Chapter 8: Problem 20
For each pair of rectangular coordinates, ( \(a\) ) plot the point and (b) give two pairs of polar coordinates for the point, where \(0^{\circ} \leq \theta<360^{\circ} .\) $$(-\sqrt{2}, \sqrt{2})$$
Short Answer
Expert verified
The two pairs of polar coordinates are \( (2, 135^{\circ}) \) and \( (-2, 315^{\circ}) \).
Step by step solution
01
- Plot the Point
Locate the point \((-\sqrt{2}, \sqrt{2})\) on the Cartesian coordinate system. This point lies in the second quadrant, where x is negative and y is positive.
02
- Compute the Distance from Origin
Use the formula for the radius in polar coordinates: \[ r = \sqrt{x^2 + y^2} \] Substituting \( x = -\sqrt{2} \) and \( y = \sqrt{2} \), \[ r = \sqrt{(-\sqrt{2})^2 + (\sqrt{2})^2} = \sqrt{2 + 2} = \sqrt{4} = 2 \]
03
- Compute the Angle \theta for the First Pair
Use the tangent function to find the angle: \[ \tan(\theta) = \frac{y}{x} = \frac{\sqrt{2}}{-\sqrt{2}} = -1 \] So, \[ \theta = 135^{\circ} \] as we are in the second quadrant.
04
- Provide First Pair of Polar Coordinates
Thus, one pair of polar coordinates is \( (2, 135^{\circ}) \).
05
- Compute the Angle \theta for the Second Pair
For the second pair, add 360° to the angle to get another equivalent angle: \[ 135^{\circ} + 360^{\circ} = 495^{\circ} \] or subtract 360° to stay within the primary cycle: \[ 135^{\circ} - 360^{\circ} = -225^{\circ} = 135^{\circ} \] or simply invert with the point negative: \[ (-2, 315^{\circ}) \]
06
- Provide Second Pair of Polar Coordinates
Thus, another pair of polar coordinates can be \( (-2, 315^{\circ}) \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cartesian coordinates
In the Cartesian coordinate system, points in a plane are identified using an ordered pair of numbers called coordinates. These coordinates are written as \((x, y)\), where:
- \textbf{x}: the horizontal distance from the origin.
- \textbf{y}: the vertical distance from the origin.
- x is negative (to the left of the origin).
- y is positive (above the origin).
polar coordinates
Polar coordinates offer a different way to describe a point in a plane using two values: the radius \( r \) and the angle \( \theta \). The polar coordinates for a point are written as \( (r, \theta) \), where:
1. Compute \( r \) using the formula: \[ r = \sqrt{x^2 + y^2} \] Substituting the values, \[r = \sqrt{ (-\sqrt{2})^2 + (\sqrt{2})^2 } = 2 \]
2. Compute \(\theta\) by finding the angle whose tangent is the ratio of y to x:
\[tan(\theta) = \frac{y}{x} = \frac{\sqrt{2}}{-\sqrt{2}} = -1 \] Since the point is in the second quadrant, \( \theta = 135^{\text{\degree}} \). So, one set of polar coordinates is \( (2, 135^{\text{\degree}}) \).
Another equivalent angle option:
3. To find another angle, we can add 360° or subtract 360° to keep within one cycle: \ [{0^{\text{\degree}} \leq \theta< 360^{\text{\degree}}}] For example:
Adding: \( 135^{\text{\degree}} + 360^{\text{\degree}} = 495^{\text{\degree}} \)
Subtracting: \( 135^{\text{\degree}} - 360^{\text{\degree}} = -225^{\text{\degree}} = 135^{\text{\degree}} \)
Using a negative radius with adjusted angle: \( (-2, 315^{\text{\degree}}) \)
Therefore, another set of polar coordinates is \( (-2, 315^{\text{\degree}}) \).
- \textbf{r}: the distance from the origin to the point.
- \textbf{\theta}: the angle measured counterclockwise from the positive x-axis to the line segment from the origin to the point.
1. Compute \( r \) using the formula: \[ r = \sqrt{x^2 + y^2} \] Substituting the values, \[r = \sqrt{ (-\sqrt{2})^2 + (\sqrt{2})^2 } = 2 \]
2. Compute \(\theta\) by finding the angle whose tangent is the ratio of y to x:
\[tan(\theta) = \frac{y}{x} = \frac{\sqrt{2}}{-\sqrt{2}} = -1 \] Since the point is in the second quadrant, \( \theta = 135^{\text{\degree}} \). So, one set of polar coordinates is \( (2, 135^{\text{\degree}}) \).
Another equivalent angle option:
3. To find another angle, we can add 360° or subtract 360° to keep within one cycle: \ [{0^{\text{\degree}} \leq \theta< 360^{\text{\degree}}}] For example:
Adding: \( 135^{\text{\degree}} + 360^{\text{\degree}} = 495^{\text{\degree}} \)
Subtracting: \( 135^{\text{\degree}} - 360^{\text{\degree}} = -225^{\text{\degree}} = 135^{\text{\degree}} \)
Using a negative radius with adjusted angle: \( (-2, 315^{\text{\degree}}) \)
Therefore, another set of polar coordinates is \( (-2, 315^{\text{\degree}}) \).
coordinate transformation
Converting a point from Cartesian to polar coordinates involves translating the rectangular coordinates into a form that uses distance and angle. This transformation is crucial for understanding relationships between points in different coordinate systems.
Here’s a quick guide:
Here’s a quick guide:
- Distance (radial distance or r): Calculated using the Pythagorean theorem. From \((x, y)\) to \(r\), use:
\[ r = \sqrt{x^2 + y^2} \]
- Angle (θ): Found using trigonometric relationships, specifically the tangent function:
\[ \theta = \tan^{-1} \( \frac{y}{x} \) \] To place the angle correctly in the appropriate quadrant, consider the signs of x and y. Knowing the quadrant helps determine the correct direction and angle from the x-axis.