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If the statement is in exponential form, write it in an equivalent logarithmic form. If the statement is in logarithmic form, write it in exponential form. $$2^{5}=32$$

Short Answer

Expert verified
\log_2(32) = 5\

Step by step solution

01

Identify the Given Form

The given statement is in exponential form: \(2^{5}=32\).
02

Understand the Conversion

To convert from exponential form \(a^b = c\) to logarithmic form, use the formula: \log_a(c) = b\.
03

Apply the Conversion

Using the formula, convert \(2^5 = 32\) into logarithmic form: \log_2(32) = 5\.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

exponential form
The exponential form of an equation is a mathematical way to express repeated multiplication of the same number. In this form, there is a base, an exponent, and the result. For instance, in the equation \(2^{5} = 32\), the base is 2, the exponent is 5, and the result is 32. This means that 2 is multiplied by itself 5 times. Exponential forms are useful in various fields such as science, engineering, and finance, particularly when dealing with growth rates and compound interest.

Key points to remember about exponential form:
  • The base (also called the 'radix') is the number being multiplied.
  • The exponent (also called the 'power') tells you how many times to multiply the base by itself.
  • The result is the outcome of the multiplication.
By understanding how to read and interpret exponential forms, we can make working with large numbers and repeated multiplication much simpler.
logarithmic form
Logarithmic form is another way to express exponential relationships. It is often used to solve for the exponent in exponential equations. The general formula for a logarithm is \(\log_a(c) = b\), which translates to 'the logarithm of c with base a equals b'. This means that if you raise a (the base) to the power of b (the exponent), you get the number c. For example, converting the exponential form \(2^5 = 32\) into logarithmic form gives us \(\log_2(32) = 5\). This indicates that 2 raised to the power of 5 equals 32.

Important things to remember about logarithmic form:
  • The base of the logarithm is the same as the base in the exponential form.
  • The argument of the logarithm (inside the parentheses) is the result from the exponential form.
  • The value of the logarithm is the exponent from the exponential form.
Using logarithmic form can simplify solving equations where the exponent is unknown, making complex calculations more manageable.
logarithmic conversion
Logarithmic conversion is the process of transforming an exponential expression into a logarithmic one, and vice versa. This conversion is crucial in solving equations and understanding the relationship between exponential and logarithmic forms. Let’s break down how to perform this conversion.

To convert from exponential form to logarithmic form, use the template:
  • Given: \(a^b = c\)
  • Convert to: \(\log_a(c) = b\)
Applying this to our example \(2^5 = 32\), we get \(\log_2(32) = 5\).

Conversely, to go from logarithmic form to exponential form, reverse the process:
  • Given: \(\log_a(c) = b\)
  • Convert to: \(a^b = c\)
Using \(\log_2(32) = 5\), you get \(2^5 = 32\)

Employing logarithmic conversion helps in many scenarios such as solving for unknown exponents and dealing with equations involving growth rates. By mastering these conversions, you'll have a better understanding of exponential and logarithmic relationships, which are foundational concepts in mathematics.

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Most popular questions from this chapter

Deer Population The exponential growth of the deer population in Massachusetts can be calculated using the model $$ f(x)=50,000(1+0.06)^{x} $$ where \(50,000\) is the initial deer population and 0.06 is the rate of growth. \(f(x)\) is the total population after \(x\) years have passed. (a) Predict the total population after 4 yr. (b) If the initial population was \(30,000\) and the growth rate was \(0.12,\) approximately how many deer would be present after 3 yr? (c) How many additional deer can we expect in 5 yr if the initial population is \(45,000\) and the current growth rate is \(0.08 ?\) (IMAGE CANT COPY)

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=\sqrt{6+x}, \quad x \geq-6$$

Health Care Spending Out-of-pocket spending in the United States for health care increased between 2004 and 2008 . The function $$ f(x)=2572 e^{0.0359 x} $$ models average annual expenditures per household, in dollars. In this model, \(x\) represents the year, where \(x=0\) corresponds to \(2004 .\) (Source: U.S. Bureau of Labor Statistics.) (a) Estimate out-of-pocket household spending on health care in 2008 . (b) Determine the year when spending reached \(\$ 2775\) per household.

Use a graphing calculator to find the solution set of each equation. Give solutions to the nearest hundredth. $$2^{-x}=\log _{10} x$$

Use a graphing calculator to solve each equation. Give irrational solutions correct to the nearest hundredth. $$e^{x}+\ln x=5$$

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