/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 Evaluate the discriminant for ea... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the discriminant for each equation. Then use it to predict the number of distinct solutions, and whether they are rational, irrational, or non real complex. Do not solve the equation. $$2 x^{2}+4 x+1=0$$

Short Answer

Expert verified
The equation has two distinct irrational solutions.

Step by step solution

01

Identify coefficients

Identify the coefficients from the quadratic equation. For the equation 2x^2 + 4x + 1 = 0: a = 2, b = 4, c = 1.
02

Calculate the discriminant

Use the formula for the discriminant, D = b^2 - 4ac. Substitute the values for a, b, and c: D = 4^2 - 4 * 2 * 1.
03

Simplify the discriminant

Simplify the equation to find the value of the discriminant: D = 16 - 8 = 8.
04

Analyze the discriminant

Evaluate the discriminant to predict the number and type of solutions: Since D = 8 > 0, the quadratic equation has two distinct real solutions. Moreover, since the discriminant is not a perfect square, the solutions are irrational.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

quadratic equations
A quadratic equation is a polynomial equation of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(a eq 0\). This type of equation can describe a parabola in a graph and is fundamental in algebra. Quadratic equations can have different types of solutions, which we can predict using the discriminant. Let's explore how to do this in the context of the provided example: \(2x^2 + 4x + 1 = 0\).
discriminant
In the context of quadratic equations, the discriminant is a value that helps to determine the nature of the roots. It's calculated using the formula: \(D = b^2 - 4ac\). For the given equation (\(2x^2 + 4x + 1 = 0\)), we identify the coefficients as follows:
  • \(a = 2\)
  • \(b = 4\)
  • \(c = 1\)
By substituting these into the discriminant formula, we calculate: \(D = 4^2 - 4(2)(1)\), leading to: \(D = 16 - 8 = 8\). This value tells us important information about the nature of the solutions.
real solutions
Real solutions are the values for \(x\) that satisfy the quadratic equation and are real numbers, as opposed to imaginary or complex numbers. To determine the type of solutions, we can analyze the discriminant (\(D\)):
  • If \(D > 0\), there are two distinct real solutions.
  • If \(D = 0\), there is one real solution (a repeated root).
  • If \(D < 0\), there are no real solutions; instead, there are two complex solutions.
For \(2x^2 + 4x + 1 = 0\), since \(D = 8 > 0\), it has two distinct real solutions.
irrational solutions
Irrational solutions are real numbers that cannot be expressed as a simple fraction. They are typically expressed in terms of square roots. When the discriminant is a positive number that is not a perfect square (like 8 in our example), the roots of the quadratic equation are irrational. For \(2x^2 + 4x + 1 = 0\), since \(D = 8\) is positive but not a perfect square, the equation has two distinct irrational solutions. Understanding these aspects helps us predict the nature of the solutions without actually solving the equation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An astronaut on the moon throws a baseball upward. The astronaut is \(6 \mathrm{ft}, 6\) in. tall, and the initial velocity of the ball is \(30 \mathrm{ft}\) per sec. The height \(s\) of the ball in feet is given by the equation $$s=-2.7 t^{2}+30 t+6.5$$ where \(t\) is the number of seconds after the ball was thrown. (a) After how many seconds is the ball \(12 \mathrm{ft}\) above the moon's surface? Round to the nearest hundredth. (b) How many seconds will it take for the ball to return to the surface? Round to the nearest hundredth.

Solve each problem. Recycling Bin Dimensions A recycling bin is in the shape of a rectangular box. Find the height of the box if its length is \(18 \mathrm{ft}\), its width is \(8 \mathrm{ft}\), and its surface area is \(496 \mathrm{ft}^{2}\). ( In the figure, \(h=\) height. Assume that the given surface area includes that of the top lid of the box.)

A projectile is launched from ground level with an initial velocity of \(v_{0}\) feet per second. Neglecting air resistance, its height in feet \(t\) seconds after launch is given by $$s=-16 t^{2}+v_{0} t$$ Find the time(s) that the projectile will (a) reach a height of 80 \(\mathrm{ft}\). and (b) return to the ground for the given value of \(v_{0}\). Round answers to the nearest hundredth if necessary. $$v_{0}=16$$

A sewage treatment plant has two inlet pipes to its settling pond. One pipe can fill the pond 3 times as fast as the other pipe, and together they can fill the pond in 12 hr. How long will it take the faster pipe to fill the pond alone?

Unknown Numbers Consider the following problem. The difference between seven times a number and 9 is equal to five times the sum of the number and 2. Find the number. If \(x\) represents the number, which equation is correct for solving this problem? A. \(7 x-9=5(x+2)\) B. \(9-7 x=5(x+2)\) C. \(7 x-9=5 x+2\) D. \(9-7 x=5 x+2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.