ where all the elements are real numbers. Use these matrices to show that each statement is true for \(2 \times 2\) matrices. \((A B) C=A(B C)\) (associative property)

Supply and Demand In many applications of economics, as the price of an item goes up, demand for the item goes down and supply of the item goes up. The price where supply and demand are equal is the equilibrium price, and the resulting sup. ply or demand is the equilibrium supply or equilibrium demand. Suppose the supply of a product is related to its price by the equation $$p=\frac{2}{3} q$$ where \(p\) is in dollars and \(q\) is supply in appropriate units. (Here, \(q\) stands for quantity.) Furthermore, suppose demand and price for the same product are related by $$p=-\frac{1}{3} q+18$$ where \(p\) is price and \(q\) is demand. The system formed by these two equations has solution \((18,12),\) as seen in the graph. (GRAPH CANNOT COPY) Find the demand for the electric can opener at each price. (a) \(\$ 6\) (b) \(\$ 11\) (c) \(\$ 16\)

Use a system of equations to solve each problem. Find the equation of the line \(y=a x+b\) that passes through the points \((3,-4)\) and \((-1,4)\)

Use Cramer's rule to solve each system of equations. If \(D=0,\) use another method to determine the solution set. $$\begin{aligned} &\frac{1}{2} x+\frac{1}{3} y=2\\\ &\frac{3}{2} x-\frac{1}{2} y=-12 \end{aligned}$$

For the following system, \(D=-43, D_{x}=-43, D_{y}=0,\) and \(D_{z}=43 .\) What is the solution set of the system? $$ \begin{aligned} x+3 y-6 z &=7 \\ 2 x-y+z &=1 \\ x+2 y+2 z &=-1 \end{aligned} $$

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