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Solve each formula for the indicated variable. Assume that the denominator is not 0 if variables appear in the denominator. See Examples \(4(a)\) and \((b)\). \(I=P r t, \quad\) for \(P \quad\) (simple interest)

Short Answer

Expert verified
P = \frac{I}{r t}.

Step by step solution

01

Understand the given formula

The given formula is the simple interest formula: \[I = P r t \].We need to solve this equation for the variable \(P\).
02

Isolate the Variable \(P\)

To isolate \(P\), we need to divide both sides of the equation by \(r t\). Divide both sides:\[ \frac{I}{r t} = \frac{P r t}{r t}.\]
03

Simplify the Equation

Simplify the right-hand side of the equation. Since \(r t\) in the numerator and denominator will cancel out, we have:\[ \frac{I}{r t} = P. \]
04

Write the Final Solution

The isolated variable \(P\) is: \[ P = \frac{I}{r t}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

solve for variable
Solving for a variable is an essential skill in precalculus and other mathematics areas. It involves finding the value of a specific variable in an equation.

The variable we want to solve for is often written on one side of the equation while the other side contains the rest of the equation's terms.

This requires systematically performing operations that will simplify and rearrange the equation until the desired variable is isolated.

For example, in the simple interest formula \(I = Prt\), we needed to solve for the variable \(P\).

To do this, we divided both sides of the equation by \(rt\) to isolate \(P\). This method ensures the equation remains balanced while isolating the target variable.
isolate variable
Isolating a variable means getting the variable alone on one side of the equation so we can see exactly what it equals.

In the simple interest formula example, our goal was to isolate \(P\).

Starting with \(I = Prt\), we performed the same operation on both sides: \(\frac{I}{rt} = \frac{Prt}{rt}\).

This operation canceled out \(rt\) on the right side, effectively isolating \(P\) and resulting in \(\frac{I}{rt} = P\).

This process of isolating variables is widely used not only in simple equations but also in more complex algebraic and calculus problems.
precalculus problem-solving
Precalculus problem-solving often involves techniques such as isolating variables and solving for them.

These foundations are crucial as they build toward understanding more complex mathematical concepts.

By practicing these skills, students develop strong analytical skills and a deeper understanding of algebra.

For instance, using the simple interest formula \(I = Prt\), we needed to isolate \(P\) to find its value depending on \(I\), \(r\), and \(t\).

This type of manipulation and simplification of equations is a core aspect of precalculus problem-solving and prepares students for advanced mathematics.

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