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Concept Check Match the inequality in each exercise in Column I with its equivalent interval notation in Column II. A. \((-2,6]\) B. \([-2,6)\) C. \((-\infty,-6]\) D. \([6, \infty)\) E. \((-\infty,-3) \cup(3, \infty)\) F. \((-\infty,-6)\) G. \((0,8)\) H. \((-\infty, \infty)\) I. \([-6, \infty)\) J. \(\quad(-\infty, 6]\) $$x \leq 6$$

Short Answer

Expert verified
J. \( (-\infty, 6] \)

Step by step solution

01

Identify the inequality

The given inequality is: \( x \leq 6 \). This means that \( x \) is less than or equal to 6.
02

Determine the interval notation

To express \( x \leq 6 \) in interval notation, note that it represents all values of \( x \) from negative infinity up to and including 6.
03

Match with Column II

The interval notation for \( x \leq 6 \) is \((-\infty, 6] \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interval Notation
Interval notation is a way of representing the set of all solutions to an inequality. It is a concise and visually clear method to display the range of possible values. An interval looks like a pair of numbers within either parentheses or brackets, separated by a comma.

Parentheses, \( ... )\), mean that the boundary numbers are not included in the set. Brackets, \[ ... ]\], mean the boundary numbers are included. For example:
  • \( (a, b) \rightarrow \text{a < x < b} \text{ (exclusive)} \)
  • \( [a, b] \rightarrow \text{a ≤ x ≤ b} \text{ (inclusive)} \)
  • \( (-\text{∞}, b) \rightarrow \text{x < b} \)
  • \( (a, \text{∞}) \rightarrow \text{a < x} \)
To understand how these notations work with inequalities, let's look at an example. The inequality \ x \leq 6 \ is written in interval notation as \( -\text{∞} ≤ x ≤ 6 ( -\text{∞}, 6 ]\). Since ∞ can never be reached, we always use a parenthesis with it.
Inequalities
Inequalities are mathematical expressions that show the relationship between two values. They tell us how one value is smaller or bigger than another. Here are the most common inequality symbols:
  • \textgreater \rightarrow greater than
  • \textless \rightarrow less than
  • \textgreater\textgreater= \rightarrow greater than or equal to
  • \textless= \rightarrow less than or equal to
For example, \( x < 4 \) means x is any number less than 4.

To solve inequalities, we use similar principles as with regular equations. However, when you multiply or divide by a negative number, you must reverse the inequality sign. For example, if we have \ -2x \geq 6\, when we divide by -2, the inequality flips and we get \ x \leq -3\. This is a key concept in understanding and solving inequalities.
Precalculus
Precalculus serves as a bridge between algebra and calculus. It includes a thorough understanding of the properties and applications of functions, complex numbers, and trigonometry. In the context of inequalities, precalculus often involves solving polynomial or rational inequalities and representing these solutions using interval notation.

One important aspect of precalculus is preparing students to understand limits and continuity, which are essential for calculus. Alongside the algebraic manipulations of inequalities, students will learn to analyze functions graphically and understand end behavior. This broader understanding helps solidify the concept of solutions represented in interval notation.

For instance, knowing how to solve \(x^2 - 4 > 0\) by factoring, testing intervals, and writing the solution in interval notation (in this case, \(-\text{∞}, -2) \cup (2, \text{∞})\) is crucial groundwork for the more complex topics encountered in calculus.

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Most popular questions from this chapter

If p units of an item are sold for \(x\) dollars per unit, the revenue is \(R=p x\). Use this idea to analyze the following problem. Number of Apartments Rented The manager of an 80-unit apartment complex knows from experience that at a rent of \(\$ 300,\) all the units will be full. On the average, one additional unit will remain vacant for each \(\$ 20\) increase in rent over \(\$ 300 .\) Furthermore, the manager must keep at least 30 units rented due to other financial considerations. Currently, the revenue from the complex is \(\$ 35,000 .\) How many apartments are rented? Suppose that \(x\) represents the number of \(\$ 20\) increases over \(\$ 300 .\) Represent the number of apartment units that will be rented in terms of \(x .\)

Which one of the following inequalities has solution set \((-\infty, \infty) ?\) A. \((x-3)^{2} \geq 0\) B. \((5 x-6)^{2} \leq 0\) C. \((6 x+4)^{2}>0\) D. \((8 x+7)^{2}<0\)

Solve each rational inequality. Write each solution set in interval notation. $$\frac{-6}{3 x-5} \leq 2$$

The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. \(^{2} .\) Find the lengths of the sides of the two squares.

Celsius and Fahrenheit Temperatures In the met- ric system of weights and measures, temperature is measured in degrees Celsius (" \(^{\circ}\) C) instead of degrees Fahrenheit \(\left(^{\circ} \mathrm{F}\right) .\) To convert between the two systems, we use the equations $$ C=\frac{5}{9}(F-32) \quad \text { and } \quad F=\frac{9}{5} C+32 $$ In each exercise, convert to the other system. Round answers to the nearest tenth of a degree if necessary. $$100^{\circ} \mathrm{F}$$

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