/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 Use the properties of logarithms... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the properties of logarithms to rewrite expression. Simplify the result if possible. Assume all variables represent positive real numbers. $$\log _{m} \sqrt{\frac{5 r^{3}}{z^{5}}}$$

Short Answer

Expert verified
\(1/2\log_{m} 5 + (3/2)\log_{m} r - (5/2)\log_{m} z \)

Step by step solution

01

Express the Square Root as an Exponent

The square root can be rewritten as an exponent of 1/2. So, rewrite the expression \( \log _{m} \sqrt{\frac{5r^{3}}{z^{5}}} \) as \( \log _{m} \(\frac{5r^{3}}{z^{5}}\)^{1/2} \)
02

Apply the Power Rule of Logarithms

According to the power rule of logarithms, \( \log_b(x^y) = y \log_b(x) \). Applying this rule, move the exponent \(1/2\) in front of the logarithm: \( \(1/2\) \log _{m} \(\frac{5r^{3}}{z^{5}}\). \)
03

Apply the Quotient Rule of Logarithms

The quotient rule of logarithms states \( \log_b\frac{x}{y} = \log_b(x) - \log_b(y) \). Apply this rule to split the logarithm: \( \(1/2\) (\log _{m} 5r^{3} - \log _{m} z^{5}). \)
04

Apply the Product Rule of Logarithms

The product rule of logarithms states \( \log_b(xy) = \log_b(x) + \log_b(y) \). Apply this rule to split the first logarithm: \( \(1/2\) (\log _{m} 5 + \log _{m} r^{3} - \log _{m} z^{5}). \)
05

Apply the Power Rule Again

Once more, use the power rule of logarithms to bring the exponents in front of their respective logarithms: \( \(1/2\) (\log _{m} 5 + 3 \log _{m} r - 5 \log _{m} z). \)
06

Distribute the Fraction

Finally, distribute \(1/2\) across all terms inside the parentheses: \( (1/2)\log _{m} 5 + (3/2)\log _{m} r - (5/2)\log _{m} z. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule of Logarithms
The power rule of logarithms is a fundamental property used to manipulate logarithmic expressions. It states that for any positive real numbers \(a\) and \(b\), and any real number \(c\), the expression \(\log_{a}(b^c)\) can be rewritten as \(c \, \log_{a}(b)\). This rule is very useful when dealing with exponents within logarithms. For example, in the expression \( \log_{m} \left( \frac{5r^3}{z^5} \right)^{1/2} \), the exponent \(\frac{1}{2}\) can be moved in front of the logarithm, simplifying the expression: \( \frac{1}{2} \, \log_{m} \left( \frac{5r^3}{z^5} \right) \). This makes it easier to apply other logarithmic rules.
Quotient Rule of Logarithms
The quotient rule of logarithms helps simplify the logarithms of fractions. It states that for any positive real numbers \(a\), \(b\), and \(c\), \( \log_a \left( \frac{b}{c} \right) \) can be simplified to \( \log_a(b) - \log_a(c) \). This means the logarithm of a quotient is the difference of the logarithms of the numerator and the denominator. For instance, in our expression \( \frac{1}{2} \log_m \left( \frac{5r^3}{z^5} \right) \), applying the quotient rule gives us \( \frac{1}{2} (\log_m (5r^3) - \log_m (z^5)) \). This allows each part of the fraction to be handled separately, which simplifies the computation further.
Product Rule of Logarithms
The product rule of logarithms is another key property. It states that for any positive real numbers \(a\), \(b\), and \(c\), \( \log_a(bc) \) can be rewritten as \( \log_a(b) + \log_a(c) \). That is, the logarithm of a product is the sum of the logarithms of the factors. Using this rule in our expression, we can simplify \(\log_m (5r^3)\) as \(\log_m (5) + \log_m (r^3)\). So our expression becomes \( \frac{1}{2} (\log_m (5) + \log_m (r^3) - \log_m (z^5)) \). This further breaks down complex expressions into simpler parts.
Simplifying Logarithmic Expressions
Simplifying logarithmic expressions often requires using a combination of logarithm properties like the power, quotient, and product rules. For example, take \( \frac{1}{2} (\log_m 5 + \log_m r^3 - \log_m z^5) \). Notice that \( \log_m r^3 \) and \( \log_m z^5 \) can both be simplified further using the power rule. Applying this rule, we transform each term: \( \log_m r^3 \) becomes \( 3 \log_m r \) and \( \log_m z^5 \) becomes \( 5 \log_m z \). Substituting back, we get: \( \frac{1}{2} (\log_m 5 + 3 \log_m r - 5 \log_m z) \). Finally, distribute \( \frac{1}{2} \): \( \frac{1}{2} \log_m 5 + \frac{3}{2} \log_m r - \frac{5}{2} \log_m z \). This combination of rules streamlines complex logarithmic expressions into simpler, more manageable parts.

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Most popular questions from this chapter

Product Sales Sales of a product, under relatively stable market conditions but in the absence of promotional activities such as advertising, tend to decline at a constant yearly rate. This rate of sales decline varies considerably from product to product, but it seems to remain the same for any particular product. The sales decline can be expressed by the function $$ S(t)=S_{0} e^{-a t} $$ where \(S(t)\) is the rate of sales at time \(t\) measured in years, \(S_{0}\) is the rate of sales at time \(t=0,\) and \(a\) is the sales decay constant. (a) Suppose the sales decay constant for a particular product is \(a=0.10 .\) Let \(S_{0}=50,000\) and find \(S(1)\) and \(S(3)\) (b) Find \(S(2)\) and \(S(10)\) if \(S_{0}=80,000\) and \(a=0.05\)

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