91Ó°ÊÓ

Consider the following nonlinear system. $$ \begin{array}{l} y=|x-1| \\ y=x^{2}-4 \end{array} $$ Work Exercise, to see how concepts from previous chapters are related to the graphs and the solutions of this system. How is the graph of \(y=|x-1|\) obtained by transforming the graph of \(y=|x| ?\)

Given \(A=\left[\begin{array}{rr}4 & -2 \\ 3 & 1\end{array}\right], B=\left[\begin{array}{rr}5 & 1 \\ 0 & -2 \\ 3 & 7\end{array}\right],\) and \(C=\left[\begin{array}{rrr}-5 & 4 & 1 \\ 0 & 3 & 6\end{array}\right],\) find each product when possible. $$C B$$

Use the determinant theorems to find the value of each determinant. $$\left|\begin{array}{rrr} 2 & -1 & 3 \\ 6 & 4 & 10 \\ 4 & 5 & 7 \end{array}\right|$$

Solve each system. $$\begin{aligned} &\frac{2}{x}+\frac{1}{y}=\frac{3}{2}\\\ &\frac{3}{x}-\frac{1}{y}=1 \end{aligned}$$

Consider the following nonlinear system. $$ \begin{array}{l} y=|x-1| \\ y=x^{2}-4 \end{array} $$ Work Exercise, to see how concepts from previous chapters are related to the graphs and the solutions of this system. How is the graph of \(y=x^{2}-4\) obtained by transforming the graph of \(y=x^{2} ?\)

Given \(A=\left[\begin{array}{rr}4 & -2 \\ 3 & 1\end{array}\right], B=\left[\begin{array}{rr}5 & 1 \\ 0 & -2 \\ 3 & 7\end{array}\right],\) and \(C=\left[\begin{array}{rrr}-5 & 4 & 1 \\ 0 & 3 & 6\end{array}\right],\) find each product when possible. $$A B$$

Consider the following nonlinear system. $$ \begin{array}{l} y=|x-1| \\ y=x^{2}-4 \end{array} $$ Work Exercise, to see how concepts from previous chapters are related to the graphs and the solutions of this system. Use the definition of absolute value to write \(y=|x-1|\) as a piecewisedefined function.

Given \(A=\left[\begin{array}{rr}4 & -2 \\ 3 & 1\end{array}\right], B=\left[\begin{array}{rr}5 & 1 \\ 0 & -2 \\ 3 & 7\end{array}\right],\) and \(C=\left[\begin{array}{rrr}-5 & 4 & 1 \\ 0 & 3 & 6\end{array}\right],\) find each product when possible. $$C A$$

Solve each system. $$\begin{aligned} &\frac{1}{x}+\frac{3}{y}=\frac{16}{5}\\\ &\frac{5}{x}+\frac{4}{y}=5 \end{aligned}$$

Use the determinant theorems to find the value of each determinant. $$\left|\begin{array}{rrr} 9 & 1 & 7 \\ 12 & 5 & 2 \\ 11 & 4 & 3 \end{array}\right|$$