/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Find the \(\left[\mathrm{H}_{3} ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) for each substance with the given \(p H\) beer, 4.8

Short Answer

Expert verified
The \$\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\$ for beer is \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right] = 1.58\times 10^{-5} \ \mathrm{M}\).

Step by step solution

01

Understand the relationship between pH and \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\)

The pH of a solution is defined as \[ pH = - \log\left(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\right) \]. To find \[ \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] \], we need to rewrite this equation to solve for the concentration.
02

Rewrite the equation to solve for \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\)

Rearrange the pH equation to isolate \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\): \[ \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] = 10^{-pH} \]
03

Substitute the given pH value

Now, substitute the given pH value (4.8) into the equation: \[ \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] = 10^{-4.8} \]
04

Calculate the value

Calculate the concentration using a calculator: \[ \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] = 1.58 \times 10^{-5} \ \mathrm{M} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hydronium ion concentration
In chemistry, the hydronium ion concentration helps us determine how acidic or basic a solution is. The term hydronium ion refers to \[ H_{3}O^{+} \], which is formed when a hydrogen ion (\[H^{+}\]) combines with a water molecule (\[H_{2}O\]). To find the hydronium ion concentration of a solution, we often use its pH value.

For example, in our exercise, we are provided with the pH of beer, which is 4.8. We can use this value to find the concentration of hydronium ions in the beer. Understanding the hydronium ion concentration is essential in many areas of science, especially in determining the properties and reactivity of the solution.
pH formula
The pH of a solution is a measure of its acidity or basicity. It is defined by the formula:

\[ pH = - \log (\left[ H_{3}O^{+} \right]) \]

This formula tells us that pH is the negative logarithm (base 10) of the hydronium ion concentration. When we have a pH value, we can use this equation to find the hydronium ion concentration. To make this possible, we rearrange the equation:

\[ \left[ H_{3}O^{+} \right] = 10^{- pH} \]

For the beer with a pH of 4.8, substituting the pH value into this rearranged formula gives:

\[ \left[ H_{3}O^{+} \right] = 10^{-4.8} \].

Using a calculator, we find that \[ \left[ H_{3}O^{+} \right] \] is approximately \[1.58 \times \ 10^{-5} M \]

Understanding this formula helps in various fields, including environmental science and medicine.
logarithmic functions
Logarithmic functions are essential in pH calculations. A logarithm is the inverse of an exponentiation. The logarithmic function used in chemistry is the common logarithm (base 10).

When we express the pH of a solution, we use the logarithmic function:

\[ pH = - \log (\left[ H_{3}O^{+} \right]) \]

This means the pH is a measure of how many times we need to multiply 10 to get the hydronium ion concentration. Here's a simpler analogy:

If multiplying 10 three times (\[ 10^3 \]) equals 1000, then the log of 1000 is 3.
Applied to pH, a lower pH means a higher \[ \left[ H_{3}O^{+} \right] \]:
  • Low pH = more acidic
  • High pH = less acidic
For the beer example, a pH of 4.8 translates into a specific hydronium ion concentration using the inverse logarithmic function.
Logarithms simplify the complexity, making it easier to work with very large or small numbers in scientific calculations.
acid-base chemistry
Acid-base chemistry explores the properties of acids and bases and their reactions. Understanding this field is crucial for areas ranging from industrial manufacturing to biological functions.

In our context, acids increase the hydronium ion concentration (\[ \left[ H_{3}O^{+} \right] \]) in a solution. The stronger the acid, the higher the \[ \left[ H_{3}O^{+} \right] \], and thus, the lower the pH.

Common examples include:
  • Strong acids like hydrochloric acid (HCl) which completely dissociate into ions in water.
  • Weak acids like acetic acid (vinegar), which only partially dissociate.
Beer, with a pH of 4.8, is a weakly acidic solution. The principle we used to find its hydronium ion concentration is central to understanding how solutions behave chemically.

Acid-base chemistry also explains reactions like neutralization, where acids and bases react to form water and salts. These principles have real-world applications, including medical diagnostics, environmental monitoring, and manufacturing processes.

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Most popular questions from this chapter

World Population Growth since 2000 , world population in millions closely fits the exponential function $$ y=6084 e^{00120 x} $$ where \(x\) is the number of years since 2000 . (Source: U.S. Census Bureau.) (a) The world population was about 6853 million in 2010 . How closely does the function approximate this value? (b) Use this model to predict the population in 2020 . (c) Use this model to predict the population in 2030 . (d) Explain why this model may not be accurate for 2030 .

Use a graphing calculator to graph each function defined as follows, using the given viewing window. Use the graph to decide which functions are one-to-one. If a function is one-to-one, give the equation of its inverse. $$\begin{aligned}&f(x)=6 x^{3}+11 x^{2}-6;\\\&[-3,2] \text { by }[-10,10]\end{aligned}$$

Use a graphing calculator to graph each function defined as follows, using the given viewing window. Use the graph to decide which functions are one-to-one. If a function is one-to-one, give the equation of its inverse. $$\begin{aligned}&f(x)=x^{4}-5 x^{2};\\\&[-3,3] \text { by }[-8,8]\end{aligned}$$

Let \(u=\ln a\) and \(v=\ln b .\) Write each expression in terms of \(u\) and \(v\) without using the In function. $$\ln \sqrt{\frac{a^{3}}{b^{5}}}$$

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=-x^{3}-2$$

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