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Solve each exponential equation. Express irrational solutions as decimals correct to the nearest thousandth. $$3^{x}=7$$

Short Answer

Expert verified
x ≈ 1.771.

Step by step solution

01

Understand the equation

The given equation is an exponential equation of the form \(a^x=b\). In this case, \(a=3\) and \(b=7\). The goal is to find the value of \(x\) that satisfies the equation.
02

Take the logarithm of both sides

Take the natural logarithm (ln) of both sides of the equation to bring the exponent down. This gives \(\ln(3^x)=\ln(7)\).
03

Use the power rule of logarithms

Apply the power rule of logarithms, which states \(\ln(a^b)=b\ln(a)\). So, \(\ln(3^x)=x\ln(3)\) becomes \(x\ln(3)=\ln(7)\).
04

Solve for \(x\)

Isolate \(x\) by dividing both sides of the equation by \(\ln(3)\). Thus, \(x=\frac{\ln(7)}{\ln(3)}\).
05

Evaluate the expression

Use a calculator to find the values of \(\ln(7)\) and \(\ln(3)\), then divide. \(\ln(7)\approx1.945910\) and \(\ln(3)\approx1.098612\). So, \(x\approx\frac{1.945910}{1.098612}\approx1.771\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

exponential equations
Let's start by understanding what exponential equations are. Exponential equations are mathematical expressions where the variable appears as an exponent. A typical exponential equation looks like this: \(a^x = b\). Here, \(a\) is the base, \(x\) is the exponent (which we want to solve for), and \(b\) is a constant.
The challenge with exponential equations is that they involve finding the value of the exponential variable, which can be tricky without specific techniques like logarithms.
For example, in our given exercise, we have \(3^x = 7\). To solve for \(x\), we can't simply perform traditional algebraic operations. Instead, we'll need to use logarithms to work with the exponent.
natural logarithms
Natural logarithms (denoted as \(\ln\)) are a powerful tool for solving exponential equations. The natural logarithm function is the inverse of the exponential function with base \ e \ (Euler's number, approximately 2.718).
When we apply the natural logarithm to both sides of an exponential equation, it allows us to bring the exponent down to a regular number, making it easier to solve for the variable.
For example, starting from \(3^x = 7\), taking \(\ln\) of both sides gives us \(\ln(3^x) = \ln(7)\).
power rule of logarithms
The power rule of logarithms states that \(\ln(a^b) = b\ln(a)\). This property is incredibly useful when dealing with exponential equations.
For the equation we started with, \(\ln(3^x)\) can be simplified using the power rule. It becomes \(x\ln(3)\).
This transformation makes it possible to isolate \(x\), which is our goal.
So, \(\ln(3^x) = \ln(7)\) becomes \(x\ln(3) = \ln(7)\).
irrational solutions
Sometimes, solving exponential equations results in irrational numbers. Irrational numbers cannot be exactly expressed as a simple fraction and their decimal representations are non-repeating and non-terminating.
In our example, solving for \(x\) involves dividing \(\ln(7)\) by \(\ln(3)\). Using a calculator, we find that \(\ln(7) \approx 1.945910\) and \(\ln(3) \approx 1.098612\). This gives \(x \approx \frac{1.945910}{1.098612} \approx 1.771\).
Thus, \(x \approx 1.771\) is an irrational number and we approximate it to three decimal places.

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Most popular questions from this chapter

At the World Championship races held at Rome's Olympic Stadium in \(1987,\) American sprinter Carl Lewis ran the 100 -m race in 9.86 sec. His speed in meters per second after \(t\) seconds is closely modeled by the function $$f(t)=11.65\left(1-e^{-t / 1.27}\right)$$ (Source: Banks, Robert B., Towing Icebergs, Falling Dominoes, and Other Adventures in Applied Mathematics, Princeton University Press.) (a) How fast was he running as he crossed the finish line? (b) After how many seconds was he running at the rate of \(10 \mathrm{m}\) per sec?

Emissions Tax One action that government could take to reduce carbon emissions into the atmosphere is to levy a tax on fossil fuel. This tax would be based on the amount of carbon dioxide emitted into the air when the fuel is burned. The cost-benefit equation $$\ln (1-P)=-0.0034-0.0053 T$$ models the approximate relationship between a tax of \(T\) dollars per ton of carbon and the corresponding percent reduction \(P\) (in decimal form) of emissions of carbon dioxide. (Source: Nordhause, W., "To Slow or Not to Slow: The Economics of the Greenhouse Effect," Yale University, New Haven, Connecticut.) (a) Write \(P\) as a function of \(T\). (b) Graph \(P\) for \(0 \leq T \leq 1000 .\) Discuss the benefit of continuing to raise taxes on carbon (c) Determine \(P\) when \(T=60\) dollars, and interpret this result. (d) What value of \(T\) will give a \(50 \%\) reduction in carbon emissions?

Use a graphing calculator to graph each function defined as follows, using the given viewing window. Use the graph to decide which functions are one-to-one. If a function is one-to-one, give the equation of its inverse. $$\begin{aligned}&f(x)=\frac{-x}{x-4}, \quad x \neq 4;\\\&[-1,8] \text { by }[-6,6]\end{aligned}$$

Use the change-of-base theorem to find an approximation to four decimal places for each logarithm. $$\log _{0.32} 5$$

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=-6 x-8$$

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