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Use an identity to write each expression as a single trigonometric function value or as a single number. $$\frac{\tan 34^{\circ}}{2\left(1-\tan ^{2} 34^{\circ}\right)}$$

Short Answer

Expert verified
The expression simplifies to \( \frac{1}{2} \tan 68^{\circ} \).

Step by step solution

01

Recall the trigonometric identity

Use the trigonometric identity for tangent double-angle: \[ \tan(2\theta) = \frac{2 \tan(\theta)}{1 - \tan^2(\theta)} \]In this problem, let \(\theta = 34^{\circ}\).
02

Substitute \(\theta = 34^{\circ}\) into the identity

Substitute \(\theta = 34^{\circ}\) into the double-angle identity: \[ \tan(2 \times 34^{\circ}) = \frac{2 \tan(34^{\circ})}{1 - \tan^2(34^{\circ})} \]This simplifies to: \[ \tan(68^{\circ}) = \frac{2 \tan(34^{\circ})}{1 - \tan^2(34^{\circ})} \]
03

Identify the given expression

The given expression is \(\frac{\tan 34^{\circ}}{2(1 - \tan^2 34^{\circ})}\). Factor the 2 out of the denominator: \[\frac{2 \tan 34^{\circ}}{2(1 - \tan^2 34^{\circ})} \times \frac{1}{2}\]
04

Substitute and simplify

Since from Step 2, we know that \(\tan 68^{\circ} = \frac{2 \tan 34^{\circ}}{1 - \tan^2 34^{\circ}}\), the given expression simplifies to: \[ \frac{\tan 68^{\circ}}{2} \]
05

Conclusion

Hence, the expression \(\frac{\tan 34^{\circ}}{2(1 - \tan^2 34^{\circ})}\) simplifies to: \[ \frac{1}{2} \tan 68^{\circ} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Double-Angle Identity
Understanding the tangent double-angle identity is crucial for simplifying certain trigonometric expressions.
The identity tells us that the tangent of twice an angle can be expressed in terms of the tangent of the original angle:
\[ \tan(2\theta) = \frac{2 \tan(\theta)}{1 - \tan^2(\theta)} \]

For instance, in this exercise, when we let \( \theta = 34^{\text{\textdegree}} \), plugging it into the formula gives us:
\[ \tan(68^{\text{\textdegree}}) = \frac{2 \tan(34^{\text{\textdegree}})}{1 - \tan^2(34^{\text{\textdegree}})} \]
Identities like this one are incredibly useful because they allow us to rewrite complex trigonometric expressions in simpler forms.
This is essential not only in solving equations but also in other mathematical applications such as integration and differentiation.
Trigonometric Simplification
Trigonometric simplification is all about making expressions more manageable and often involves using identities.
In our example, we started with the expression:
\[ \frac{\tan 34^{\text{\textdegree}}}{2(1 - \tan^2 34^{\text{\textdegree}})} \]
By relating it to the tangent double-angle identity, we replaced it with:
\[ \frac{2 \tan 34^{\text{\textdegree}}}{2(1 - \tan^2 34^{\text{\textdegree}})} \times \frac{1}{2} \]
This step was key because it set up the simplification where we know:
\[ \tan 68^{\text{\textdegree}} = \frac{2 \tan 34^{\text{\textdegree}}}{1 - \tan^2(34^{\text{\textdegree}})} \]
Thus, the expression simplifies to:
\[ \frac{\tan 68^{\text{\textdegree}}}{2} \]
and ultimately:
\[ \frac{1}{2} \tan 68^{\text{\text{\textdegree}}} \]
Simplifying trigonometric expressions can save you a lot of time and effort, especially in calculus and advanced math subjects.
Precalculus Problem Solving
Precalculus problem solving often involves understanding and applying various identities and algebraic techniques.
This problem showcases several important skills:
  • Identifying which trigonometric identity to use
  • Substituting values effectively
  • Manipulating expressions algebraically
In our example, by recognizing the tangent double-angle identity, we could transform a seemingly complicated expression into a simpler one.
This step-by-step strategy is commonly employed in precalculus to handle tasks involving trigonometric functions.
By practicing more of these problems, you'll get better at selecting the right identities and techniques to make problem-solving efficient and straightforward.
Remember, each problem you solve contributes to building a strong foundation for calculus and other advanced math courses.

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Most popular questions from this chapter

Graph each expression and use the graph to make a conjecture, predicting what might be an identity. Then verify your conjecture algebraically. $$\frac{4 \tan x \cos ^{2} x-2 \tan x}{1-\tan ^{2} x}$$

Verify that each equation is an identity. $$\sin 2 x=\frac{2 \tan x}{1+\tan ^{2} x}$$

Verify that each equation is an identity. $$\cot 4 \theta=\frac{1-\tan ^{2} 2 \theta}{2 \tan 2 \theta}$$

(This discussion applies to functions of both angles and real numbers.) Consider the following. $$\begin{aligned}\cos (&\left.180^{\circ}-\theta\right) \\\&=\cos 180^{\circ} \cos \theta+\sin 180^{\circ} \sin \theta \\\&=(-1) \cos \theta+(0) \sin \theta \\\&=-\cos \theta\end{aligned}$$ \(\cos \left(180^{\circ}-\theta\right)=-\cos \theta\) is an example of a reduction formula, which is an identity that reduces a function of a quadrantal angle plus or minus \(\theta\) to a function of \(\theta\) alone. Another example of a reduction formula is \(\cos \left(270^{\circ}+\theta\right)=\sin \theta\) Here is an interesting method for quickly determining a reduction formula for a trigonometric function \(f\) of the form \(f(Q \pm \theta),\) where \(Q\) is a quadrantal angle. There are two cases to consider, and in each case, think of \(\boldsymbol{\theta}\) as a small positive angle in order to determine the quadrant in which \(Q \pm \theta\) will lie. Case 1 Suppose that \(Q\) is a quadrantal angle whose terminal side lies along the \(x\) -axis. Determine the quadrant in which \(Q \pm \theta\) will lie for a small positive angle \(\theta .\) If the given function \(f\) is positive in that quadrant, use a \(+\) sign on the reduced form. If \(f\) is negative in that quadrant, use a - sign. The reduced form will have that \(\operatorname{sign}, f\) as the function, and \(\theta\) as the argument. For example: CAN'T COPY THE GRAPH Case 2 Suppose that \(Q\) is a quadrantal angle whose terminal side lies along the \(y\) -axis. Determine the quadrant in which \(Q \pm \theta\) will lie for a small positive angle \(\theta .\) If the given function \(f\) is positive in that quadrant, use a \(+\) sign on the reduced form. If \(f\) is negative in that quadrant, use a - sign. The reduced form will have that sign, the cofunction of \(f\) as the function, and \(\theta\) as the argument. For example: CAN'T COPY THE GRAPH Use these ideas to write reduction formulas for each of the following. $$\tan \left(270^{\circ}-\theta\right)$$

Verify that each equation is an identity. $$\frac{\sin (x+y)}{\cos (x-y)}=\frac{\cot x+\cot y}{1+\cot x \cot y}$$

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