Chapter 5: Problem 68
Find the values of the trigonometric functions of \(t\) from the given information. $$\csc t=5, \quad \cos t<0$$
Short Answer
Expert verified
\(\sin t = \frac{1}{5}, \cos t = -\frac{\sqrt{24}}{5}, \tan t = -\frac{1}{\sqrt{24}}\).
Step by step solution
01
Understanding Cosecant
The cosecant function, \( ext{csc } t\), is the reciprocal of the sine function. Therefore, if \( ext{csc } t = 5\), then \( ext{sin } t = \frac{1}{5}\). This is a key starting point to finding other trigonometric functions.
02
Using the Pythagorean Identity
The Pythagorean identity for trigonometric functions states that: \(\sin^2 t + \cos^2 t = 1\). Substituting \(\sin t = \frac{1}{5}\) into this identity, we have:\[\left(\frac{1}{5}\right)^2 + \cos^2 t = 1.\] Simplifying gives \(\cos^2 t = 1 - \frac{1}{25} = \frac{24}{25}\).
03
Determining the Sign of Cosine
Since \(\cos^2 t = \frac{24}{25}\), we take the square root to find \(\cos t\). This results in two possible values for \(\cos t\): \(\frac{\sqrt{24}}{5}\) or \(-\frac{\sqrt{24}}{5}\). Given the condition \(\cos t < 0\), we choose \(\cos t = -\frac{\sqrt{24}}{5}\).
04
Finding the Other Trigonometric Functions
With \(\sin t\) and \(\cos t\) known, we can find all other trigonometric functions:- \(\tan t = \frac{\sin t}{\cos t} = \frac{\frac{1}{5}}{-\frac{\sqrt{24}}{5}} = -\frac{1}{\sqrt{24}}\).- \(\cot t = \frac{1}{\tan t} = -\sqrt{24}\).- \(\sec t = \frac{1}{\cos t} = -\frac{5}{\sqrt{24}}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosecant
Cosecant, denoted as \( \csc t \), is one of the six fundamental trigonometric functions. It is defined as the reciprocal of the sine function. To put it simply, \( \csc t = \frac{1}{\sin t} \).
Understanding this relationship is crucial because if we are given the value of \( \csc t \), we can easily determine sine. For example, if \( \csc t = 5 \), then \( \sin t = \frac{1}{5} \). This understanding is a key building block for solving trigonometric problems, as it offers a straightforward path to finding the sine of an angle once the cosecant is known.
Understanding this relationship is crucial because if we are given the value of \( \csc t \), we can easily determine sine. For example, if \( \csc t = 5 \), then \( \sin t = \frac{1}{5} \). This understanding is a key building block for solving trigonometric problems, as it offers a straightforward path to finding the sine of an angle once the cosecant is known.
- Cosecant provides a direct link to sine.
- It is always greater than or equal to 1 or less than or equal to -1, since \( \sin t \) ranges only between -1 and 1.
Pythagorean identity
The Pythagorean identity is a fundamental concept in trigonometry that relates the squares of the sine and cosine functions. This identity is given by the equation: \[\sin^2 t + \cos^2 t = 1.\]
This equation holds true for any angle \( t \) and forms a basis for finding one function when the other is known. Substituting \( \sin t = \frac{1}{5} \), derived from \( \csc t = 5 \) into the identity, we get: \[\left(\frac{1}{5}\right)^2 + \cos^2 t = 1.\]
Simplifying, this results in: \[ \cos^2 t = 1 - \frac{1}{25} = \frac{24}{25}. \]This shows that \( \cos^2 t \) accounts for the remaining portion of the identity, revealing the importance of this identity in solving for cosine.
This equation holds true for any angle \( t \) and forms a basis for finding one function when the other is known. Substituting \( \sin t = \frac{1}{5} \), derived from \( \csc t = 5 \) into the identity, we get: \[\left(\frac{1}{5}\right)^2 + \cos^2 t = 1.\]
Simplifying, this results in: \[ \cos^2 t = 1 - \frac{1}{25} = \frac{24}{25}. \]This shows that \( \cos^2 t \) accounts for the remaining portion of the identity, revealing the importance of this identity in solving for cosine.
- Allows calculation of one function if another is known.
- Key tool in verifying correctness of trigonometric values.
Sine and Cosine
Sine and cosine are the most well-known trigonometric functions. They are fundamental in defining other trigonometric functions. Here’s how they work:
When we say \( \cos t < 0 \), it indicates that \( t \) is in the second or third quadrant of the unit circle (since cosine represents the x-coordinate). By using \( \sin t = \frac{1}{5} \), we understand that the angle is such that sine is quite small but positive, and cosine is negative, representing a specific point on the circle.
Finding \( \cos t \) involves ensuring it satisfies both the Pythagorean identity and the condition \( \cos t < 0 \). When \( \cos^2 t = \frac{24}{25} \), extracting roots gives two options: \( \sqrt{\frac{24}{25}} \) or \( -\sqrt{\frac{24}{25}} \). Here, we choose \( -\sqrt{\frac{24}{25}} \) due to the given condition.
- \( \sin t \) measures the y-coordinate on the unit circle, representing how far upward or downward a point is from the center.
- \( \cos t \) measures the x-coordinate, reflecting how far left or right the point is.
When we say \( \cos t < 0 \), it indicates that \( t \) is in the second or third quadrant of the unit circle (since cosine represents the x-coordinate). By using \( \sin t = \frac{1}{5} \), we understand that the angle is such that sine is quite small but positive, and cosine is negative, representing a specific point on the circle.
Finding \( \cos t \) involves ensuring it satisfies both the Pythagorean identity and the condition \( \cos t < 0 \). When \( \cos^2 t = \frac{24}{25} \), extracting roots gives two options: \( \sqrt{\frac{24}{25}} \) or \( -\sqrt{\frac{24}{25}} \). Here, we choose \( -\sqrt{\frac{24}{25}} \) due to the given condition.
- Critical for analyzing properties of angles and their measures.
- Sometimes referred to as coordinates in the unit circle framework.
Reciprocal Identities
Reciprocal identities connect the six trigonometric functions, linking them in pairs:
These identities simplify the work involved in finding less intuitive functions by using the basic ones. Reciprocal identities ensure that once you have a pair of primary functions (sine and cosine), you can derive the rest accurately.
- \( \csc t = \frac{1}{\sin t} \)
- \( \sec t = \frac{1}{\cos t} \)
- \( \cot t = \frac{1}{\tan t} \)
- \( \sec t = \frac{1}{\cos t} = -\frac{5}{\sqrt{24}} \)
- \( \cot t = \frac{1}{\tan t} = -\sqrt{24} \)
These identities simplify the work involved in finding less intuitive functions by using the basic ones. Reciprocal identities ensure that once you have a pair of primary functions (sine and cosine), you can derive the rest accurately.
- Facilitates transitions between different function calculations.
- Enables comprehensive analysis of trigonometric expressions.