/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Answer each of the following. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Answer each of the following. The domain of \(f\) is equal to the _______________ of \(f^{-1},\) and the range of \(f\) is equal to the _________________ of \(f^{-1}\).

Short Answer

Expert verified
The domain of \(f\) is the range of \(f^{-1}\), and the range of \(f\) is the domain of \(f^{-1}\).

Step by step solution

01

Identify the Domain of a Function

The domain of a function, denoted as \(f\), is the set of all possible input values (x-values) for which the function is defined.
02

Relationship Between a Function and Its Inverse

The inverse of a function, denoted as \(f^{-1}\), reverses the roles of the input and output of the original function. Therefore, the input values for the original function become the output values for the inverse function, and vice versa.
03

Determine the Domain and Range Relationships

From Step 2, it follows that the domain of the original function \(f\) is the range of the inverse function \(f^{-1}\). Conversely, the range of the original function \(f\) is the domain of the inverse function \(f^{-1}\).
04

Fill in the Blanks

Based on the relationships established, we can conclude: The domain of \(f\) is equal to the range of \(f^{-1}\), and the range of \(f\) is equal to the domain of \(f^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
The domain of a function is a fundamental concept in understanding how functions operate. It refers to the set of all possible input values (x-values) that a function can accept. Let's break this down further. If we have a function denoted as \( f(x) \), the domain is essentially all the x-values for which the function \( f(x) \) is defined and produces real numbers.
For example, consider the function \( f(x) = \frac{1}{x} \). Here, the function is defined for all x-values except for x = 0, because division by zero is undefined. Hence, the domain is all real numbers except 0.
In general, to determine the domain of a given function, you need to identify any restrictions on the input values. These restrictions can come from:
  • Divisions by zero
  • Square roots of negative numbers (for real-valued functions)
  • Logarithms of non-positive numbers
Understanding the domain of a function is crucial because it sets the stage for discussing other key concepts like the range and function relationships.
Range of a Function
The range of a function is closely related to its domain but focuses on the output values rather than the input values. The range of a function, denoted as \( f \), is the set of all possible output values (y-values) that the function can produce.
Consider the function \( f(x) = x^2 \). No matter what real number we input into this function, the output (y-value) will always be a non-negative number. So, the range of \( f(x) = x^2 \) is all non-negative real numbers.
To find the range of a function, you need to manipulate and analyze the function to see what outputs are possible for all allowable inputs (the domain). In some cases, you may need to solve for x in terms of y to find the explicit range.
Understanding the range of a function helps provide a complete picture of how the function behaves and what values it can produce when fed with allowable inputs.
Function Relationships
Function relationships are essential for understanding how different functions interact with each other, especially when considering inverse functions. The inverse of a function, denoted as \( f^{-1} \), essentially swaps the roles of inputs and outputs.
This swapping of roles means that the domain of the original function becomes the range of its inverse, and the range of the original function becomes the domain of its inverse.
For example, let's say we have a function \( f(x) \) with a domain [1,5] and a range [2,6]. The inverse function \( f^{-1}(x) \) will have a domain [2,6] and a range [1,5].
This relationship is crucial for solving problems related to function and inverse function properties, as it provides a way to transition between the two. By mastering function relationships, you will be better equipped to understand more complex concepts in calculus and higher-level math.

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Most popular questions from this chapter

The amount of medication still available in the system is given by the function $$ f(t)=200(0.90)^{t} $$ In this model, \(t\) is in hours and \(f(t)\) is in milligrams. How long will it take for this initial dose to reach the dangerously low level of \(50 \mathrm{mg} ?\) Population Size Many environmental situations place effective limits on the growth of the number of an organism in an area. Many such limited-growth situations are described by the logistic function $$ G(x)=\frac{M G_{0}}{G_{0}+\left(M-G_{0}\right) e^{-k M x}} $$ where \(G_{0}\) is the initial number present, \(M\) is the maximum possible size of the population, and \(k\) is a positive constant. The screens illustrate a typical logistic function calculation and graph. (Graph can't copy) Assume that \(G_{0}=100, M=2500, k=0.0004,\) and \(x=\) time in decades ( \(10-\) yr periods). (a) Use a calculator to graph the function, using \(0 \leq x \leq 8,0 \leq y \leq 2500\) (b) Estimate the value of \(G(2)\) from the graph. Then evaluate \(G(2)\) algebraically to find the population after 20 yr. (c) Find the \(x\) -coordinate of the intersection of the curve with the horizontal line \(y=1000\) to estimate the number of decades required for the population to reach \(1000 .\) Then solve \(G(x)=1000\) algebraically to obtain the exact value of \(x .\)

Explain the error in the following "proof" that \(2<1\). $$\begin{aligned}\frac{1}{9} &<\frac{1}{3} \\\\\left(\frac{1}{3}\right)^{2} &<\frac{1}{3} \\ \log \left(\frac{1}{3}\right)^{2} &<\log \frac{1}{3} \\\2 \log \frac{1}{3} &<1 \log \frac{1}{3} \\ 2 &<1\end{aligned}$$

(Modeling) Solve each problem. See Example 11 . Atmospheric Pressure The atmospheric pressure (in millibars) at a given altitude (in meters) is shown in the table. $$\begin{array}{c|c||c|c} \hline \text { Altitude } & \text { Pressure } & \text { Altitude } & \text { Pressure } \\ \hline 0 & 1013 & 6000 & 472 \\ \hline 1000 & 899 & 7000 & 411 \\ \hline 2000 & 795 & 8000 & 357 \\ \hline 3000 & 701 & 9000 & 308 \\ \hline 4000 & 617 & 10,000 & 265 \\ \hline 5000 & 541 & & \\ \hline \end{array}$$ (a) Use a graphing calculator to make a scatter diagram of the data for atmospheric pressure \(P\) at altitude \(x\). (b) Would a linear or an exponential function fit the data better? (c) The function $$ P(x)=1013 e^{-0.0001341 x} $$ approximates the data. Use a graphing calculator to graph \(P\) and the data on the same coordinate axes. (d) Use \(P\) to predict the pressures at \(1500 \mathrm{m}\) and \(11,000 \mathrm{m},\) and compare them to the actual values of 846 millibars and 227 millibars, respectively.

Concept Check Use properties of exponents to write each function in the form \(f(t)=k a^{\prime},\) where \(k\) is a constant. (Hint: Recall that \(a^{x+y}=a^{x} \cdot a^{y}\).) $$f(t)=2^{3 t+2}$$

Work each problem. Which of the following is equivalent to \(2 \ln (3 x)\) for \(x>0 ?\) A. \(\ln 9+\ln x\) B. \(\ln (6 x)\) C. \(\ln 6+\ln x\) D. \(\ln \left(9 x^{2}\right)\)

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