Chapter 8: Problem 72
A Heron triangle is a triangle having integer sides and area. Show that each of the following is a Heron triangle. (a) \(a=11, b=13, c=20\) (b) \(a=13, b=14, c=15\) (c) \(a=7, b=15, c=20\) (d) \(a=9, b=10, c=17\)
Short Answer
Expert verified
All given triangles are Heron triangles.
Step by step solution
01
Understand Heron's formula
Heron's formula for the area of a triangle with sides of length a, b, and c is given by \[ A = \sqrt{s(s-a)(s-b)(s-c)} \]where s is the semi-perimeter of the triangle,\[ s = \frac{a+b+c}{2} \]
02
Check Triangle (a)
Given sides are a=11, b=13, c=20.Calculate the semi-perimeter s:\[ s = \frac{11 + 13 + 20}{2} = 22 \]Calculate the area using Heron's formula:\[ A = \sqrt{22(22-11)(22-13)(22-20)} = \sqrt{22 \cdot 11 \cdot 9 \cdot 2} = \sqrt{4356} = 66 \]Since the area is an integer, the triangle is a Heron triangle.
03
Check Triangle (b)
Given sides are a=13, b=14, c=15.Calculate the semi-perimeter s:\[ s = \frac{13 + 14 + 15}{2} = 21 \]Calculate the area using Heron's formula:\[ A = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \cdot 8 \cdot 7 \cdot 6} = \sqrt{7056} = 84 \]Since the area is an integer, the triangle is a Heron triangle.
04
Check Triangle (c)
Given sides are a=7, b=15, c=20.Calculate the semi-perimeter s:\[ s = \frac{7 + 15 + 20}{2} = 21 \]Calculate the area using Heron's formula:\[ A = \sqrt{21(21-7)(21-15)(21-20)} = \sqrt{21 \cdot 14 \cdot 6 \cdot 1} = \sqrt{1764} = 42 \]Since the area is an integer, the triangle is a Heron triangle.
05
Check Triangle (d)
Given sides are a=9, b=10, c=17.Calculate the semi-perimeter s:\[ s = \frac{9 + 10 + 17}{2} = 18 \]Calculate the area using Heron's formula:\[ A = \sqrt{18(18-9)(18-10)(18-17)} = \sqrt{18 \cdot 9 \cdot 8 \cdot 1} = \sqrt{1296} = 36 \]Since the area is an integer, the triangle is a Heron triangle.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heron's formula
Heron's formula is a mathematical tool for finding the area of a triangle when you know the lengths of all three sides. The formula is particularly useful because it doesn't require you to know any angles. The formula is given by \[\text{A} = \sqrt{s(s-a)(s-b)(s-c)}\], where \(\text{a}\), \(\text{b}\), and \(\text{c}\) are the lengths of the sides of the triangle, and \(\text{s}\) is the semi-perimeter of the triangle.\
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Using Heron's formula involves a few straightforward steps:\
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Using Heron's formula involves a few straightforward steps:\
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- First, compute the semi-perimeter \(s\).\li>Next, calculate the terms \(s - a\), \(s - b\), and \(s - c\).\
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Let's look at an example. For a triangle with sides 13, 14, and 15:\
\(a = 13\), \(\text{b} = 14\), and \(c = 15\), and calculating the semi-perimeter \(s = \frac{13 + 14 + 15}{2} = 21\).\
Now substitute the values back into Heron's formula: \[\text{A} = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \cdot 8 \cdot 7 \cdot 6} = 84\]. Johnny, be sure to use your calculator for the square root if needed!\
An evaluated area of 84, an integer, confirms it is a valid Heron triangle.
Semi-perimeter
The semi-perimeter of a triangle is essential in applying Heron's formula. The semi-perimeter \(s\) is simply half the perimeter of the triangle. To calculate semi-perimeter, add the lengths of all three sides and divide by two. For example, if the sides of the triangle are \(a = 11\), \(b = 13\), and \(c = 20\), then the semi-perimeter \(s\) is given by: \[\text{s} = \frac{11 + 13 + 20}{2} = 22\].\
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Semi-perimeter helps in breaking the problem into manageable parts. It allows us to separately evaluate factors inside Heron's formula. Once you have the semi-perimeter, you can compute \(s - a\), \(s - b\), and \(s - c\), which are intermediate steps essential for calculating the area of the triangle. \
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Here's how it works for another example: For \(a = 9\), \(b = 10\), and \(c = 17\), calculate \(s\): \[\text{s} = \frac{9 + 10 + 17}{2} = 18\].\ Remember, always ensure the calculations are correct through double-checking!
\
Semi-perimeter helps in breaking the problem into manageable parts. It allows us to separately evaluate factors inside Heron's formula. Once you have the semi-perimeter, you can compute \(s - a\), \(s - b\), and \(s - c\), which are intermediate steps essential for calculating the area of the triangle. \
\
Here's how it works for another example: For \(a = 9\), \(b = 10\), and \(c = 17\), calculate \(s\): \[\text{s} = \frac{9 + 10 + 17}{2} = 18\].\ Remember, always ensure the calculations are correct through double-checking!
Integer-sided triangles
Heron triangles are special because they not only have integer sides but also an integer area. To show a triangle is a Heron triangle, we must confirm both these conditions using Heron's formula. \
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Let's consider the triangle with sides \(a = 7\), \(b = 15\), and \(c = 20\). First, you calculate the semi-perimeter: \[s = \frac{7 + 15 + 20}{2} = 21\]. Next, use Heron's formula to determine the area \[A = \sqrt{21(21-7)(21-15)(21-20)} = \sqrt{21 \cdot 14 \cdot 6 \cdot 1} = \sqrt{1764} = 42\].\
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The integer result ensures that the triangle's properties comply with being a Heron triangle. Integer-sided triangles offer historical and practical significance, especially for geometrical and algebraic studies. Always remember to verify if the area is an integer to label it a Heron triangle correctly. This makes math problems easier and rewarding!
\
Let's consider the triangle with sides \(a = 7\), \(b = 15\), and \(c = 20\). First, you calculate the semi-perimeter: \[s = \frac{7 + 15 + 20}{2} = 21\]. Next, use Heron's formula to determine the area \[A = \sqrt{21(21-7)(21-15)(21-20)} = \sqrt{21 \cdot 14 \cdot 6 \cdot 1} = \sqrt{1764} = 42\].\
\
The integer result ensures that the triangle's properties comply with being a Heron triangle. Integer-sided triangles offer historical and practical significance, especially for geometrical and algebraic studies. Always remember to verify if the area is an integer to label it a Heron triangle correctly. This makes math problems easier and rewarding!