/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 $$\text { Find each value. If ap... [FREE SOLUTION] | 91Ó°ÊÓ

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$$\text { Find each value. If applicable, give an approximation to four decimal places.}$$ $$\ln \left(\frac{1}{e^{4}}\right)$$

Short Answer

Expert verified
\( -4 \)

Step by step solution

01

- Understand the Natural Logarithm

The natural logarithm function, denoted as \(\ln(x)\), is the inverse function of the exponential function \(e^x\). This means that \(\ln(e^x) = x\).
02

- Apply Logarithm Properties

Use the logarithm property \( \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \). In this case, \(\frac{1}{e^4}\) can be rewritten in the form of \((a / b)\), where \(a = 1\) and \(b = e^4\). Thus, \(\ln\left(\frac{1}{e^4}\right) = \ln(1) - \ln(e^4)\).
03

- Simplify Logarithm Terms

Recall that \(\ln(1) = 0\) and \(\ln(e^k) = k\). Thus, \(\ln(1) = 0\) and \(\ln(e^4) = 4\). Using these, \(\ln\left(\frac{1}{e^4}\right) = 0 - 4\).
04

- Combine the Results

Combining the simplified terms, the expression becomes \(\ln\left(\frac{1}{e^4}\right) = -4\).
05

- Final Answer

Therefore, \(\ln\left(\frac{1}{e^4}\right) = -4\). No further approximation is needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
Inverse functions reverse the effect of the original function. For example, the natural logarithm function, represented as \[ \ln(x) \], is the inverse of the exponential function, \[ e^x \]. This means that if you apply the exponential function to a number and then take the natural logarithm of the result, you will get back the original number.

Mathematically, this is represented as: \[ \ln(e^x) = x \].

Understanding this relationship helps us solve equations involving logarithms and exponentials more easily. For example, in the given exercise, we use this property to simplify \[ \ln(e^4) = 4 \].
Exponential Functions
Exponential functions are functions where the variable appears in the exponent. The most common is \[ e^x \], where \[ e \] is the base of natural logarithms, approximately equal to 2.71828. Exponential functions grow rapidly and are found commonly in natural phenomena such as population growth and radioactive decay.

One important property is that the exponential function and its inverse, the natural logarithm function, cancel each other out: \[ e^{\ln(x)} = x \]. This property is fundamental in calculus and helps us solve many algebraic and differential equations.

In the exercise provided, we deal with \[ e^4 \] as part of simplifying the logarithmic expression. By understanding how exponentials and their inverses interact, we can define the problem as \[ \ln\left( \frac{1}{e^4} \right) \] and then solve it by breaking it down into more manageable terms.
Logarithm Properties
Logarithm properties help us manipulate and simplify logarithmic expressions. Here are some essential properties:
  • \[ \ln(1) = 0 \]: The natural logarithm of 1 is 0 because \[ e^0 = 1 \].
  • \[ \ln(e^k) = k \]: This property states that the natural logarithm of \[ e \] raised to any power \[ k \] is \[ k \].
  • \[ \ln\left( \frac{a}{b} \right) = \ln(a) - \ln(b) \]: This property allows us to split a logarithm of a fraction into the difference of two logarithms.
In the given exercise, we specifically use the property \[ \ln\left( \frac{1}{e^4} \right) = \ln(1) - \ln(e^4) \]. By recalling that \[ \ln(1) = 0 \], and \[ \ln(e^4) = 4 \], we simplify the expression down to \[ 0 - 4 = -4 \]. These properties are invaluable tools in both algebra and calculus for simplifying and solving equations.

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Most popular questions from this chapter

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=\sqrt{6+x}, \quad x \geq-6$$

(Modeling) Solve each problem. See Example 11 . Atmospheric Pressure The atmospheric pressure (in millibars) at a given altitude (in meters) is shown in the table. $$\begin{array}{c|c||c|c} \hline \text { Altitude } & \text { Pressure } & \text { Altitude } & \text { Pressure } \\ \hline 0 & 1013 & 6000 & 472 \\ \hline 1000 & 899 & 7000 & 411 \\ \hline 2000 & 795 & 8000 & 357 \\ \hline 3000 & 701 & 9000 & 308 \\ \hline 4000 & 617 & 10,000 & 265 \\ \hline 5000 & 541 & & \\ \hline \end{array}$$ (a) Use a graphing calculator to make a scatter diagram of the data for atmospheric pressure \(P\) at altitude \(x\). (b) Would a linear or an exponential function fit the data better? (c) The function $$ P(x)=1013 e^{-0.0001341 x} $$ approximates the data. Use a graphing calculator to graph \(P\) and the data on the same coordinate axes. (d) Use \(P\) to predict the pressures at \(1500 \mathrm{m}\) and \(11,000 \mathrm{m},\) and compare them to the actual values of 846 millibars and 227 millibars, respectively.

If the function is one-to-one, find its inverse. $$\\{(1,-3),(2,-7),(4,-3),(5,-5)\\}$$

At the World Championship races held at Rome's Olympic Stadium in \(1987,\) American sprinter Carl Lewis ran the 100 -m race in 9.86 sec. His speed in meters per second after \(t\) seconds is closely modeled by the function $$f(t)=11.65\left(1-e^{-t / 1.27}\right)$$ (Source: Banks, Robert B., Towing Icebergs, Falling Dominoes, and Other Adventures in Applied Mathematics, Princeton University Press.) (a) How fast was he running as he crossed the finish line? (b) After how many seconds was he running at the rate of \(10 \mathrm{m}\) per sec?

Use the various properties of exponential and logarithmic functions to evaluate the expressions in parts \((a)-(c)\) Given \(g(x)=e^{x},\) find (a) \(g(\ln 4) \quad\) (b) \(g\left(\ln \left(5^{2}\right)\right)\) (c) \(g\left(\ln \left(\frac{1}{\varepsilon}\right)\right)\)

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