Chapter 10: Problem 27
Find the eccentricity of each hyperbola to the nearest tenth. $$\frac{x^{2}}{8}-\frac{y^{2}}{8}=1$$
Short Answer
Expert verified
The eccentricity of the hyperbola is approximately 1.4.
Step by step solution
01
Identify the Standard Form
The given equation is \(\frac{x^{2}}{8}-\frac{y^{2}}{8}=1\). This matches the standard form of a hyperbola, \(\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1\). Here, \(a^{2} = 8\) and \(b^{2} = 8\).
02
Determine the Values of a and b
Since \(a^{2} = 8\), we find \(a = \sqrt{8} \approx 2.8\). Similarly, since \(b^{2} = 8\), we find \(b = \sqrt{8} \approx 2.8\).
03
Find the Value of c
Use the relationship \(c^{2} = a^{2} + b^{2}\) for hyperbolas. Substituting the given values, \(c^{2} = 8 + 8 = 16\), so \(c = \sqrt{16} = 4\).
04
Calculate the Eccentricity
Eccentricity is given by \(e = \frac{c}{a}\). Substituting \(c = 4\) and \(a \approx 2.8\), we find \(e = \frac{4}{2.8} \approx 1.4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbola Equations
A hyperbola is a type of conic section formed by intersecting a double cone with a plane. The standard forms of hyperbola equations differ based on their orientation. For hyperbolas oriented horizontally, the standard form is \(\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1\). If the hyperbola is oriented vertically, the standard form is \(\frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1\). Both forms describe the relationship between the distances from any point on the hyperbola to the foci and the center.
In our given exercise, the equation is \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\). This matches the standard form of a horizontally oriented hyperbola. Here, \(a^{2} = 8\) and \(b^{2} = 8\). Understanding the structure of these equations helps in finding key properties like the semi-major axis \(a\), the semi-minor axis \(b\), and the distance between the center and its vertices (along \(x\) or \(y\)-axis).
In our given exercise, the equation is \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\). This matches the standard form of a horizontally oriented hyperbola. Here, \(a^{2} = 8\) and \(b^{2} = 8\). Understanding the structure of these equations helps in finding key properties like the semi-major axis \(a\), the semi-minor axis \(b\), and the distance between the center and its vertices (along \(x\) or \(y\)-axis).
Eccentricity Calculation
Eccentricity is one of the essential characteristics of a hyperbola, denoted by \(e\). It measures how much the shape of the hyperbola deviates from being a circle. The formula for eccentricity in a hyperbola is given by \(e = \frac{c}{a}\), where \(c\) is the distance from the center to the foci, and \(a\) is the semi-major axis.
To find \(c\), we use the relationship \(c^{2} = a^{2} + b^{2}\). From our given equation \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\), we determined that \(a^{2} = 8\) and \(b^{2} = 8\). Thus, \(c^{2} = 8 + 8 = 16\), and \(c = \frac{16}{c} = 4\).
Finally, substituting \(c\) and \(a\) into our eccentricity formula, we get \(e = \frac{4}{\frac{√(8)}{2}} ≈ 1.4\). This means that the eccentricity of our hyperbola is approximately 1.4.
To find \(c\), we use the relationship \(c^{2} = a^{2} + b^{2}\). From our given equation \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\), we determined that \(a^{2} = 8\) and \(b^{2} = 8\). Thus, \(c^{2} = 8 + 8 = 16\), and \(c = \frac{16}{c} = 4\).
Finally, substituting \(c\) and \(a\) into our eccentricity formula, we get \(e = \frac{4}{\frac{√(8)}{2}} ≈ 1.4\). This means that the eccentricity of our hyperbola is approximately 1.4.
Standard Form of Hyperbola
The standard form of a hyperbola is crucial in understanding its geometric properties and solving related problems. A hyperbola's standard form can be written in two typical ways, depending on its orientation:
Knowing how to identify the standard form helps to find the values of \(a\), \(b\), and \(c\).
In our exercise, we have the equation \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\). This is in the form of a horizontally oriented hyperbola, where both \(a^{2}\) and \(b^{2}\) are equal to 8. Therefore, \(a = \frac{√8}{2} = 2.8\) and \(b\) is equal to 2.8.
Understanding this form allows us to easily derive other properties of the hyperbola, such as its eccentricity, which we calculated as approximately 1.4.
- Horizontal Hyperbola: \(\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1\).
- Vertical Hyperbola: \(\frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1\).
Knowing how to identify the standard form helps to find the values of \(a\), \(b\), and \(c\).
In our exercise, we have the equation \(\frac{x^{2}}{8} - \frac{y^{2}}{8} = 1\). This is in the form of a horizontally oriented hyperbola, where both \(a^{2}\) and \(b^{2}\) are equal to 8. Therefore, \(a = \frac{√8}{2} = 2.8\) and \(b\) is equal to 2.8.
Understanding this form allows us to easily derive other properties of the hyperbola, such as its eccentricity, which we calculated as approximately 1.4.