Chapter 8: Problem 7
For each pair of polar coordinates, ( \(a\) ) plot the point, ( \(b\) ) give two other pairs of polar coordinates for the point, and ( \(c\) ) give the rectangular coordinates for the point. $$\left(5,-60^{\circ}\right)$$
Short Answer
Expert verified
Plot point: \(5, 300^{\circ}\) or \(2.5, -4.33\). Two other polar coordinates: \((5, 660^{\circ})\), \((-5, 120^{\circ})\).
Step by step solution
01
- Convert Polar Angle
Identify the given polar coordinates: \ \((r, \theta) = (5, -60^{\circ})\)\. Since angular measurements can be cyclic, first convert the angle to a positive equivalent. For instance, \ -60^{\circ} = 360^{\circ} - 60^{\circ} = 300^{\circ}.
02
- Plot the Point
Plot the point \ \( (5, 300^{\circ}) \) \ on the polar coordinate system. Start from the polar axis, rotate 300 degrees counterclockwise, and measure a radius of 5 units from the origin.
03
- Find Two Other Polar Coordinates
Identify two other pairs of polar coordinates that represent the same point. Two such coordinates could be obtained by: \ 1) Adding 360 degrees: \((5, 300^{\circ} + 360^{\circ}) = (5, 660^{\circ})\)\. \ 2) Using a negative radius and adding/subtracting 180 degrees: \((-5, 300^{\circ} - 180^{\circ}) = (-5, 120^{\circ})\).
04
- Convert to Rectangular Coordinates
Convert the polar coordinates to rectangular coordinates using the formulas: \ \( x = r \cos(\theta) \) and \ \( y = r \sin(\theta) \). For \( r = 5 \) and \( \theta = 300^{\circ} \), \ \( x = 5\cos(300^{\circ}) = 5\cos(-60^{\circ}) = 5 \cdot \frac{1}{2} = 2.5 \)\ and \ \( y = 5\sin(300^{\circ}) = 5\sin(-60^{\circ}) = 5 \cdot \left(-\frac{\sqrt{3}}{2}\right) = -2.5\sqrt{3} \). Thus, the rectangular coordinates are approximately \( (2.5, -4.33) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates provide a way to represent points in a plane using a radius and an angle. Unlike the more commonly known Cartesian or rectangular system that uses x and y coordinates, polar coordinates focus on the distance from a fixed point (the origin) and the angle from a fixed direction (the polar axis, typically the positive x-axis). In the given exercise, the point is represented as \( (5, -60^{\backslash}circ) \). Here, 5 is the radius (distance from the origin), and \( -60^{\backslash}circ \) is the angle measured from the positive x-axis in the negative (clockwise) direction.To fully grasp polar coordinates:
- Think of the radius as how far you 'walk' from the origin.
- The angle tells you which 'direction' to walk in.
Rectangular Coordinates
Rectangular coordinates (Cartesian coordinates) define a point's location using two distances: one along the x-axis (horizontal) and another along the y-axis (vertical). For example, in the given solution, the polar coordinates \( (5, 300^{\backslash}circ) \) needed to be converted into rectangular coordinates. Coordinate conversion formulas are:
\( y = 5 \sin(300^{\backslash}circ) = 5 \cdot (-\frac{\sqrt{3}}{2}) = -2.5 \sqrt{3} \approx -4.33 \)
Thus, the rectangular coordinates are approximately \( (2.5, -4.33) \).
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
\( y = 5 \sin(300^{\backslash}circ) = 5 \cdot (-\frac{\sqrt{3}}{2}) = -2.5 \sqrt{3} \approx -4.33 \)
Thus, the rectangular coordinates are approximately \( (2.5, -4.33) \).
Angle Conversion
Angle conversion in polar coordinates is key to understanding the cyclic nature of angles. In the given problem, the polar coordinates \( (5, -60^{\backslash}circ) \) had a negative angle. Converting it to a positive equivalent makes it easier to plot and understand.For this purpose:
- Adding 360 degrees: \( -60^{\backslash}circ + 360^{\backslash}circ = 300^{\backslash}circ \), a positive equivalent.
- Understanding that angles in polar coordinates can exceed 360 degrees due to their cyclic nature. For example, you can add multiples of 360 degrees: \( 300^{\backslash}circ + 360^{\backslash}circ = 660^{\backslash}circ \).
- Using negative radius and adding/subtracting 180 degrees: In the solution, \( -5, 120^{\backslash}circ \) becomes the point, by adding 180 degrees to the angle when using a negative radius.
Trigonometric Functions
Trigonometric functions are fundamental when converting polar coordinates to rectangular coordinates. These functions relate angles in a triangle to lengths of the sides. The main functions involved are cosine (\(\cos\)) and sine (\(\sin\)).For the given problem, the polar coordinates \( (5, 300^{\backslash}circ) \) were converted as follows:
- \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \)
- Calculating the x-coordinate: \( 5 \cos(300^{\backslash}circ) = 5 \cdot 0.5 = 2.5 \)
- Calculating the y-coordinate: \( 5 \sin(300^{\backslash}circ)= 5 \cdot -\frac{\sqrt{3}}{2}= -2.5 \sqrt{3} \)