/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 92 Let \(u=\ln a\) and \(v=\ln b .\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(u=\ln a\) and \(v=\ln b .\) Write each expression in terms of \(u\) and \(v\) without using the In function. $$\ln \frac{a^{3}}{b^{2}}$$

Short Answer

Expert verified
The expression \( \ln \left( \frac{a^{3}}{b^{2}} \right) \ \) in terms of \( u \ \) and \( v \ \) is \( 3u - 2v \ \).

Step by step solution

01

Understand Logarithm Properties

Recall the properties of logarithms, specifically: 1. \( \ln(\frac{A}{B}) = \ln(A) - \ln(B) \ \)2. \( \ln(A^n) = n \ln(A) \ \)
02

Apply Properties to Logarithm

Using the properties of logarithms, rewrite the expression:\ \( \ln \left( \frac{a^{3}}{b^{2}} \right) = \ln(a^{3}) - \ln(b^{2}) \ \)
03

Expand Using Logarithm Powers

Expand the terms using the power rule of logarithms:\ \( \ln(a^{3}) - \ln(b^{2}) = 3 \ln(a) - 2 \ln(b) \ \)
04

Substitute Given Values

Substitute \( \ln(a) \ \) with \( u \ \) and \( \ln(b) \ \) with \( v \ \):\ \( 3 \ln(a) - 2 \ln(b) = 3u - 2v \ \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

natural logarithm
The natural logarithm, denoted as \(\backslashln\) or simply \ln\, is a special type of logarithm with the base of Euler's number \(e\) which is approximately 2.71828. It simplifies the process of dealing with continuous growth, decay, and other natural phenomena due to its mathematical properties.
For instance, the natural logarithm of \(e\) itself is 1, because \(\backslashln(e) = 1\). Similarly, \(\backslashln(1) = 0\).
Natural logarithms are usually used in fields like calculus and differential equations. They are also key in any situation where exponential decay or growth is modeled. Understanding the concept of a natural logarithm sets the foundation for higher-level mathematics.
logarithm power rule
The logarithm power rule is a fundamental property of logarithms. This rule states that for any positive number \(a\) and real number \(n\):
\(\ln(a^{n}) = n \ln(a)\)
This means you can move the exponent in front of the logarithm as a multiplier. For example:
- \(\ln(a^{3}) = 3 \ln(a)\)
- \(\ln(a^{5}) = 5 \ln(a)\)
Using this rule, we can easily rewrite and simplify logarithmic expressions involving exponents. In the exercise above, we utilized the power rule to expand \(\ln(a^{3}) - \ln(b^{2})\) into \(3 \ln(a) - 2 \ln(b)\). This provides a more straightforward form when dealing with complex logarithmic functions.
logarithmic functions
Logarithmic functions are a type of function defined as the inverse of exponential functions. They are written in the form \(y = \ln(x)\), where \(x > 0\).
A key feature of logarithmic functions is their ability to transform multiplicative relationships into additive ones, simplifying complex expressions. Some important properties include:
  • \( \ln(AB) = \ln(A) + \ln(B) \)
  • \( \ln(\frac{A}{B}) = \ln(A) - \ln(B) \)
These properties often appear in exercises where we simplify or solve equations involving logarithms.
In the given exercise, we used the property \( \ln(\frac{A}{B}) = \ln(A) - \ln(B) \) to break down the expression \(\ln(\frac{a^3}{b^2})\). This application shows how logarithmic functions and their properties are highly useful in simplifying complex mathematical expressions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evolution of Language The number of years, \(n\), since two independently evolving languages split off from a common ancestral language is approximated by $$ n \approx-7600 \log r $$ where \(r\) is the proportion of words from the ancestral language common to both languages. (a) Find \(n\) if \(r=0.9\) (b) Find \(n\) if \(r=0.3\) (c) How many years have elapsed since the split if half of the words of the ancestral language are common to both languages?

The amount of medication still available in the system is given by the function $$ f(t)=200(0.90)^{t} $$ In this model, \(t\) is in hours and \(f(t)\) is in milligrams. How long will it take for this initial dose to reach the dangerously low level of \(50 \mathrm{mg} ?\) Population Size Many environmental situations place effective limits on the growth of the number of an organism in an area. Many such limited-growth situations are described by the logistic function $$ G(x)=\frac{M G_{0}}{G_{0}+\left(M-G_{0}\right) e^{-k M x}} $$ where \(G_{0}\) is the initial number present, \(M\) is the maximum possible size of the population, and \(k\) is a positive constant. The screens illustrate a typical logistic function calculation and graph. (Graph can't copy) Assume that \(G_{0}=100, M=2500, k=0.0004,\) and \(x=\) time in decades ( \(10-\) yr periods). (a) Use a calculator to graph the function, using \(0 \leq x \leq 8,0 \leq y \leq 2500\) (b) Estimate the value of \(G(2)\) from the graph. Then evaluate \(G(2)\) algebraically to find the population after 20 yr. (c) Find the \(x\) -coordinate of the intersection of the curve with the horizontal line \(y=1000\) to estimate the number of decades required for the population to reach \(1000 .\) Then solve \(G(x)=1000\) algebraically to obtain the exact value of \(x .\)

Consumer Price Index The U.S. Consumer Price Index for the years \(1990-2009\) is approximated by $$ A(t)=100 e^{0.026 t} $$ where \(t\) represents the number of years after \(1990 .\) (since \(A(16)\) is about \(152,\) the amount of goods that could be purchased for \(\$ 100\) in 1990 cost about \(\$ 152\) in 2006 .) Use the function to determine the year in which costs will be \(100 \%\) higher than in \(1990 .\)

Use another type of logistic function. Tree Growth The height of a certain tree in feet after \(x\) years is modeled by $$ f(x)=\frac{50}{1+47.5 e^{-0.22 x}} $$ (a) Make a table for \(f\) starting at \(x=10,\) and incrementing by \(10 .\) What appears to be the maximum height of the tree? (b) Graph \(f\) and identify the horizontal asymptote. Explain its significance. (c) After how long was the tree 30 ft tall?

Spread of Disease During an epidemic, the number of people who have never had the disease and who are not immune (they are susceptible) decreases exponentially according to the function $$ f(t)=15,000 e^{-0.05 t} $$ where \(t\) is time in days. Find the number of susceptible people at each time. (a) at the beginning of the epidemic (b) after 10 days (c) after 3 weeks

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.