/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find the exact value of the trig... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the exact value of the trigonometric function. $$\cos 660^{\circ}$$

Short Answer

Expert verified
The exact value of \(\cos 660^{\circ}\) is \(\frac{1}{2}\).

Step by step solution

01

Understand the Problem

To find the exact value for \(\cos 660^{\circ}\), you need to understand the periodic nature of the cosine function. Cosine is a periodic function with a period of \(360^{\circ}\). This means that \(\cos\theta = \cos(\theta + 360^{\circ}k)\) for any integer \(k\).
02

Reduce the Angle

Since \(\cos 660^{\circ}\) is larger than \(360^{\circ}\), we can reduce it by finding an equivalent angle within \(0^{\circ}\) to \(360^{\circ}\). We do this by subtracting the period of \(360^{\circ}\) from \(660^{\circ}\): \[660^{\circ} - 360^{\circ} = 300^{\circ}.\]So, \(\cos 660^{\circ} = \cos 300^{\circ}\).
03

Use Known Values of Cosine

Now, find the value of \(\cos 300^{\circ}\). The angle \(300^{\circ}\) is in the fourth quadrant, where cosine is positive. The reference angle is \(360^{\circ} - 300^{\circ} = 60^{\circ}\). We know that \(\cos 60^{\circ} = \frac{1}{2}\). Thus, \(\cos 300^{\circ} = \frac{1}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine Function
The cosine function is one of the three fundamental trigonometric functions, primarily dealing with angles and sides of triangles. When you think about the cosine function, imagine the relationship of an angle in a right triangle to the adjacent side over the hypotenuse. Mathematically, for a given angle \( \theta \) in such a triangle, you express it as \( \cos \theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} \). This function provides insight into the "x-coordinate" of a point on the unit circle corresponding to an angle \( \theta \).
The cosine function has some critical properties:
  • Function Range: The cosine values range between -1 and 1.
  • Even Function: It's a significant attribute, showcasing symmetry, where \( \cos(-\theta) = \cos(\theta) \).
Understanding these properties is fundamental when dealing with angles in various quadrants, leading to more complex interpretations of angles beyond right triangles.
Angle Reduction
Angle reduction in trigonometry involves simplifying an angle to a more manageable form, often within the first full cycle of the unit circle, which is from \(0^{\circ}\) to \(360^{\circ}\). When working with angles like \(660^{\circ}\), reducing it makes calculations straightforward.
Reducing an angle involves using its periodic nature to find an angle within the familiar range:
  • Subtract \(360^{\circ}\) until the angle lies within \(0^{\circ}\) to \(360^{\circ}\).
  • For \(660^{\circ}\), the calculation becomes \(660^{\circ} - 360^{\circ} = 300^{\circ}\).
Understanding and applying angle reduction simplifies the problem by translating it into a context where trigonometric values like the cosine can be easily determined from known values or the unit circle.
Periodicity of Trigonometric Functions
Trigonometric functions, like cosine, exhibit periodic patterns. This means they repeat values in a defined interval. For cosine, this interval or "period" is every \(360^{\circ}\). The periodicity property states that for any integer \(k\), \(\cos(\theta + 360^{\circ}k) = \cos \theta\).
This periodicity is crucial for:
  • Solving problems analytically: It allows you to "cycle" or "reset" angles to more manageable figures within one revolution (\(0^{\circ}\) to \(360^{\circ}\)).
  • Ensuring predictability: Cosine values repeat at regular intervals, helping solve complex trigonometric problems with measurements beyond one full circle.
Grasping this concept is key to understanding how angles like \(660^{\circ}\) translate their cosine values to corresponding angles within the primary cycle, streamlining calculations and problem-solving.

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Most popular questions from this chapter

The four cases in which we can solve a triangle are $$ASA SSA SAS SSS$$ (a) In which of these cases can we use the Law of sines to solve the triangle? (b) Which of the cases listed can lead to more than one solution (the ambiguous case)?

Distance Across a River To find the distance across a river, a surveyor chooses points \(A\) and \(B\), which are 200 ft apart on one side of the river (see the figure). She then chooses a reference point \(C\) on the opposite side of the river and finds that \(\angle B A C=82^{\circ}\) and \(\angle A B C \approx 52^{\circ} .\) Approximate the distance from \(A\) to \(C\). (Image can't copy)

Soap Bubbles When two bubbles cling together in midair, their common surface is part of a sphere whose center \(D\) lies on the line passing through the centers of the bubbles (see the figure). Also, \(\angle A C B\) and \(\angle A C D\) each have measure \(60^{\circ} .\) (a) Show that the radius \(r\) of the common face is given by $$ r=\frac{a b}{a-b} $$ [Hint: Use the Law of Sines together with the fact that an angle \(\theta\) and its supplement \(180^{\circ}-\theta\) have the same sine.] (b) Find the radius of the common face if the radii of the bubbles are \(4 \mathrm{cm}\) and \(3 \mathrm{cm} .\) (c) What shape does the common face take if the two bubbles have equal radii? (Image can't copy)

The Leaning Tower of Pisa The bell tower of the cathedral in Pisa, Italy, leans \(5.6^{\circ}\) from the vertical. A tourist stands \(105 \mathrm{m}\) from its base, with the tower leaning directly toward her. She measures the angle of elevation to the top of the tower to be \(29.2^{\circ} .\) Find the length of the tower to the nearest meter.

A 125-ft tower is located on the side of a mountain that is inclined \(32^{\circ}\) to the horizontal. A guy wire is to be attached to the top of the tower and anchored at a point 55 ft downhill from the base of the tower. Find the shortest length of wire needed. (IMAGE CAN'T COPY)

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