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Given the approximations \(\log _{10} 2=0.3010\) and \(\log _{10} 3=0.4771,\) find logarithm without using a calculator. $$\log _{10} \frac{9}{4}$$

Short Answer

Expert verified
0.3522

Step by step solution

01

Use Logarithm Properties

Utilize the properties of logarithms to rewrite the given logarithm. The property to use here is the quotient rule for logarithms: \[ \log _{10} \frac{a}{b}= \log_{10}a- \log_{10}b \]. Therefore, \[ \log_{10} \frac{9}{4} = \log_{10} 9 - \log_{10} 4 \].
02

Express Logarithms in Terms of Known Values

Express 9 and 4 in terms of 2 and 3, whose logarithms are given. Since \[ 9 = 3^2 \] and \[ 4 = 2^2 \], we can rewrite the equation as: \[ \log_{10} 9 - \log_{10} 4 = \log_{10} 3^2 - \log_{10} 2^2 \].
03

Apply Logarithm Power Rule

Utilize the power rule for logarithms: \[ \log_{10} a^b = b \cdot \log_{10} a \]. This simplifies the expression to: \[ \log_{10} 3^2 - \log_{10} 2^2 = 2 \cdot \log_{10} 3 - 2 \cdot \log_{10} 2 \].
04

Substitute Known Logarithm Values

Substitute the given values of \[ \log_{10} 2 = 0.3010 \] and \[ \log_{10} 3 = 0.4771 \] into the expression: \[ 2 \cdot \log_{10} 3 - 2 \cdot \log_{10} 2 = 2 \cdot 0.4771 - 2 \cdot 0.3010 \].
05

Perform the Final Arithmetic

Evaluate the expression step by step: \[ 2 \cdot 0.4771 = 0.9542 \] and \[ 2 \cdot 0.3010 = 0.6020 \]. Finally, the result is: \[ 0.9542 - 0.6020 = 0.3522 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule for Logarithms
The quotient rule for logarithms is a key property that helps simplify the logarithms of fractions. It states that the logarithm of a quotient is the logarithm of the numerator minus the logarithm of the denominator. In mathematical terms, this is written as: \ \( \log _{10} \frac{a}{b}= \log_{10}a- \log_{10}b \). For the given problem, \( \log _{10} \frac{9}{4} \), we apply this property to rewrite it as: \ \( \log_{10} 9 - \log_{10} 4 \.\) This makes it easier to handle if we know or can find the logarithms of simpler numbers like 2 and 3. This rule simplifies complex logarithmic calculations. Try identifying other opportunities to use this in your homework.
Power Rule for Logarithms
Another crucial property is the power rule for logarithms, which allows us to handle logarithms of numbers raised to a power. It states: \ \( \log_{10} a^b = b \cdot \log_{10} a \). This means you can move the exponent in front as a multiplier. In the problem, we use this with: \ \( \log_{10} 3^2 - \log_{10} 2^2 = 2 \cdot \log_{10} 3 - 2 \cdot \log_{10} 2 \.\) Doing so takes the exponential complexity out of the logarithms, making it simpler to substitute known values. This rule is exceptionally handy when you encounter exponents in logarithmic expressions.
Substitution
Substitution is a problem-solving technique where known values are substituted into an expression. In our example, we substitute the known logarithm values for 2 and 3 into the expression we derived. Since we know: \ \( \log_{10} 2 = 0.3010 \) and \ \( \log_{10} 3 = 0.4771 \,\) we replace these in the equation: \ \( 2 \cdot \log_{10} 3 - 2 \cdot \log_{10} 2 = 2 \cdot 0.4771 - 2 \cdot 0.3010. \) This step simplifies the solution process, making it purely arithmetic. Finally, we perform the calculations: \ \( 2 \cdot 0.4771 = 0.9542 \) and \ \( 2 \cdot 0.3010 = 0.6020 \), then find the difference: \ \( 0.9542 - 0.6020 = 0.3522 \.\) Substitution is a core method to make complex equations more manageable.

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Most popular questions from this chapter

Use the various properties of exponential and logarithmic functions to evaluate the expressions in parts \((a)-(c)\) Given \(g(x)=e^{x},\) find (a) \(g(\ln 4) \quad\) (b) \(g\left(\ln \left(5^{2}\right)\right)\) (c) \(g\left(\ln \left(\frac{1}{\varepsilon}\right)\right)\)

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=\frac{2 x+6}{x-3}, \quad x \neq 3$$

For individual or collaborative investigation (Exercises \(117-122\) ) Assume \(f(x)=a^{x}\), where \(a>1 .\) Work these exercises in order. If \(\left.a=10, \text { what is the equation for } y=f^{-1}(x) ? \text { (You need not solve for } y .\right)\)

Recreational Expenditures Personal consumption expenditures for recreation in billions of dollars in the United States during the years \(2004-2008\) can be approximated by the function $$ A(t)=769.5 e^{0.0503 t} $$ where \(t=0\) corresponds to the year \(2004 .\) Based on this model, how much were personal consumption expenditures in \(2008 ?\)

Emissions Tax One action that government could take to reduce carbon emissions into the atmosphere is to levy a tax on fossil fuel. This tax would be based on the amount of carbon dioxide emitted into the air when the fuel is burned. The cost-benefit equation $$\ln (1-P)=-0.0034-0.0053 T$$ models the approximate relationship between a tax of \(T\) dollars per ton of carbon and the corresponding percent reduction \(P\) (in decimal form) of emissions of carbon dioxide. (Source: Nordhause, W., "To Slow or Not to Slow: The Economics of the Greenhouse Effect," Yale University, New Haven, Connecticut.) (a) Write \(P\) as a function of \(T\). (b) Graph \(P\) for \(0 \leq T \leq 1000 .\) Discuss the benefit of continuing to raise taxes on carbon (c) Determine \(P\) when \(T=60\) dollars, and interpret this result. (d) What value of \(T\) will give a \(50 \%\) reduction in carbon emissions?

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