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Express \(f(x)\) in the form \(f(x)=(x-k) q(x)+r\) for the given value of \(k\). $$f(x)=3 x^{4}+4 x^{3}-10 x^{2}+15 ; k=-1$$

Short Answer

Expert verified
f(x) = (x + 1)(3x^3 + x^2 - 11x + 11) + 4

Step by step solution

01

Identify the polynomial and the value of k

The given polynomial is \( f(x) = 3x^4 + 4x^3 - 10x^2 + 15 \), and the value of \( k \) is \( -1 \).
02

Set up polynomial division

We need to divide the polynomial \( f(x) \) by \( x - (-1) \) or \( x + 1 \). Use synthetic division with \( k = -1 \).
03

Perform synthetic division

Write down the coefficients of the polynomial: \( 3, 4, -10, 0, 15 \). Perform synthetic division:\[\begin{array}{r|rrrrr}-1 & 3 & 4 & -10 & 0 & 15 \ & & -3 & -1 & 11 & -11 \hline & 3 & 1 & -11 & 11 & 4 \end{array}\]The quotient \( q(x) \) is \( 3x^3 + x^2 - 11x + 11 \), and the remainder \( r \) is \( 4 \).
04

Write the polynomial in the desired form

Using the results from the synthetic division, express \( f(x) \) as:\[ f(x) = (x + 1) (3x^3 + x^2 - 11x + 11) + 4 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Synthetic Division
Synthetic division is a simplified method for dividing polynomials. It's especially useful when dividing by a linear factor of the form \(x - k\). Instead of performing long polynomial division, we use coefficients and a simpler set of rules, making the process quicker and easier.
Here's a quick run-through of the steps involved:
  • Write down the coefficients of the polynomial. If any degree is missing, use a coefficient of 0 for that term.
  • Set up a grid where the top row contains the value of \(k\) and the coefficients arranged in sequence.
  • Bring down the leading coefficient to the bottom row as is.
  • Multiply this coefficient by \(k\) and write the result under the next coefficient in the top row.
  • Add this result to the coefficient directly above it and write the sum in the bottom row.
  • Repeat until you have processed all coefficients.
The bottom row will give the coefficients of the quotient polynomial \(q(x)\), and the last number will be the remainder \(r\). This method is particularly efficient and minimizes the chances of error. In our example, for the polynomial \(3x^4 + 4x^3 - 10x^2 + 15\) divided by \(x - (-1) = x + 1\), we used synthetic division to find that \(q(x) = 3x^3 + x^2 - 11x + 11\) and \(r = 4\).
Remainder Theorem
The Remainder Theorem provides a quick way to find the remainder of a polynomial division. Specifically, it states that for any polynomial \(f(x)\) divided by \(x - k\), the remainder of this division is \(f(k)\).
In simpler terms, if we were to substitute \(k\) into the polynomial and calculate the result, we would obtain the same value as if we had performed the entire division and looked at the remainder.
For our problem:
  • We have the polynomial \(f(x) = 3x^4 + 4x^3 - 10x^2 + 15\) and \(k = -1\).
  • According to the Remainder Theorem, the remainder is \(f(-1)\).
  • Substituting \(-1\) into \(f(x)\):
\[ f(-1) = 3(-1)^4 + 4(-1)^3 - 10(-1)^2 + 15 = 3 - 4 - 10 + 15 = 4 \]
Indeed, this matches the remainder we obtained through synthetic division, confirming our results.
Factoring Polynomials
Factoring polynomials is crucial for solving polynomial equations and simplifying expressions. A polynomial like \(f(x)\) can often be broken down into simpler polynomials that, when multiplied together, give the original polynomial. This can reveal important features like roots and help in polynomial long division.
In practice, to factor a polynomial:
  • Identify any common factors and factor them out.
  • Use patterns such as difference of squares, perfect square trinomials, or sum/difference of cubes to simplify.
  • For higher degree polynomials, polynomial division or synthetic division can be used to further reduce and factor them.
In our example, after using synthetic division, we saw that \(f(x)\) could be expressed as: \[ f(x) = (x + 1)(3x^3 + x^2 - 11x + 11) + 4 \] This decomposition allows a deeper understanding of the polynomial’s structure and lays the foundation for solving \(f(x) = 0\) by finding roots of the factored parts. Although fully factoring \(3x^3 + x^2 - 11x + 11\) isn't required here, recognizing this form is already useful.

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