/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for Precalculus Student Solutions Manual 5th Chapter 7 - (Page 4) [step by step] | 91Ó°ÊÓ

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Problem 8

Use identities to find each exact value. (Do not use a calculator.). $$\cos \left(-15^{\circ}\right)$$

Problem 9

Write short answers. Consider the inverse tangent function, defined by \(y=\tan ^{-1} x,\) or \(y=\arctan x\) (a) What is its domain? (b) What is its range? (c) Is this function increasing or decreasing? (d) Is there any real number \(x\) for which arctan \(x\) is not defined? If so, what is it (or what are they)?

Problem 9

Find \(\sin \theta\) $$\cot \theta=-\frac{1}{5}, \theta \text { in quadrant IV }$$

Problem 9

Use identities to find values of the sine and cosine functions for each angle measure. $$2 x, \text { given } \tan x=2 \text { and } \cos x > 0$$

Problem 10

Find \(\sin \theta\) $$\cot \theta=-\frac{1}{3}, \theta \text { in quadrant IV }$$

Problem 10

Lindsay solved the equation \(\sin x=1-\cos x\) by squaring each side to get $$ \sin ^{2} x=1-2 \cos x+\cos ^{2} x $$ Several steps later, using correct algebra, she concluded that the solution set for solutions over the interval \([0,2 \pi)\) is \(\left\\{0, \frac{\pi}{2}, \frac{3 \pi}{2}\right\\} .\) Explain why this is not the correct solution set.

Problem 10

Perform each indicated operation and simplify the result so that there are no quotients. $$(1+\tan \theta)^{2}-2 \tan \theta$$

Problem 10

Use identities to find each exact value. (Do not use a calculator.). $$\cos 105^{\circ}$$

Problem 11

Use identities to find values of the sine and cosine functions for each angle measure. $$2 \theta, \text { given } \sin \theta=-\frac{\sqrt{5}}{7} \text { and } \cos \theta > 0$$

Problem 11

Find \(\sin \theta\) $$\cos (-\theta)=\frac{\sqrt{5}}{5}, \tan \theta<0$$

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