Chapter 6: Problem 37
$$\text {Graph each function over a two-period interval. Give the period and amplitude.}$$ $$y=\frac{1}{2} \cos \frac{\pi}{2} x$$
Short Answer
Expert verified
Amplitude: \(\frac{1}{2}\), Period: 4.
Step by step solution
01
- Identify the standard form
The given function is in the form of the cosine function. The standard form of the cosine function is: \( y = A \cos(Bx) \)
02
- Determine the amplitude
The amplitude (A) is the coefficient in front of the cosine function. For the given function, \( A = \frac{1}{2} \).
03
- Determine the period
The period (T) of the cosine function is calculated using the formula: \( T = \frac{2\pi}{B} \). Here, \( B = \frac{\pi}{2} \). So, \[ T = \frac{2\pi}{\frac{\pi}{2}} = 4 \]
04
- Graph the function over a two-period interval
To graph the function, note that one period is 4. Therefore, two periods span from 0 to 8. Plot the cosine curve considering the amplitude \(A = \frac{1}{2} \) and period \(T = 4\). The cosine function starts at its maximum value, so at \( x = 0 \), \( y = \frac{1}{2} \). At \( x = 2 \), \( y = 0 \). At \( x = 4 \), \( y = -\frac{1}{2} \). The pattern then repeats for the second period (from \( x = 4 \) to \( x = 8 \)).
05
- Verify key points
Verify that the key points follow the expected pattern of the cosine graph shifted and scaled accordingly. Important points are at the intervals of one-fourth the period: \( 0, 1, 2, 3, 4, 5, 6, 7, 8 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
In trigonometry, the amplitude of a function refers to the height of its peaks from the centerline. For a cosine function, the amplitude is half the distance between the maximum and minimum values it can take. The standard form of a cosine function is given by:
\[ y = A \cos(Bx) \] Here, A represents the amplitude. In the exercise problem: \[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] The amplitude (A) is \frac{1}{2}\. This means that the maximum value of the function is 0.5 and the minimum value is -0.5. The function oscillates between these two values. The amplitude is essential for understanding the range of the function and ensuring the accuracy of its graph.
\[ y = A \cos(Bx) \] Here, A represents the amplitude. In the exercise problem: \[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] The amplitude (A) is \frac{1}{2}\. This means that the maximum value of the function is 0.5 and the minimum value is -0.5. The function oscillates between these two values. The amplitude is essential for understanding the range of the function and ensuring the accuracy of its graph.
Period
The period of a trigonometric function is the distance it takes for the function to complete one full cycle before repeating. For the cosine function, the standard form is: \[ y = A \cos(Bx) \] The period (T) is calculated using the formula:
\[ T = \frac{2\pi}{B} \] For the given function:
\[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] The coefficient of x (B) is \frac{\pi}{2}\. Substituting this into the formula gives: \[ T = \frac{2\pi}{\frac{\pi}{2}} = 4 \] This means that one full cycle of the cosine wave completes every 4 units. Over a two-period interval, the graph should be plotted from x=0 to x=8.
\[ T = \frac{2\pi}{B} \] For the given function:
\[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] The coefficient of x (B) is \frac{\pi}{2}\. Substituting this into the formula gives: \[ T = \frac{2\pi}{\frac{\pi}{2}} = 4 \] This means that one full cycle of the cosine wave completes every 4 units. Over a two-period interval, the graph should be plotted from x=0 to x=8.
Cosine Function
The cosine function is one of the fundamental trigonometric functions used to describe oscillatory behaviors, such as waves. It is generally expressed in its standard form as:
\[ y = A \cos(Bx) \] Key things to remember about cosine functions:
\[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] To plot this function over a two-period interval, recognize its amplitude (\frac{1}{2}\right). By plotting key points at intervals of one-fourth the period (every 1 unit in this case), the function starts at its maximum value of \frac{1}{2}\right) at x=0. It then reaches zero at x=2, its minimum of -\frac{1}{2}\left) at x=4, and zero again at x=6. This pattern repeats in the second period from x=4 to x=8.
\[ y = A \cos(Bx) \] Key things to remember about cosine functions:
- They start at their maximum value when x=0.
- They are symmetric about the y-axis.
- They oscillate between positive and negative amplitudes.
\[ y = \frac{1}{2} \cos(\frac{\pi}{2} x) \] To plot this function over a two-period interval, recognize its amplitude (\frac{1}{2}\right). By plotting key points at intervals of one-fourth the period (every 1 unit in this case), the function starts at its maximum value of \frac{1}{2}\right) at x=0. It then reaches zero at x=2, its minimum of -\frac{1}{2}\left) at x=4, and zero again at x=6. This pattern repeats in the second period from x=4 to x=8.