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91Ó°ÊÓ

Let \(f(x)=x^{2}+3\) and \(g(x)=-2 x+6 .\) Find each of the following. $$(f g)(4)$$

Short Answer

Expert verified
(fg)(4) = 7

Step by step solution

01

- Evaluate g(4)

First, find the value of the function g at x = 4. Given: \[ g(x) = -2x + 6 \] Plug in x = 4: \[ g(4) = -2(4) + 6 \] Simplify: \[ g(4) = -8 + 6 \] \[ g(4) = -2 \]
02

- Evaluate f(-2)

Next, use the value of g(4) found in Step 1 to find the value of the function f at this result. Given: \[ f(x) = x^{2} + 3 \] Since g(4) = -2, plug in x = -2: \[ f(-2) = (-2)^{2} + 3 \] Simplify: \[ f(-2) = 4 + 3 \] \[ f(-2) = 7 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

f(x)=x^2+3

In this section, we look at the function \( f(x) = x^2 + 3 \).

Functions describe how inputs are transformed into outputs. Here, \( f(x) \) takes any number \( x \) and squares it first. Then, it adds 3 to the squared result.

Let's break it down step by step:
  • Take the input \( x \).
  • Square \( x \) to obtain \( x^2 \).
  • Add 3 to \( x^2 \) to get the final result.

Example: Let's evaluate \( f(2) \).
  • First, we calculate \( 2^2 \), which equals 4.
  • Next, we add 3 to 4, which gives us 7.
So, \( f(2) = 7 \).

This function shows us a quadratic relationship, meaning the outputs grow faster as our inputs get larger.
g(x)=-2x+6

The function \( g(x) = -2x + 6 \) has a different structure. Here’s how we can break it down:
  • First, take the input \( x \).
  • Multiply it by -2.
  • Add 6 to the product.

This is a linear function, which means its graph is a straight line. Each step multiplies \( x \) by a negative number (-2), causing the line to slope downward as \( x \) increases.

Example: Let's evaluate \( g(3) \):
  • First, multiply 3 by -2. This results in -6.
  • Next, add 6 to -6. This gives us 0.
So, \( g(3) = 0 \).

Linear functions increase or decrease at a constant rate.
evaluate functions

To evaluate functions, we substitute the input value into the function and perform the operations. Let's use the original exercise:

1. Evaluate \( g(4) \):
- Given \( g(x) = -2x + 6 \), substitute \( x = 4 \).
  • \( g(4) = -2(4) + 6 = -8 + 6 = -2 \)

So, \( g(4) = -2 \).

2. Evaluate \( f(-2) \) using the result of \( g(4) \):
- Given \( f(x) = x^2 + 3 \), substitute \( x = -2 \).
  • \( f(-2) = (-2)^2 + 3 = 4 + 3 = 7 \)

So, \( f(-2) = 7 \).

This illustrates how you can combine functions and use the result of one as the input for another.

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