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Solve each equation by the zero-factor property. $$x^{2}-100=0$$

Short Answer

Expert verified
The solutions are \(x = -10\) and \(x = 10\).

Step by step solution

01

Set the equation to zero

For the zero-factor property, we need to set the equation equal to zero. Given: \(x^{2} - 100 = 0\).
02

Factor the quadratic expression

Recognize the equation as a difference of squares: \(x^{2} - 100 = (x + 10)(x - 10)\).
03

Apply the zero-factor property

Set each factor equal to zero: \(x + 10 = 0\) and \(x - 10 = 0\).
04

Solve each equation

Solve for \(x\) in both equations: \(x + 10 = 0\) gives \(x = -10\), and \(x - 10 = 0\) gives \(x = 10\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

factoring quadratic equations
Factoring quadratic equations is a method used to simplify the equation to make it easier to solve. A quadratic equation generally has the form: \[ ax^{2} + bx + c = 0 \] To factor the quadratic equation means to express it as a product of two binomials. For example, if we have \( x^{2} - 100 = 0 \), we can notice that this can be written as: \[ (x + 10)(x - 10) = 0 \]This is because the product of \( (x + 10) \) and \( (x - 10) \) results in \( x^{2} - 100 \) when expanded. Breaking down the equation to this form allows us to use the zero-factor property, which states that if the product of two factors is zero, at least one of the factors must be zero. This way, we can find the possible values of \( x \).
Remember, not every quadratic equation is as straightforward to factor, but recognizing patterns like the difference of squares can make the process easier.
difference of squares
The difference of squares is a special pattern that makes factoring simpler. It refers to expressions of the form: \[ a^{2} - b^{2} \] which can be factored into: \[ (a + b)(a - b) \] Notice how our original equation, \[ x^{2} - 100 = 0 \] fits this pattern, with \( a = x \) and \( b = 10 \). Recognizing that this is a difference of squares allows us to quickly rewrite it as: \[ (x + 10)(x - 10) = 0 \] This pattern is very useful for many algebra problems, so it's helpful to remember: any time you see a term squared minus another term squared, think \( difference of squares \)! This method simplifies equations and makes it easier to solve for the variable.
Segments like these are fundamental in learning how to tackle quadratic equations efficiently.
solving equations
Solving equations often involves isolating the variable by performing algebraic operations. In our example, after factoring the quadratic equation: \[ x^{2} - 100 = (x + 10)(x - 10) = 0 \], we use the zero-factor property. This property states: If the product of two numbers is zero, one or both of the numbers must be zero. Therefore, we set each factor equal to zero: \[ x + 10 = 0 \] and \[ x - 10 = 0 \]Solving these equations gives us the solutions: \[ x = -10 \] and \[ x = 10 \] These are the values of \( x \) that satisfy the original equation. By breaking down the problem into smaller, manageable steps, solving equations becomes more straightforward.
Solving equations might require different methods like factoring, using the quadratic formula, or completing the square, but the foundational principle remains: isolate the variable to find its value.

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Most popular questions from this chapter

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