Chapter 11: Problem 30
Evaluate each series. $$\sum_{i=1}^{6}(3 i-2)$$
Short Answer
Expert verified
The sum is 51.
Step by step solution
01
- Understand the Series
The given series is \(\sum_{i=1}^{6}(3i-2)\). This means you need to find the sum of the expression \(3i-2\) from \(i=1\) to \(i=6\).
02
- Write Out the Terms
Substitute the values from \(i=1\) to \(i=6\) into the expression \(3i-2\): \( (3(1)-2), (3(2)-2), (3(3)-2), (3(4)-2), (3(5)-2), (3(6)-2) \).
03
- Calculate Each Term
Calculate each term individually: \(3(1)-2 = 1, 3(2)-2 = 4, 3(3)-2 = 7, 3(4)-2 = 10, 3(5)-2 = 13, 3(6)-2 = 16 \).
04
- Add Up the Terms
Sum the calculated terms: \(1 + 4 + 7 + 10 + 13 + 16 \).
05
- Find the Total
Compute the total: \(1 + 4 + 7 + 10 + 13 + 16 = 51 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arithmetic Series
An arithmetic series is a sequence of numbers in which each term after the first is obtained by adding a constant difference to the preceding term. This difference is known as the common difference. In our exercise, the expression given is \(3i-2\), and it changes linearly with each increment of i.
To illustrate, let’s break down the provided example: \(3(1)-2 = 1\), \(3(2)-2 = 4\), \(3(3)-2 = 7\), and so on. Notice how there is a constant difference of 3 between consecutive terms (4 - 1, 7 - 4, etc.).
So, in an arithmetic series:
To illustrate, let’s break down the provided example: \(3(1)-2 = 1\), \(3(2)-2 = 4\), \(3(3)-2 = 7\), and so on. Notice how there is a constant difference of 3 between consecutive terms (4 - 1, 7 - 4, etc.).
So, in an arithmetic series:
- Each term increases (or decreases) by a fixed amount, called the common difference (d).
- This pattern continues uniformly to form the entire series.
Finite Series
A finite series is a series that has a limited number of terms. In the given exercise, we are dealing with a finite series because we have to find the sum from \(i=1\) to \(i=6\). This automatically limits the series to 6 terms.
Finite series are easier to evaluate because they do not go on indefinitely. To evaluate a finite series, follow these steps:
Finite series are easier to evaluate because they do not go on indefinitely. To evaluate a finite series, follow these steps:
- Identify the expression or sequence to be summed.
- Determine the range of terms (e.g., from 1 to 6).
- Compute each term in the given range.
- Sum up all these computed terms.
Series Evaluation
Series evaluation involves calculating the sum of a sequence of terms systematically. To evaluate the series given in the problem \(\sum_{i=1}^{6}(3i-2)\), you can follow a step-by-step approach.
- Start by understanding the series: Identify the general formula or rule of the series, in this case, \(3i-2\).
- Next, write out the terms: Substitute each value of \(i\) from the range 1 to 6 into the formula to get the individual terms: \(1, 4, 7, 10, 13, 16\).
- Calculate each term individually to ensure accuracy.
- Finally, sum these terms: Add up all the terms \(1 + 4 + 7 + 10 + 13 + 16\).