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Concept Check Use properties of exponents to write each function in the form \(f(t)=k a^{\prime},\) where \(k\) is a constant. (Hint: Recall that \(a^{x+y}=a^{x} \cdot a^{y}\) ) $$f(t)=\left(\frac{1}{2}\right)^{1-2 t}$$

Short Answer

Expert verified
The function is \(f(t) = \frac{1}{2} \cdot 2^{2t}\).

Step by step solution

01

Rewrite the exponent

First, we need to rewrite the exponent in the given function. Notice that the exponent can be expressed as a difference of two terms: \[ f(t) = \bigg(\frac{1}{2}\bigg)^{1-2t} \] This can be rewritten using the exponent addition property as follows: \[ f(t)= \bigg(\frac{1}{2}\bigg)^1 \cdot \bigg(\frac{1}{2}\bigg)^{-2t} \]
02

Simplify the expression

Next, simplify the expression. Remember that \(\bigg(\frac{1}{2}\bigg)^1 = \frac{1}{2}\): \[ f(t) = \frac{1}{2} \cdot \bigg(\frac{1}{2}\bigg)^{-2t} \]
03

Simplify the negative exponent

To simplify the term \(\bigg(\frac{1}{2}\bigg)^{-2t}\), recall that a negative exponent indicates a reciprocal: \[ \bigg(\frac{1}{2}\bigg)^{-2t} = 2^{2t} \] Now substitute this back into the function: \[ f(t) = \frac{1}{2} \cdot 2^{2t} \]
04

Combine constants

Combine the constant \(\frac{1}{2}\) with the exponent term: \[ f(t) = \frac{1}{2} \cdot 2^{2t} \] We can write this as: \[ k = \frac{1}{2}, \, a = 2 \] Hence, the function is: \[ f(t) = \frac{1}{2} \cdot 2^{2t} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponent Rules
Exponent rules are essential tools in mathematics that help simplify expressions involving exponents. The primary rules include:
  • Product Rule: \( a^m \times a^n = a^{m+n} \) - When multiplying like bases, add their exponents.
  • Quotient Rule: \( \frac{a^m}{a^n} = a^{m-n} \) - When dividing like bases, subtract the exponents.
  • Power Rule: \( (a^m)^n = a^{mn} \) - When raising a power to another power, multiply the exponents.
  • Zero Exponent Rule: \(a^0 = 1\) - Any number raised to the power of zero is one, provided \( a \) is not zero.
  • Negative Exponent Rule: \( a^{-m} = \frac{1}{a^m} \) - A negative exponent indicates the reciprocal of the base.
Understanding these rules is crucial for solving problems involving exponents effectively. For example, in the given solution, we use the property \( a^{x+y} = a^x \times a^y \) to rewrite the original expression.
Simplifying Expressions
Simplifying expressions with exponents often involves combining like terms and following the exponent rules. Let's break down the process used in the example:
1. Rewrite the exponent: Identify how to break down the exponent using addition or subtraction. This step leverages the rule \( a^{x+y} = a^x \times a^y \).
2. Simplify known values: For instance, \( \bigg(\frac{1}{2}\bigg)^1 = \frac{1}{2} \). Simplifying these constants helps in further steps.
3. Handle the negative exponent: Understanding that a negative exponent signals a reciprocal is key. This use of the negative exponent property allows us to easily transform \( \bigg(\frac{1}{2}\bigg)^{-2t} \) into \( 2^{2t} \).
Following these minor yet systematic steps can demystify the process of simplifying exponential expressions. This approach ensures you don’t miss any critical steps while simplifying.
Negative Exponents
Negative exponents might seem tricky, but they're actually straightforward once you grasp their meaning. A negative exponent indicates that the base should be taken as a reciprocal. For example, \( a^{-m} = \frac{1}{a^m} \). Let's see this in action with our example:
  • We start with \( \bigg(\frac{1}{2}\bigg)^{-2t} \).
  • Applying the negative exponent rule, it becomes \( 2^{2t} \), since \( \frac{1}{\bigg(\frac{1}{2}\bigg)^{2t}} = \bigg(\frac{2}{1}\bigg)^{2t} = 2^{2t} \).
This transformation is vital for converting complex expressions into a simpler, more manageable form. By fully understanding the negative exponent rule, you’ll be well equipped to handle challenging expressions and make your simplifying process smoother.

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Most popular questions from this chapter

Growth of Bacteria The growth of bacteria makes it necessary to time-date some food products so that they will be sold and consumed before the bacteria count is too high. Suppose for a certain product the number of bacteria present is given by $$ f(t)=500 e^{0.1 t} $$ where \(t\) is time in days and the value of \(f(t)\) is in millions. Find the number of bacteria present at each time. (a) 2 days (b) 4 days (c) 1 week

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=x^{3}+1$$

For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form \(y=f^{-1}(x),\) (b) graph \(f\) and \(f^{-1}\) on the same axes, and \((c)\) give the domain and the range of \(f\) and \(f^{-1}\). If the function is not one-to-one, say so. $$f(x)=-6 x-8$$

Use the definition of inverses to determine whether \(f\) and \(g\) are inverses. $$f(x)=\frac{-1}{x+1}, \quad g(x)=\frac{1-x}{x}$$

Deer Population The exponential growth of the deer population in Massachusetts can be calculated using the model $$ f(x)=50,000(1+0.06)^{x} $$ where \(50,000\) is the initial deer population and 0.06 is the rate of growth. \(f(x)\) is the total population after \(x\) years have passed. (a) Predict the total population after 4 yr. (b) If the initial population was \(30,000\) and the growth rate was \(0.12,\) approximately how many deer would be present after 3 yr? (c) How many additional deer can we expect in 5 yr if the initial population is \(45,000\) and the current growth rate is \(0.08 ?\) (IMAGE CANT COPY)

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