/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Find the remaining five trigonom... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the remaining five trigonometric functions of \(\theta .\) $$\cos \theta=-\frac{1}{4}, \sin \theta>0$$

Short Answer

Expert verified
\( \sin \theta = \frac{\sqrt{15}}{4} \), \( \tan \theta = -\sqrt{15} \), \( \csc \theta = \frac{4\sqrt{15}}{15} \), \( \sec \theta = -4 \), \( \cot \theta = -\frac{\sqrt{15}}{15} \).

Step by step solution

01

- Determine the Quadrant

Given that \(\theta\) is such that \(\cos \theta = -\frac{1}{4}\) and \(\sin \theta > 0\), the angle \(\theta\) is in the second quadrant because cosine is negative and sine is positive only in this quadrant.
02

- Use the Pythagorean Identity

According to the Pythagorean identity, \(\sin^2 \theta + \cos^2 \theta = 1\). Substitute \(\cos \theta = -\frac{1}{4}\):\[\begin{align*}\sin^2 \theta + \(\frac{-1}{4}\)^2 &= 1 \sin^2 \theta + \frac{1}{16} &= 1 \sin^2 \theta &= 1 - \frac{1}{16} \sin^2 \theta &= \frac{16}{16} - \frac{1}{16} \sin^2 \theta &= \frac{15}{16}\]Then find \(\sin \theta\) by taking the positive square root (since \(\sin \theta > 0\)):\[\sin \theta = \sqrt{\frac{15}{16}} = \frac{\sqrt{15}}{4}\]
03

- Find the Tangent Function

The tangent function is defined as \(\tan \theta = \frac{\sin \theta}{\cos \theta}\). Substitute the values found:\[\tan \theta = \frac{\frac{\sqrt{15}}{4}}{\frac{-1}{4}} = -\sqrt{15}\]
04

- Find the Cosecant Function

The cosecant function is the reciprocal of the sine function: \(\csc \theta = \frac{1}{\sin \theta}\). Substitute the value found:\[\csc \theta = \frac{1}{\frac{\sqrt{15}}{4}} = \frac{4}{\sqrt{15}} = \frac{4\sqrt{15}}{15}\]
05

- Find the Secant Function

The secant function is the reciprocal of the cosine function: \(\sec \theta = \frac{1}{\cos \theta}\). Substitute the value given:\[\sec \theta = \frac{1}{-\frac{1}{4}} = -4\]
06

- Find the Cotangent Function

The cotangent function is the reciprocal of the tangent function: \(\cot \theta = \frac{1}{\tan \theta}\). Substitute the value found:\[\cot \theta = \frac{1}{-\sqrt{15}} = -\frac{1}{\sqrt{15}} = -\frac{\sqrt{15}}{15}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine
Cosine is one of the primary trigonometric functions. It is abbreviated as \(\text{cos}\). In a right triangle, cosine of an angle is the ratio of the length of the adjacent side to the hypotenuse. The cosine function is defined as:
\[ \text{cos} \theta = \frac{\text{adjacent}}{\text{hypotenuse}} \]
Cosine values range between -1 and 1. Understanding the cosine function is essential for solving many trigonometric problems, especially those involving angles in different quadrants.
Sine
Sine is another fundamental trigonometric function, abbreviated as \(\text{sin}\). In a right triangle, sine of an angle is the ratio of the length of the opposite side to the hypotenuse. The sine function is expressed as:
\[ \text{sin} \theta = \frac{\text{opposite}}{\text{hypotenuse}} \]
Sine values also range from -1 to 1. It's particularly useful when working with the Pythagorean identity and determining values of other trigonometric functions.
Quadrants
The coordinate plane is divided into four quadrants. Each quadrant has specific characteristics for the signs of trigonometric functions:
  • Quadrant I: Both sine and cosine are positive.
  • Quadrant II: Sine is positive and cosine is negative.
  • Quadrant III: Both sine and cosine are negative.
  • Quadrant IV: Sine is negative and cosine is positive.

This knowledge helps in identifying the correct trigonometric functions values based on the given conditions.
Pythagorean Identity
The Pythagorean identity is a fundamental relation in trigonometry which shows the connection between sine and cosine. It is given by:
\[ \text{sin}^2 \theta + \text{cos}^2 \theta = 1 \]
This identity is derived from the Pythagorean Theorem applied to a unit circle. It is crucial because it allows you to find \(\text{sin} \theta\) given \(\text{cos} \theta\) and vice versa.
Tangent
Tangent is a trigonometric function defined as the ratio of sine to cosine. It is abbreviated as \(\text{tan}\). The tangent function is expressed as:
\[ \text{tan} \theta = \frac{\text{sin} \theta}{\text{cos} \theta} \]
Tangent values can range from negative to positive infinity. Knowing tangent is useful for calculating angles and solving trigonometric equations.
Cosecant
Cosecant, abbreviated as \(\text{csc}\), is the reciprocal of the sine function. It is expressed as:
\[ \text{csc} \theta = \frac{1}{\text{sin} \theta} \]
Since sine values range between -1 and 1 (excluding 0), cosecant will vary from negative to positive infinity. Understanding cosecant helps in many trigonometric calculations.
Secant
Secant, abbreviated as \(\text{sec}\), is the reciprocal of the cosine function. It is given by:
\[ \text{sec} \theta = \frac{1}{\text{cos} \theta} \]
Secant values range from -infinity to -1 and 1 to infinity. It provides a convenient way to find values when cosine is known.
Cotangent
Cotangent is the reciprocal of the tangent function, abbreviated as \(\text{cot}\). It can be defined as:
\[ \text{cot} \theta = \frac{1}{\text{tan} \theta} \]
Cotangent is also expressed as the ratio of cosine to sine:
\[ \text{cot} \theta = \frac{\text{cos} \theta}{\text{sin} \theta} \] Cotangent helps to complement the set of trigonometric functions for solving various types of trigonometric problems.

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Most popular questions from this chapter

Amperage, Wattage, and Voltage Amperage is a measure of the amount of electricity that is moving through a circuit, whereas voltage is a measure of the force pushing the electricity. The wattage \(W\) consumed by an electrical device can be determined by calculating the product of the amperage \(I\) and voltage \(V .\) (Source: Wilcox, G. and C. Hesselberth, Electricity for Engineering Technology, Allyn \& Bacon.)(a) A household circuit has voltage $$ V=163 \sin 120 \pi t $$ when an incandescent light bulb is turned on with amperage $$ I=1.23 \sin 120 \pi t $$ Graph the wattage \(W=V I\) consumed by the light bulb in the window \([0,0.05]\) by $$ [-50,300] $$ (b) Determine the maximum and minimum wattages used by the light bulb. (c) Use identities to determine values for \(a, c,\) and \(\omega\) so that \(W=a \cos (\omega t)+c\) (d) Check your answer by graphing both expressions for \(W\) on the same coordinate axes. (e) Use the graph to estimate the average wattage used by the light. For how many watts (to the nearest integer) do you think this incandescent light bulb is rated?

Verify that each trigonometric equation is an identity. $$\frac{1-\cos x}{1+\cos x}=\csc ^{2} x-2 \csc x \cot x+\cot ^{2} x$$

Verify that each trigonometric equation is an identity. $$\sin ^{2} x(1+\cot x)+\cos ^{2} x(1-\tan x)+\cot ^{2} x=\csc ^{2} x$$

Solve each problem. Musicians sometimes tune instruments by playing the same tone on two different instruments and listening for a phenomenon known as beats. Beats occur when two tones vary in frequency by only a few hertz. When the two instruments are in tune, the beats disappear. The ear hears beats because the pressure slowly rises and falls as a result of this slight variation in the frequency. This phenomenon can be seen using a graphing calculator. (Source: Pierce, \(\mathrm{J}\)., The Science of Musical Sound, Scientific American Books.) (a) Consider the two tones with frequencies of \(220 \mathrm{Hz}\) and \(223 \mathrm{Hz}\) and pressures \(P_{1}=0.005 \sin 440 \pi t\) and \(P_{2}=0.005\) sin \(446 \pi t,\) respectively. Graph the pressure \(P=P_{1}+P_{2}\) felt by an eardrum over the 1 -sec interval \([0.15,1.15] .\) How many beats are there in 1 sec? (b) Repeat part (a) with frequencies of 220 and \(216 \mathrm{Hz}\) (c) Determine a simple way to find the number of beats per second if the frequency of each tone is given.

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