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Objects A and B are in harmonic motion modeled by \(y=3 \sin (2 t-\pi)\) and \(y=3 \sin \left(2 t-\frac{\pi}{2}\right) .\) The phase of \(A\) is ______, and the phase of \(\mathbf{B}\) is ______. The phase difference is ______, so the objects are moving ______ (in phase/out of phase).

Short Answer

Expert verified
The phase of A is \(-\pi\), the phase of B is \(-\frac{\pi}{2}\). The phase difference is \(\frac{\pi}{2}\); the objects are moving out of phase.

Step by step solution

01

Identify the General Form of Harmonic Motion

The general equation of harmonic motion is given by \( y = A \sin(\omega t + \phi) \), where \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( \phi \) is the phase angle. For the given equations, \( A = 3 \) and \( \omega = 2 \). We need to identify \( \phi \) for both objects A and B.
02

Determine the Phase of Object A

The equation for object A is \( y = 3 \sin(2t - \pi) \). Comparing with the general form \( y = 3 \sin(2t + \phi) \), we find the phase angle for A is \( \phi_A = -\pi \). This means the phase of object A is \(-\pi\).
03

Determine the Phase of Object B

The equation for object B is \( y = 3 \sin\left(2t - \frac{\pi}{2}\right) \). Comparing it to the general form, we find the phase angle for B is \( \phi_B = -\frac{\pi}{2} \). This means the phase of object B is \(-\frac{\pi}{2}\).
04

Calculate the Phase Difference

The phase difference between two objects is the absolute difference between their phase angles. Thus, the phase difference \( \Delta \phi \) is given by \( |\phi_A - \phi_B| = |-\pi - (-\frac{\pi}{2})| = |-\pi + \frac{\pi}{2}| = |-\frac{\pi}{2}| = \frac{\pi}{2} \).
05

Determine Relative Motion

To determine whether the objects are in phase or out of phase, we examine the phase difference. If the phase difference is 0, the objects are in phase; if it is not 0, they are out of phase. Since the phase difference is \( \frac{\pi}{2} \), objects A and B are out of phase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phase Angle
Understanding the phase angle is essential when discussing harmonic motion, such as the motion of objects A and B. The phase angle, denoted by \( \phi \), is a measure of how much the wave is shifted horizontally from a standard position, like the cosine or sine function starting point. In the general form of harmonic motion \( y = A \sin(\omega t + \phi) \), the phase angle represents this horizontal shift.

For object A, the equation is \( y = 3 \sin(2t - \pi) \). By comparing this with the general form, we find that \( \phi_A = -\pi \). This negative shift indicates that the wave for object A has moved to the right by \( \pi \) units.

Similarly, for object B defined by \( y = 3 \sin\left(2t - \frac{\pi}{2}\right) \), the phase angle is \( \phi_B = -\frac{\pi}{2} \). This tells us that object B’s wave has shifted to the right by \( \frac{\pi}{2} \) units.

Recognizing these phase angles helps us visualize how the waves for each object align at any given moment in time.
Angular Frequency
Angular frequency, represented by \( \omega \), is a key concept in harmonic motion and describes how rapidly an object moves through its oscillations. It is related to the period and frequency of the wave. In our equations for objects A and B, the angular frequency \( \omega = 2 \) signifies the rate at which the waves repeat over time.

This value of \( \omega \) suggests that both objects experience two complete cycles in a time frame equivalent to one period of the oscillation. Angular frequency is crucial as it influences the speed of oscillation for these objects. A higher angular frequency means a faster oscillation, while a lower one implies a slower movement.

Additionally, the constant angular frequency in both equations indicates that any differences in object behavior arise from other factors like phase angle rather than the speed of oscillation itself.
Phase Difference
The phase difference between two harmonic motion functions is a decisive factor in determining how these motions relate to each other. It is given by the absolute difference between their phase angles, \( \Delta \phi = |\phi_A - \phi_B| \).

For objects A and B, with \( \phi_A = -\pi \) and \( \phi_B = -\frac{\pi}{2} \), the calculated phase difference is \( \frac{\pi}{2} \). This can be computed as follows:

\[\Delta \phi = |\phi_A - \phi_B| = |-\pi + \frac{\pi}{2}| = |-\frac{\pi}{2}| = \frac{\pi}{2}.\]

This phase difference of \( \frac{\pi}{2} \) informs us that the objects are not oscillating in synchrony - they are out of phase. When two objects are out of phase, they do not reach their maximum or minimum positions simultaneously.

Understanding phase differences is crucial for predicting the behavior of oscillating systems, whether analyzing musical notes or electrical circuits.

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Most popular questions from this chapter

Circadian rhythms are biological processes that oscillate with a period of approximately 24 h. That is, a circadian rhythm is an internal daily biological clock. Blood pressure appears to follow such a rhythm. For a certain individual the average resting blood pressure varies from a maximum of 100 mmHg at 2:00 p.m. to a minimum of 80 mmHg at 2:00 a.m. Find a sine function of the form $$f(t)=a \sin (\omega(t-c))+b$$ that models the blood pressure at time \(t,\) measured in hours from midnight.

This exercise explores the effect of the inner function \(g\) on a composite function \(y=f(g(x))\) (a) Graph the function \(y=\sin \sqrt{x}\) using the viewing rectangle \([0,400]\) by \([-1.5,1.5]\). In what ways does this graph differ from the graph of the sine function? (b) Graph the function \(y=\sin \left(x^{2}\right)\) using the viewing rectangle \([-5,5]\) by \([-1.5,1.5]\). In what ways does this graph differ from the graph of the sine function?

Graph \(f, g,\) and \(f+g\) on a common screen to illustrate graphical addition. $$f(x)=\sin x, \quad g(x)=\sin 2 x$$

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