Chapter 2: Problem 54
Graph the line passing through the given point and having the indicated slope. Plot two points on the line. $$\text { through }(-2,-3), m=-\frac{3}{4}$$
Short Answer
Expert verified
Plot points (-2, -3), (0, -\frac{9}{2}), and (4, -\frac{15}{2}) on the graph.
Step by step solution
01
- Understand the Slope-Point Form
The slope-point form of a line's equation is: \( y - y_1 = m (x - x_1) \), where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope.
02
- Substitute the Given Values
Substitute the point \( (-2, -3) \) and the slope \( m = -\frac{3}{4} \) into the slope-point form equation: \( y - (-3) = -\frac{3}{4} (x - (-2)) \).
03
- Simplify the Equation
Simplify the equation from Step 2: \( y + 3 = -\frac{3}{4}(x + 2) \).
04
- Convert to Slope-Intercept Form
Distribute \( -\frac{3}{4} \) and solve for \( y \): \( y + 3 = -\frac{3}{4}x - \frac{3}{2} \). Subtract 3 from both sides to get: \( y = -\frac{3}{4}x - \frac{3}{2} - 3 \). Simplify: \( y = -\frac{3}{4}x - \frac{9}{2} \).
05
- Identify Two Points on the Line
Use the equation \( y = -\frac{3}{4}x - \frac{9}{2} \). Choose \( x \rightarrow 0 \) to find one point: When \( x = 0 \), \( y = -\frac{9}{2} \), so the point is \( (0, -\frac{9}{2}) \). Choose \( x \rightarrow 4 \) for the second point: When \( x = 4 \), \( y = -\frac{3}{4}(4) - \frac{9}{2} \), resulting in \( y = -3 - \frac{9}{2} \), so the point is \( (4, -\frac{15}{2}) \).
06
- Plot the Points on Graph
Plot the points \( (-2, -3) \), \( (0, -\frac{9}{2}) \), and \( (4, -\frac{15}{2}) \) on a coordinate plane and draw the line passing through them.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
slope-point form
The slope-point form is an efficient way to write the equation of a line when you know a point on the line and its slope. In this form, the equation is written as: \( y - y_1 = m (x - x_1) \). Here,
- \( (x_1, y_1) \) is a specific point on the line.
- \( m \) is the slope of the line.
slope-intercept form
To graph a linear equation, it can be practical to use the slope-intercept form, which is \( y = mx + b \). In this form:
- \( m \) is the slope.
- \( b \) is the y-intercept (the value of y when x is 0).
finding points on a line
Once you have a line's equation in slope-intercept form (\( y = -\frac{3}{4}x - \frac{9}{2} \)), you can find specific points on the line by substituting values for \( x \) and solving for \( y \). Let's start with \( x = 0 \): When \( x = 0 \rightarrow y = -\frac{9}{2} \). The point \( (0, -\frac{9}{2}) \) is on the line.Now, let’s choose another \( x \) value, say 4: When \( x = 4 \rightarrow y = -\frac{3}{4}(4) - \frac{9}{2} = -3 - \frac{9}{2} \rightarrow y = -\frac{15}{2} \). So, \( (4, -\frac{15}{2}) \) is another point on the line.By substituting different \( x \) values, you can find corresponding \( y \) values and thus, more points on the line.
coordinate plane
A coordinate plane is a two-dimensional surface where we can plot points, lines, and curves to visualize mathematical concepts. It is made up of two perpendicular number lines: the x-axis and the y-axis.
- The horizontal line is called the x-axis.
- The vertical line is the y-axis.