/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Solve each equation. $$(2 x+5)... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each equation. $$(2 x+5)^{1 / 3}-(6 x-1)^{1 / 3}=0$$

Short Answer

Expert verified
\( x = \frac{3}{2} \)

Step by step solution

01

Isolate one of the cube roots

Start by isolating one of the cube roots in the equation \( (2x + 5)^{1/3} - (6x - 1)^{1/3} = 0 \) \( \Rightarrow (2x + 5)^{1/3} = (6x - 1)^{1/3} \)
02

Cube both sides

To eliminate the cube roots, cube both sides of the equation: \( [(2x + 5)^{1/3}]^3 = [(6x - 1)^{1/3}]^3 \) This simplifies to: \( 2x + 5 = 6x - 1 \)
03

Solve the linear equation

Now solve the linear equation for \(x\): \( 2x + 5 = 6x - 1 \) First, subtract \2x\ from both sides: \( 5 = 4x - 1 \) Then add \1\ to both sides: \( 6 = 4x \) Finally, divide both sides by \4\: \( x = \frac{6}{4} = \frac{3}{2} \)
04

Verify the solution

Substitute \( x = \frac{3}{2} \) back into the original equation to verify: \( (2(\frac{3}{2}) + 5)^{1/3} - (6(\frac{3}{2}) - 1)^{1/3} = 0 \) Simplifies to: \( (3 + 5)^{1/3} - (9 - 1)^{1/3} = 0 \) \( 8^{1/3} - 8^{1/3} = 0 \) \( 2 - 2 = 0 \) The solution is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

cube roots
A cube root of a number is a value that, when multiplied by itself three times, gives the original number. For example, the cube root of 8 is 2 because \(2 \times 2 \times 2 = 8\). In algebra, cube roots are often represented as \(a^{1/3}\) where 'a' is the number.
In the given problem, we have cube roots like \( (2x + 5)^{1/3}\) and \( (6x - 1)^{1/3}\). These represent the cube roots of the expressions inside the parentheses.
To solve equations involving cube roots, one method used is to ‘isolate’ one of the cube root terms. This means you'll try to get one of the cube root terms by itself on one side of the equation.
Once isolated, to clear the cube root, you can cube both sides of the equation. This means raising each side of the equation to the power of three because cubing a cube root will leave you with the original expression inside. For instance, in our exercise, \[ ( (2x + 5)^{1/3})^3 = ( (6x - 1)^{1/3})^3 \] simplifies to \[ 2x + 5 = 6x - 1 \].
linear equations
A linear equation is an equation between two variables that forms a straight line when plotted on a graph. The general form of a linear equation in one variable is \(ax + b = c\), where 'a', 'b', and 'c' are constants.
In the solved exercise, after cubing both sides of the equation to remove the cube roots, we are left with \(2x + 5 = 6x - 1\). This is a straightforward linear equation.
To solve it, we use basic algebraic operations:
  • Subtract 2x from both sides to find: \[ 5 = 4x - 1 \]
  • Next, add 1 to both sides: \[ 6 = 4x \]
  • Finally, divide both sides by 4 to isolate x: \[ x = \frac{6}{4} = \frac{3}{2} \]

So, solving linear equations generally involves isolating the variable on one side of the equation by using addition, subtraction, multiplication, or division.
verification of solutions
Verification of a solution means substituting the solution back into the original equation to check if it satisfies the equation.
This step ensures that no mistakes were made during solving.
In our example, after finding \ ( x = \frac{3}{2} )\, we substitute \(x\) back into the original equation \[ ( 2x+5 )^{1/3} - ( 6x-1 )^{1/3} = 0\]
Substitute \( x = \frac{3}{2}\): \[ ( 2(\frac{3}{2}) + 5 )^{1/3} - ( 6(\frac{3}{2}) - 1 )^{1/3} = 0 \]
Simplify within the cube roots: \[ ( 3 + 5 )^{1/3} - ( 9 - 1 )^{1/3} = 0 \] \[ 8^{1/3} - 8^{1/3} = 0 \] \[ 2 - 2 = 0 \]
The left-hand side equals the right-hand side, confirming that \( x = \frac{3}{2} \) is indeed the correct solution.

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Most popular questions from this chapter

When humans breathe, carbon dioxide is emitted. In one study, the emission rates of carbon dioxide by college students were measured during both lectures and exams. The average individual rate \(R_{L}\) (in grams per hour) during a lecture class satisfied the inequality $$\left|R_{L}-26.75\right| \leq 1.42,$$ whereas during an exam the rate \(R_{E}\) satisfied the inequality $$\left|R_{E}-38.75\right| \leq 2.17.$$ Use this information in Exercises. The class had 225 students. If \(T_{L}\) and \(T_{E}\) represent the total amounts of carbon dioxide in grams emitted during a one-hour lecture and exam, respectively, write inequalities that model the ranges for \(T_{L}\) and \(T_{E}\).

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Solve each equation or inequality. $$|3 x+2|>0$$

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