/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A population of fruit flies is g... [FREE SOLUTION] | 91Ó°ÊÓ

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A population of fruit flies is growing in such a way that each generation is 1.25 times as large as the last generation. Suppose there were 200 insects in the first generation. How many would there be in the fifth generation?

Short Answer

Expert verified
There would be approximately 488 insects in the fifth generation.

Step by step solution

01

Identify Given Values

Identify and list the given values in the problem. The initial population (first generation) is 200 insects, and the growth factor per generation is 1.25.
02

Define the Formula

Define the formula for population growth over successive generations. Use the formula for geometric progression: \[ P_n = P_0 \times r^{n-1} \] where \( P_n \) is the population at the n-th generation, \( P_0 \) is the initial population, \( r \) is the growth factor, and \( n \) is the generation number.
03

Substitute Known Values

Substitute the known values into the formula. For the fifth generation (\( n = 5 \)), the initial population (\( P_0 = 200 \)), and the growth factor (\( r = 1.25 \)), the formula becomes: \[ P_5 = 200 \times 1.25^{5-1} \]
04

Calculate the Exponential Term

Calculate the exponential term \( 1.25^{4} \). Using a calculator: \[ 1.25^4 \ = 1.25 \times 1.25 \times 1.25 \times 1.25 \ \ = 2.44140625 \]
05

Compute the Final Population

Multiply the initial population by the calculated growth factor: \[ P_5 = 200 \times 2.44140625 \ = 488.28125 \] Since population counts are typically whole numbers, round to the nearest whole number: \( P_5 \approx 488 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Growth
Population growth refers to the increase in the number of individuals in a population. It can be influenced by factors like birth rates, death rates, immigration, and emigration. Understanding how populations grow is crucial in many fields like biology, environmental science, and economics.

In mathematical terms, population growth can often be modeled using geometric progression. This is particularly useful when each generation grows by a constant factor. In the given exercise, the fruit fly population grows by a factor of 1.25 each generation. This type of growth is predictable and allows us to calculate future populations given an initial starting point and a constant growth rate.

This kind of modeling can help scientists predict and manage real-world populations more effectively.
Exponential Growth
Exponential growth occurs when a quantity increases by a consistent percentage over equal intervals of time. It is characterized by the formula \[ y = a \times b^x \], where:
  • a is the initial quantity,
  • b is the growth factor,
  • x is the number of time intervals.

In the problem of the fruit fly population, this growth is shown by the formula \[ P_n = P_0 \times r^{n-1} \], where \[ P_n \] is the population at the n-th generation, \[ P_0 \] is the initial population, and \[ r \] is the growth factor.

This means as generations pass, the population size increases exponentially. For the fruit flies, starting from 200 individuals and growing at a rate of 1.25 per generation, we can calculate the population at any future generation.

Exponential growth can rapidly increase the population size in a short time, reflecting real-life situations like bacteria growth, investments in finance, or even certain environmental phenomena.
Precalculus Problem Solving
Precalculus involves understanding and solving problems using algebraic and trigonometric concepts, often as preparation for calculus. For problems involving geometric progression and exponential growth, the steps are relatively straightforward but require precise calculation and understanding of formulas.

Here's a simple guide to solve similar problems:
  • Identify given values and the type of growth model.
  • Define the relevant formula, typically geometric progression for population growth problems.
  • Substitute the given values into the formula.
  • Calculate any exponential terms needed.
  • Compute the final value, rounding if necessary.

Practicing these steps enhances problem-solving skills and prepares students for more advanced topics in calculus. By working through these problems methodically, students build a strong foundation in mathematical reasoning and techniques. This is essential for higher-level math courses and real-world applications.

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Most popular questions from this chapter

The series $$x-\frac{x^{2}}{2}+\frac{x^{3}}{3}-\frac{x^{4}}{4}+\cdots$$ can be used to approximate the value of \(\ln (1+x)\) for values of \(x\) in \((-1,1] .\) Use the first six terms of this series to approximate each expression. Compare this approximation with the value obtained on a calculator. (a) \(\ln 1.02(x=0.02)\) (b) \(\ln 0.97(x=-0.03)\)

Assume that \(n\) is a positive integer. Use mathematical induction to prove each statement S by following these steps. See Example \(I\). (a) Verify the statement for \(n=1\) (b) Write the statement for \(n=k\) (c) Write the statement for \(n=k+1\) (d) Assume the statement is true for \(n=k\). Use algebra to change the statement in part (b) to the statement in part (c). (e) Write a conclusion based on Steps (a)-(d). $$3+6+9+\dots+3 n=\frac{3 n(n+1)}{2}$$

The table gives the results of a 2008 survey of Americans aged \(18-24\) in which the respondents were asked, "During the past 30 days, for about how many days have you felt that you did not get enough sleep?"$$\begin{array}{|l|c|c|c|c|}\hline \text { Number of Days } & 0 & 1-13 & 14-29 & 30 \\ \hline \text { Percent (as a decimal) } & 0.23 & 0.45 & 0.20 & 0.12 \\\\\hline\end{array}$$ Using the percents as probabilities, find the probability that, out of 10 respondents in the \(18-24\) age group selected at random, the following were true. Fewer than 2 did not get enough sleep on 14 or more days.

Work each problem.One game in a state lottery requires you to pick 1 heart, 1 club, 1 diamond, and 1 spade, in that order, from the 13 cards in each suit. What is the probability of getting all four picks correct and winning \(\$ 5000 ?\)

Male Life Table The table is an abbreviated version of the 2006 period life table used by the Office of the Chief Actuary of the Social Security Administration. (The actual table includes every age, not just every tenth age.) Theoretically, this table follows a group of \(100,000\) males at birth and gives the number still alive at each age.$$\begin{array}{c|c||c|c}\hline \text { Exact Age } & \text { Number of Lives } & \text { Exact Age } & \text { Number of Lives } \\\\\hline 0 & 100,000 & 60 & 85,026 \\\\\hline 10 & 99,067 & 70 & 71,586 \\\\\hline 20 & 98,519 & 80 & 47,073 \\\\\hline 30 & 97,079 & 90 & 15,051 \\ \hline 40 & 95,431 & 100 & 657 \\\\\hline 50 & 92,041 & 110 & 1 \\\\\hline\end{array}$$ (a) What is the probability that a 40 -year-old man will live 30 more years? (b) What is the probability that a 40 -year-old man will not live 30 more years? (c) Consider a group of five 40 -year-old men. What is the probability that exactly three of them survive to age \(70 ?\) (Hint: The longevities of the individual men can be considered as independent trials.) (d) Consider two 40 -year-old men. What is the probability that at least one of them survives to age \(70 ?\) (Hint: The complement of at least one is none.)

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