/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Find the amplitude, period, and ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the amplitude, period, and horizontal shift of the function, and graph one complete period. $$y=\sin (\pi+3 x)$$

Short Answer

Expert verified
Amplitude: 1, Period: \(\frac{2\pi}{3}\), Horizontal Shift: \(-\frac{\pi}{3}\).

Step by step solution

01

Identify the Amplitude

The given function is in the form \( y = a \, \sin(bx + c) \), where \( a \) is the amplitude. For this function, \( y = \sin(\pi + 3x) \), there is no coefficient in front of \( \sin \), which means \( a = 1 \). Thus, the amplitude is 1.
02

Determine the Period

The formula for the period of a sine function \( y = \sin(bx + c) \) is \( \frac{2\pi}{|b|} \). For the function \( y = \sin(\pi + 3x) \), \( b = 3 \). Therefore, the period is calculated as \( \frac{2\pi}{3} \).
03

Calculate the Horizontal Shift

The horizontal shift (or phase shift) is given by \( \frac{-c}{b} \) for \( y = \sin(bx + c) \). In this function, \( c = \pi \). Thus, the horizontal shift is \( \frac{-\pi}{3} \). This means the graph shifts to the left by \( \frac{\pi}{3} \) units.
04

Graph the Function for One Complete Period

To graph the function, plot from the horizontal shift of \( \frac{-\pi}{3} \) (start) to the end of one period (\( \frac{2\pi}{3} \) units further), i.e., \( \frac{2\pi}{3} - \frac{\pi}{3} = \frac{\pi}{3} \) on the x-axis, where the graph completes one full sine wave.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
The amplitude of a trigonometric function, such as the sine function, represents the peak value, or maximum height, of the wave from its central axis. In simpler terms, it indicates how "tall" the wave rises or descends when you look at the function graphically. Particularly for a function in the form \( y = a \sin(bx + c) \), the coefficient \( a \) directly reflects the amplitude.When we examine the function \( y = \sin(\pi + 3x) \), there is no number multiplying the sine function, which implicitly suggests that \( a = 1 \). Therefore, the amplitude is 1. This means that from its middle point, the wave will reach up to 1 unit above and 1 unit below. Understanding amplitude helps predict the extent of variation in trigonometric functions.
Period
The period of a sine or cosine function refers to the length of one full cycle on the graph. A cycle is when the function starts from a specific point, goes through a peak and a trough, and returns to the starting point. For a general sine function \( y = \sin(bx + c) \), the period is calculated using the formula \( \frac{2\pi}{|b|} \).In our function \( y = \sin(\pi + 3x) \), the value of \( b \) is determined by the coefficient of \( x \) within the argument of the sine function, which is 3 here. Hence, the period is \( \frac{2\pi}{3} \). What does this mean graphically? It means the entire wave pattern of this sine function repeats every \( \frac{2\pi}{3} \) units along the x-axis. Knowing the period allows you to predict where the wave begins anew.
Horizontal Shift
The horizontal shift, also known as the phase shift, informs us how the graph of a trigonometric function moves left or right from its usual position. For a sinusoidal function in the format \( y = \sin(bx + c) \), the horizontal shift is found using \( \frac{-c}{b} \).Applying this to our function \( y = \sin(\pi + 3x) \), where \( c = \pi \) and \( b = 3 \), gives us a horizontal shift of \( \frac{-\pi}{3} \). This negative value signifies a leftward shift along the x-axis. Specifically, every point on the wave's graph has been translated left by \( \frac{\pi}{3} \) units compared to the standard sine wave's position. Recognizing the horizontal shift is crucial as it provides insight into how the start of the cycle is offset from the origin.

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