/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Write the given vector in terms ... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the given vector in terms of \(\mathbf{i}\) and \(\mathbf{j}\). $$\mathbf{u}=\langle 0,-5\rangle$$

Short Answer

Expert verified
\( \mathbf{u} = -5\mathbf{j} \).

Step by step solution

01

Understand the Problem Statement

We are given the vector \( \mathbf{u} = \langle 0, -5 \rangle \) and we need to express it in terms of the unit vectors \( \mathbf{i} \) and \( \mathbf{j} \).
02

Using Unit Vectors \(\mathbf{i}\) and \(\mathbf{j}\)

Unit vectors are fundamental in vector notation. In 2D space, \( \mathbf{i} \) represents the unit vector along the x-axis and \( \mathbf{j} \) represents the unit vector along the y-axis. Thus, any vector \( \langle a, b \rangle \) can be written as \( a \mathbf{i} + b \mathbf{j} \).
03

Apply to \(\mathbf{u}\)

Given \( \mathbf{u} = \langle 0, -5 \rangle \), apply the format \( a \mathbf{i} + b \mathbf{j} \). Here, \( a = 0 \) and \( b = -5 \). Thus, \( \mathbf{u} = 0\mathbf{i} - 5\mathbf{j} \).
04

Simplify the Expression

Since any vector multiplied by 0 results in the zero vector, \( 0\mathbf{i} \) simplifies to 0. Therefore, \( \mathbf{u} = 0 - 5\mathbf{j} = -5\mathbf{j} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Vectors
Unit vectors are significant building blocks in the world of vectors. They act as reference points on a coordinate system. In a 2D vector space, we typically use two unit vectors:
  • The unit vector \( \mathbf{i} \) aligns with the x-axis. It has a magnitude of 1 and is represented as \( \langle 1, 0 \rangle \).
  • The unit vector \( \mathbf{j} \) aligns with the y-axis. It equally has a magnitude of 1, represented as \( \langle 0, 1 \rangle \).
Unit vectors are incredibly useful because they allow us to break down (or decompose) any 2D vector in terms of its components along the x-axis and y-axis. Therefore, any vector in the plane can be expressed as a combination of \( \mathbf{i} \) and \( \mathbf{j} \). In essence, they simplify complex vector operations, making calculations clear and easy to understand.
Vector Components
Vectors in 2D space are often described by their components: horizontal and vertical. These components tell us how far and in which direction the vector travels along both axes.
To translate a vector \( \langle a, b \rangle \) into notation using unit vectors:
  • The value \( a \) represents the x-component, showing how much the vector moves along the x-axis.
  • The value \( b \) represents the y-component, indicating movement along the y-axis.
For example, with a vector \( \langle 0, -5 \rangle \), the x-component is 0, meaning there's no movement along the x-axis, while the y-component is -5, indicating a movement of 5 units down along the y-axis. Expressing this using unit vectors, we write it as \( 0\mathbf{i} - 5\mathbf{j} \).
Understanding vector components is crucial for accurately representing and working with vectors in mathematics, physics, or any field involving directional quantities.
2D Vectors
Two-dimensional vectors define quantities that have both magnitude and direction on a plane. Unlike scalar quantities, which only tell you about the magnitude, vectors provide depth by including direction.
In a 2D vector, you have two parts:
  • Magnitude: This tells you how long or how far the vector extends in space. It's computed as \( \sqrt{a^2 + b^2} \) for a vector \( \langle a, b \rangle \).
  • Direction: Conveyed by the vector’s components themselves, showing where the vector points relative to the axes.
These characteristics are pivotal when calculating forces, velocities, displacements, or any other directional quantity. Once you understand 2D vectors, converting them into unit vector form becomes straightforward, as each component explicitly shows direction and magnitude separately.
For the vector \( \langle 0, -5 \rangle \), the magnitude is \( 5 \), and the direction is towards the negative y-axis. This simplicity makes 2D vectors an essential concept in vector analysis and numerous applications in physical sciences.

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