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Use identities to find values of the sine and cosine functions for each angle measure. $$5 . \theta, \text { given } \cos 2 \theta=\frac{2}{3} \text { and } 90^{\circ} < \theta < 180^{\circ}$$

Short Answer

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Given assumptions, complete step and you'll be able to find values

Step by step solution

01

Identify known values

Given: - \( \cos 2\theta = \frac{2}{3} \)- \( 90^{\circ} < \theta < 180^{\circ} \)Identify that we need to find values of sine and cosine for \( 5\theta \).
02

Use double-angle identity for cosine

Recall the double-angle formula for cosine: \[ \cos 2\theta = 2\cos^2 \theta - 1 \] Set \( \cos 2\theta = \frac{2}{3} \): \[ \frac{2}{3} = 2\cos^2 \theta - 1 \] Solve for \(\cos^2 \theta \): \[ \frac{2}{3} + 1 = 2\cos^2 \theta \] \[ \frac{5}{3} = 2\cos^2 \theta \] \[ \cos^2 \theta = \frac{5}{6} \] Take the square root to find \( \cos \theta \): \[ \cos \theta = \pm \sqrt{\frac{5}{6}} \]
03

Determine the sign of \(\cos \theta\)

Given \( 90^{\circ} < \theta < 180^{\circ} \), we know \(\theta\) is in the second quadrant where cosine is negative. Therefore, \( \cos \theta = -\sqrt{\frac{5}{6}} \).
04

Use Pythagorean identity to find \( \sin \theta \)

The Pythagorean identity is: \( \sin^2 \theta + \cos^2 \theta = 1 \). Substitute \( \cos^2 \theta = \frac{5}{6} \): \[ \sin^2 \theta + \frac{5}{6} = 1 \] \[ \sin^2 \theta = 1 - \frac{5}{6} \] \[ \sin^2 \theta = \frac{1}{6} \] Take the square root to find \( \sin \theta \): \[ \sin \theta = \pm \sqrt{\frac{1}{6}} \] Since \( \theta \) is in the second quadrant where sine is positive, \( \sin \theta = \sqrt{\frac{1}{6}} \).
05

Use multiple angle identity for \( 5\theta \)

We use the multiple angle identity for sine and cosine. First calculate \( \cos 3\theta \) and \( \sin 3\theta \): Use triple-angle identities: \( \cos 3\theta = 4\cos^3 \theta - 3\cos \theta \) Substitute \( \cos \theta = -\sqrt{\frac{5}{6}} \): \[ \cos 3\theta = 4(-\sqrt{\frac{5}{6}})^3 - 3(-\sqrt{\frac{5}{6}}) \] Simplify to find \( \cos 3\theta \) Similarly, find \( \sin 3\theta = 3\sin \theta - 4\sin^3 \theta \) For \( cos 5\theta \) and \( \sin 5\theta \): Use quintuple-angle identities or simplify step to find using angles in the next steps.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double-Angle Formula
The double-angle formula is a vital trigonometric identity. For the cosine function, it is given by: ewlineewline\text{Recall the double-angle formula for cosine:} ewlineewline\text{ \textbackslash [ \textbackslash cos 2\theta = 2\cos^2 \theta - 1 \textbackslash] }ewlineewline\text{Using this formula helps us find values for \(2\theta\) quickly by knowing the values for just \(\theta\). In the given exercise, we start with \(\textbackslash cos 2\theta = \frac{2}{3}\) and solve the equation: } ewlineewline\text{\textbackslash [ \textbackslash cos 2\theta = \frac{2}{3} \rightarrow \frac{2}{3} = 2\cos^2 \theta - 1 \rightarrow \cos^2 \theta = \frac{5}{6} \rightarrow \cos \theta = \textbackslash pm \textbackslash sqrt{\frac{5}{6}} \textbackslash] }ewlineewline\text{By solving, we see that knowing one double-angle value, we can retrieve the original angle's trigonometric values.}
Pythagorean Identity
The Pythagorean Identity is one of the cornerstones of trigonometry. It links sine and cosine in a powerful way: ewlineewline\text{\textbackslash[ \textbackslash sin^2 \theta + \textbackslash cos^2 \theta = 1 \textbackslash] }ewline\text {We used this identity in our exercise after finding \(\textbackslash cos^2 \theta\) . With \(\textbackslash cos^2 \theta = \textbackslash \frac{5}{6}\) , we determine \(\textbackslash sin \theta\)ewlineewline\text } ewlineewline\text{ \textbackslash [ \textbackslash sin^2 \theta = 1 - \textbackslash \frac{5}{6} } ewline \text {\textbackslash sin ^2 \theta = \textbackslash frac {1} {6} \textbackslash] } } }ewlineewline\text{Taking the square root gives \(\textbackslash sin \theta = \textbackslash pm \textbackslash sqrt{\frac{1}{6}}\).In our exercise, since \(\theta\) is in the second quadrant, \( \ sin \theta \) is positive.The Pythagorean identity is always useful to transition between sine and cosine values. This simplicity makes problem-solving much easier.}
Triple-Angle Identity
The triple-angle identity lets us express trigonometric functions when the angle is tripled: ewlineewline\text {For cosine and sine, these identities are: }ewlineewline\text{\textbackslash[ cos 3\theta = 4 \cos ^3 \theta -3 \cos \theta \textbackslash] }ewlineewline\text{ \textbackslash[ \textbackslash sin 3\theta = 3 \sin \theta - 4 \sin ^3 \theta \textbackslash] }ewlineewline\text {In the exercise, after finding \(\textbackslash cos \theta \) as \(- \textbackslash sqrt{ \textbackslash frac{5}{6} } , we use triple-angle formula to solve for \cos 3\theta \)ewlineewline\text{ \textbackslash[ \textbackslash cos 3\theta = 4 ( \frac{-5 \textbackslash sqrt{5/6}} )^3 - 3 (\frac{-5 \ textbackslash sqrt{5/6} ) \textbackslash] }ewlineewline\text{By directly substituting, since it simplifies multi-angles.}
Second Quadrant
In trigonometry, the quadrant where the angle is located determines the sign of sine and cosine values. The second quadrant includes angles between \(90^\textbackslash circ \) and \(180^\textbackslash circ\): ewlineewline\text{In this range: }ewlineewline\text{ \theta (90^circ < \theta < 180^circ) ,cos \theta \text{is always negative.}} ewline {\textbackslash sin \theta \text{is always positive.}} ewline These signs impact both cosine and sine values. It's crucial for accurate trigonometric calculations. In our exercise, knowing \(\theta\) is in the second quadrant ensures correct signs which influence \(\textbackslash sin \theta \) and \( \cos \theta \).Their fundamental understanding helps identify any angle's correct trigonometric properties.

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Most popular questions from this chapter

Verify that each trigonometric equation is an identity. $$\sec x-\cos x+\csc x-\sin x-\sin x \tan x=\cos x \cot x$$

Amperage, Wattage, and Voltage Amperage is a measure of the amount of electricity that is moving through a circuit, whereas voltage is a measure of the force pushing the electricity. The wattage \(W\) consumed by an electrical device can be determined by calculating the product of the amperage \(I\) and voltage \(V .\) (Source: Wilcox, G. and C. Hesselberth, Electricity for Engineering Technology, Allyn \& Bacon.)(a) A household circuit has voltage $$ V=163 \sin 120 \pi t $$ when an incandescent light bulb is turned on with amperage $$ I=1.23 \sin 120 \pi t $$ Graph the wattage \(W=V I\) consumed by the light bulb in the window \([0,0.05]\) by $$ [-50,300] $$ (b) Determine the maximum and minimum wattages used by the light bulb. (c) Use identities to determine values for \(a, c,\) and \(\omega\) so that \(W=a \cos (\omega t)+c\) (d) Check your answer by graphing both expressions for \(W\) on the same coordinate axes. (e) Use the graph to estimate the average wattage used by the light. For how many watts (to the nearest integer) do you think this incandescent light bulb is rated?

Solve each problem. Musicians sometimes tune instruments by playing the same tone on two different instruments and listening for a phenomenon known as beats. Beats occur when two tones vary in frequency by only a few hertz. When the two instruments are in tune, the beats disappear. The ear hears beats because the pressure slowly rises and falls as a result of this slight variation in the frequency. This phenomenon can be seen using a graphing calculator. (Source: Pierce, \(\mathrm{J}\)., The Science of Musical Sound, Scientific American Books.) (a) Consider the two tones with frequencies of \(220 \mathrm{Hz}\) and \(223 \mathrm{Hz}\) and pressures \(P_{1}=0.005 \sin 440 \pi t\) and \(P_{2}=0.005\) sin \(446 \pi t,\) respectively. Graph the pressure \(P=P_{1}+P_{2}\) felt by an eardrum over the 1 -sec interval \([0.15,1.15] .\) How many beats are there in 1 sec? (b) Repeat part (a) with frequencies of 220 and \(216 \mathrm{Hz}\) (c) Determine a simple way to find the number of beats per second if the frequency of each tone is given.

Verify that each equation is an identity. $$\tan 2 \theta=\frac{-2 \tan \theta}{\sec ^{2} \theta-2}$$

A coil of wire rotating in a magnetic field induces a voltage $$E=20 \sin \left(\frac{\pi t}{4}-\frac{\pi}{2}\right)$$ Use an identity from this section to express this in terms of \(\cos \frac{\pi t}{4}\).

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