/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Verify that each trigonometric e... [FREE SOLUTION] | 91Ó°ÊÓ

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Verify that each trigonometric equation is an identity. $$\sin ^{4} \theta-\cos ^{4} \theta=2 \sin ^{2} \theta-1$$

Short Answer

Expert verified
Both sides simplify to \- \cos (2 \theta ) \.

Step by step solution

01

- Simplify the Left Side Using Trigonometric Identities

Start by recognizing that the left side \(\sin ^{4} \theta-\cos ^{4} \theta\) can be factored using the difference of squares. This gives: \(\sin ^{4} \theta-\cos ^{4} \theta = (\sin^2 \theta - \cos^2 \theta)(\sin^2 \theta + \cos^2 \theta) \)
02

- Simplify Using Pythagorean Identity

Recall the Pythagorean identity \( \sin^2 \theta + \cos^2 \theta = 1 \). Replace the \(\sin^2 \theta + \cos^2 \theta\) in the equation: \( \left( \sin^2 \theta - \cos^2 \theta \right) ( 1 ) \) Since multiplying by 1 does not change the expression, it simplifies to: \( \sin^2 \theta - \cos^2 \theta \)
03

- Use the Double-Angle Identity

Rewrite \(\sin^2 \theta - \cos^2 \theta\) using the double-angle identity for cosine, \( \cos ( 2 \theta ) = \cos^2 \theta - \sin^2 \theta\). Thus, \(\sin^2 \theta - \cos^2 \theta = -( \cos (2 \theta ) )\).This means: \( \sin ^{4} \theta-\cos ^{4} \theta = -\cos (2 \theta ) \)
04

- Verify with Original Right Side

Finally, simplify the original right side \( 2 \sin^2 \theta - 1 \). Using the double angle identity for sine, \( \sin^2 \theta = \frac{1 - \cos (2 \theta)}{2} \), we have: \( 2 \sin^2 \theta - 1 = 2 \left ( \frac{1 - \cos (2 \theta)}{2} \right ) - 1 \) This simplifies to: \( 2 \left ( \frac{1 - \cos (2 \theta)}{2} \right ) - 1 = (1 - \cos (2 \theta)) - 1 = - \cos (2 \theta) \)
05

Conclusion - Verify Both Sides Are Equal

Both the left and right sides simplify to \- \cos (2 \theta )\. Thus, the given trigonometric equation \( \sin^{4} \theta - \cos^{4} \theta = 2 \sin^{2} \theta - 1 \) is verified to be an identity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

difference of squares
The difference of squares is a powerful algebraic tool. It states that \(a^2 - b^2 = (a - b)(a + b)\). This identity is useful for factoring complex expressions. In this problem, we started with \(\sin^4 \theta - \cos^4 \theta\). By recognizing that \(\sin^4 \theta\) and \(\cos^4 \theta\) are both squares, we rewrote the expression as \(\sin^2 \theta \cdot \sin^2 \theta - \cos^2 \theta \cdot \cos^2 \theta\). Applying the difference of squares identity transformed it to \(\sin^2 \theta - \cos^2 \theta\) times \(\sin^2 \theta + \cos^2 \theta\). This factorization simplifies solving many trigonometric equations.
Pythagorean identity
The Pythagorean identity is fundamental in trigonometry. It states that \(\sin^2 \theta + \cos^2 \theta = 1\). This identity helps bridge different trigonometric functions. In this exercise, we leveraged the Pythagorean identity to simplify \(\sin^2 \theta + \cos^2 \theta\) in our expression. By substituting \(1\) for \(\sin^2 \theta + \cos^2 \theta\), we turned the complex product \(\sin^2 \theta - \cos^2 \theta \cdot (\sin^2 \theta + \cos^2 \theta)\) into just \(\sin^2 \theta - \cos^2 \theta\). This simplification is crucial in many trigonometric proofs and problems.
double-angle identity
The double-angle identities allow you to express trigonometric functions of double angles (like \(2\theta\)) in terms of single angles. For cosine, the double-angle identity is \(\cos(2\theta) = \cos^2 \theta - \sin^2 \theta\). By rearranging it, we get \(\sin^2 \theta - \cos^2 \theta = -\cos(2\theta)\). In our problem, this conversion was crucial to match both sides of the equation. Substituting \(-\cos(2\theta)\) for \(\sin^2 \theta - \cos^2 \theta\) simplified the left side to resemble the right side. Mastering double-angle identities is important for advanced trigonometry.
proof by simplification
Proof by simplification involves breaking down a complex expression to verify its equality. Here, we started with \(\sin^4 \theta - \cos^4 \theta\) and transformed it step by step using different identities. By employing the difference of squares, Pythagorean identity, and double-angle identity, we systematically simplified both sides. Eventually, we showed that the left side equaled the right side, confirming the original equation. This methodical simplification proves that \(\sin^4 \theta - \cos^4 \theta = 2 \sin^2 \theta - 1\) holds true. Using multiple methods to simplify both sides of an equation is key in trigonometric proofs.

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Most popular questions from this chapter

Verify that each equation is an identity. $$\frac{\sin (x+y)}{\cos (x-y)}=\frac{\cot x+\cot y}{1+\cot x \cot y}$$

Verify that each equation is an identity. $$\cos x=\frac{1-\tan ^{2} \frac{x}{2}}{1+\tan ^{2} \frac{x}{2}}$$

Use the given information to find ( \(a\) ) \(\sin (s+t),(b) \tan (s+t),\) and \((c)\) the quadrant of \(s+t .\) $$\cos s=-\frac{1}{5} \text { and } \sin t=\frac{3}{5}, s \text { and } t \text { in quadrant II }$$

Solve each equation ( \(x\) in radians and \(\theta\) in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures. $$\sin \frac{\theta}{2}=1$$

(This discussion applies to functions of both angles and real numbers.) Consider the following. $$\begin{aligned}\cos (&\left.180^{\circ}-\theta\right) \\\&=\cos 180^{\circ} \cos \theta+\sin 180^{\circ} \sin \theta \\\&=(-1) \cos \theta+(0) \sin \theta \\\&=-\cos \theta\end{aligned}$$ \(\cos \left(180^{\circ}-\theta\right)=-\cos \theta\) is an example of a reduction formula, which is an identity that reduces a function of a quadrantal angle plus or minus \(\theta\) to a function of \(\theta\) alone. Another example of a reduction formula is \(\cos \left(270^{\circ}+\theta\right)=\sin \theta\) Here is an interesting method for quickly determining a reduction formula for a trigonometric function \(f\) of the form \(f(Q \pm \theta),\) where \(Q\) is a quadrantal angle. There are two cases to consider, and in each case, think of \(\boldsymbol{\theta}\) as a small positive angle in order to determine the quadrant in which \(Q \pm \theta\) will lie. Case 1 Suppose that \(Q\) is a quadrantal angle whose terminal side lies along the \(x\) -axis. Determine the quadrant in which \(Q \pm \theta\) will lie for a small positive angle \(\theta .\) If the given function \(f\) is positive in that quadrant, use a \(+\) sign on the reduced form. If \(f\) is negative in that quadrant, use a - sign. The reduced form will have that \(\operatorname{sign}, f\) as the function, and \(\theta\) as the argument. For example: CAN'T COPY THE GRAPH Case 2 Suppose that \(Q\) is a quadrantal angle whose terminal side lies along the \(y\) -axis. Determine the quadrant in which \(Q \pm \theta\) will lie for a small positive angle \(\theta .\) If the given function \(f\) is positive in that quadrant, use a \(+\) sign on the reduced form. If \(f\) is negative in that quadrant, use a - sign. The reduced form will have that sign, the cofunction of \(f\) as the function, and \(\theta\) as the argument. For example: CAN'T COPY THE GRAPH Use these ideas to write reduction formulas for each of the following. $$\tan \left(270^{\circ}-\theta\right)$$

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