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91Ó°ÊÓ

$$\text {Give the focus, directrix, and axis of symmetry for each parabola.}$$ $$y=-4 x^{2}$$

Short Answer

Expert verified
Focus: \( \left( 0, -\frac{1}{16} \right) \), Directrix: \( y = \frac{1}{16} \), Axis of Symmetry: \( x = 0 \).

Step by step solution

01

Identify the Standard Form

The given equation is in the form of a parabola. The standard form for a vertical parabola is \[ y = ax^2 + bx + c \].Here, the equation is \[ y = -4x^2 \].
02

Compare with Standard Form

Compare the given equation with the standard form. Here, a = -4,b = 0,c = 0.
03

Determine the Value of 'a'

Identify the coefficient 'a' in the equation. In this case,\[ a = -4 \].
04

Find the Focus

For a vertical parabola, the focus (h, k + 1/(4a)) can be calculated. Here, h and k are both 0, and a = -4.So, the focus is \[ \left( 0, -\frac{1}{16} \right) \].
05

Find the Directrix

The directrix of a vertical parabola can be found using the formula \[ y = k - \frac{1}{4a} \].Here, k = 0. Therefore the directrix is \[ y = \frac{1}{16} \].
06

Find the Axis of Symmetry

The axis of symmetry for a vertical parabola is the line \[ x = h \]. Here, \[ h = 0 \]. Therefore, the axis of symmetry is \[ x = 0 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

focus of parabola
A parabola's focus is a special point located inside the curve. It plays a crucial role in defining the shape and properties of the parabola. To find the focus for a vertical parabola given in the form \[y = ax^2 + bx + c\], use the formula \[\left(h, k + \frac{1}{4a}\right)\]. Here, \((h, k)\) is the vertex of the parabola.
In our specific example, the equation is \[ y = -4x^2 \] which simplifies to the vertex form with \(h = 0\) and \(k = 0\). By identifying \(a = -4\), we can find the focus by substituting into our formula:
\[ \left( 0, -\frac{1}{16} \right) \].
This means the focus is positioned at \(0, -\frac{1}{16}\), inside the curve, guiding how the parabola opens and forms.
directrix of parabola
The directrix of a parabola is a line that lies outside the curve. It works together with the focus point to maintain the parabola's unique property: any point on the parabola is equidistant from the focus and the directrix.
For a vertical parabola, given in the form \[ y = ax^2 + bx + c \], the directrix can be found using the formula \[ y = k - \frac{1}{4a} \].
In our case, the parabola equation \[ y = -4x^2 \] has \(k = 0\) and \(a = -4\). Substituting these values, the directrix equation becomes
\[ y = \frac{1}{16} \].
This means the directrix is a horizontal line \[ y = \frac{1}{16} \], running parallel to the x-axis, and it assists in defining the shape and orientation of the parabola.
axis of symmetry
The axis of symmetry in a parabola is a vertical line that divides the parabola into two mirror-image halves. It passes through the vertex and ensures that every point on one side of the axis has a corresponding point on the other side.
For a vertical parabola given in the form \[ y = ax^2 + bx + c \], the axis of symmetry can be found using the formula \[ x = h \]. Here, \((h, k)\) refers to the vertex of the parabola.
For our given equation \[ y = -4x^2 \], we identify the vertex as \(h = 0\) and \(k = 0\). Therefore, the axis of symmetry is the vertical line
\[ x = 0 \].
This line runs through the vertex along the y-axis, ensuring the parabola is symmetrical on both sides.

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