/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Answer each question. Suppose ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Answer each question. Suppose you are solving a trigonometric equation for solutions over the interval \(\left[0^{\circ}, 360^{\circ}\right),\) and your work leads to \(\frac{1}{3} \theta=45^{\circ}, 60^{\circ}, 75^{\circ}, 90^{\circ} .\) What are the corresponding values of \(\theta ?\)

Short Answer

Expert verified
135°,180°,225°,270°

Step by step solution

01

- Understand the given equation

The equation provided is \(\frac{1}{3}\theta = 45^{\circ}, 60^{\circ}, 75^{\circ}, 90^{\circ}\). We need to solve for \(\theta\) in each case.
02

- Solve for \(\theta\) when \(\frac{1}{3}\theta = 45^{\circ}\)

Multiply both sides of the equation by 3 to isolate \(\theta\): \(\theta = 3 \times 45^{\circ} = 135^{\circ}\)
03

- Solve for \(\theta\) when \(\frac{1}{3}\theta = 60^{\circ}\)

Multiply both sides of the equation by 3 to isolate \(\theta\): \(\theta = 3 \times 60^{\circ} = 180^{\circ}\)
04

- Solve for \(\theta\) when \(\frac{1}{3}\theta = 75^{\circ}\)

Multiply both sides of the equation by 3 to isolate \(\theta\): \(\theta = 3 \times 75^{\circ} = 225^{\circ}\)
05

- Solve for \(\theta\) when \(\frac{1}{3}\theta = 90^{\circ}\)

Multiply both sides of the equation by 3 to isolate \(\theta\): \(\theta = 3 \times 90^{\circ} = 270^{\circ}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
When solving trigonometric equations, the objective is to find the values of the variable that make the equation true. In our example, we are given \(\frac{1}{3}\theta = 45^{\bullet}, 60^{\bullet}, 75^{\bullet}, 90^{\bullet}\). Here are the steps:

  • First, we need to isolate \(\theta\) by multiplying both sides of the equation by 3.
  • Body: The overall goal is to simplify each expression to find the specific values of \(\theta\).
This process can be broken into simple steps:
\(\frac{1}{3}\theta = 45^{\bullet}\) becomes \(\theta = 3 \times 45^{\bullet} = 135^{\bullet}\)
\(\frac{1}{3}\theta = 60^{\bullet}\) becomes \(\theta = 3 \times 60^{\bullet} = 180^{\bullet}\)
\(\frac{1}{3}\theta = 75^{\bullet}\) becomes \(\theta = 3 \times 75^{\bullet} = 225^{\bullet}\)
\(\frac{1}{3}\theta = 90^{\bullet}\) becomes \(\theta = 3 \times 90^{\bullet} = 270^{\bullet}\)

By following these straightforward steps, you can easily solve similar trigonometric equations with multiplication.
Theta Values
Theta (\(\theta\)) represents an angle, often measured in degrees or radians. In the context of trigonometric equations, you will find \(\theta\) as part of the equations needing solutions. In the given exercise, we are focusing on degrees.

Each \(\theta\) value must be computed within the specified interval \([0^{\bullet}, 360^{\bullet})\). In our case, \(\frac{1}{3}\theta = 45^{\bullet}, 60^{\bullet}, 75^{\bullet}, 90^{\bullet}\), \(\theta\) is isolated by multiplying by 3. The solutions \(\theta = 135^{\bullet}, 180^{\bullet}, 225^{\bullet}, 270^{\bullet}\) fall within the given interval and are correct.

Key points to remember:
  • Make sure your solutions fall within the given interval.
  • Always double-check your final \(\theta\) values to ensure accuracy.
Understanding intervals and degree measures are crucial for mastering trigonometric equations.
Multiplication in Trigonometry
Multiplication can simplify trigonometric equations by isolating the variable. Here’s why it works:

Given the equation \(\frac{1}{3}\theta = 45^{\bullet}\), we multiply both sides by 3, which reverses the division by 3:

\[ 3 \times \frac{1}{3}\theta = 3 \times 45^{\bullet} \]
Simplifying, we get \(\theta = 135^{\bullet}\)

The same approach applies to the other parts of the exercise:

\(\frac{1}{3}\theta = 60^{\bullet}\) results in \(\theta = 180^{\bullet}\)
\(\frac{1}{3}\theta = 75^{\bullet}\) results in \(\theta = 225^{\bullet}\)
\(\frac{1}{3}\theta = 90^{\bullet}\) results in \(\theta = 270^{\bullet}\)

Multiplying both sides by the same number (in this case 3) simplifies the equations and helps in isolating \(\theta\). Understanding this concept is essential for solving more complex trigonometric equations effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph each expression and use the graph to make a conjecture, predicting what might be an identity. Then verify your conjecture algebraically. $$\frac{\tan \frac{x}{2}+\cot \frac{x}{2}}{\cot \frac{x}{2}-\tan \frac{x}{2}}$$

Solve each equation ( \(x\) in radians and \(\theta\) in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures. $$2 \sqrt{3} \sin \frac{x}{2}=3$$

Verify that each equation is an identity. $$\cot 4 \theta=\frac{1-\tan ^{2} 2 \theta}{2 \tan 2 \theta}$$

Amperage, Wattage, and Voltage Amperage is a measure of the amount of electricity that is moving through a circuit, whereas voltage is a measure of the force pushing the electricity. The wattage \(W\) consumed by an electrical device can be determined by calculating the product of the amperage \(I\) and voltage \(V .\) (Source: Wilcox, G. and C. Hesselberth, Electricity for Engineering Technology, Allyn \& Bacon.)(a) A household circuit has voltage $$ V=163 \sin 120 \pi t $$ when an incandescent light bulb is turned on with amperage $$ I=1.23 \sin 120 \pi t $$ Graph the wattage \(W=V I\) consumed by the light bulb in the window \([0,0.05]\) by $$ [-50,300] $$ (b) Determine the maximum and minimum wattages used by the light bulb. (c) Use identities to determine values for \(a, c,\) and \(\omega\) so that \(W=a \cos (\omega t)+c\) (d) Check your answer by graphing both expressions for \(W\) on the same coordinate axes. (e) Use the graph to estimate the average wattage used by the light. For how many watts (to the nearest integer) do you think this incandescent light bulb is rated?

Verify that each trigonometric equation is an identity. $$\sec x-\cos x+\csc x-\sin x-\sin x \tan x=\cos x \cot x$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.