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Find the period, and graph the function. $$y=5 \csc 3 x$$

Short Answer

Expert verified
The period of the function is \( \frac{2\pi}{3} \) and repeat the graph structure around asymptotes at \( x = \frac{n\pi}{3} \).

Step by step solution

01

Understanding the Formula

The function given is a cosecant function, which is related to the sine function. The general form of a cosecant function is \( y = A \csc(Bx + C) + D \). In our case, \( A = 5 \), \( B = 3 \), \( C = 0 \), and \( D = 0 \).
02

Determine the Period of the Function

The period of a cosecant function \( y = A \csc(Bx + C) + D \) is determined by the formula \( \text{Period} = \frac{2\pi}{B} \). Substituting \( B = 3 \), we get \[ \text{Period} = \frac{2\pi}{3} \].
03

Identify Vertical Asymptotes

The function \( y = 5\csc(3x) \) has vertical asymptotes where the sine function in the cosecant becomes zero. This happens at \( 3x = n\pi \), where \( n \) is an integer. Solving for \( x \), the vertical asymptotes are at \( x = \frac{n\pi}{3} \).
04

Sketch the Graph Structure

Plot the vertical asymptotes derived in Step 3. The cosecant function will have branches between these asymptotes. Sketch curves going to infinity as they approach the asymptotes, with maximum and minimum points at the midway of the intervals determined by consecutive asymptotes. The amplitude of the function is controlled by \( A = 5 \).
05

Sketch One Complete Cycle

A complete cycle of the cosecant function starts at one asymptote and ends at the next. Given that the period is \( \frac{2\pi}{3} \), draw the high and low points at \( x = \frac{\pi}{6} + k\frac{2\pi}{3} \) for \( k \in \mathbb{Z} \), reaching values of \( 5 \) and \( -5 \). Continue the pattern to cover the entire graph as needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosecant Function
The cosecant function is one of the six fundamental trigonometric functions. It is defined as the reciprocal of the sine function. This means if you know the value of the sine of an angle, you can find the cosecant by taking its reciprocal. Mathematically, if \( y = \sin(x) \), then \( y = \csc(x) = \frac{1}{\sin(x)} \). The cosecant is undefined wherever the sine function is zero, leading to vertical asymptotes, which are crucial features of its graph.

Key characteristics of the cosecant function include:
  • The graph has a series of u-shaped curves called branches, finding themselves between vertical asymptotes where the sine function is zero.
  • These branches go towards infinity near the asymptotes, demonstrating the undefined nature of the cosecant when sine is zero.
  • The function is neither even nor odd; however, it is periodic just like the sine function.
The amplitude of the graph, dictated by the coefficient in front of the cosecant term, affects how tall the branches of the graph appear. In our case, the amplitude is 5, which amplifies the curve vertically.
Period of a Function
The period of a function describes how often the function repeats its pattern. For trigonometric functions such as the cosecant, the period is vital in predicting when the function will loop through its values again. In essence, it answers the question, "after how many units along the x-axis does the function start repeating?"

The period of the standard cosecant function \( y = \csc(x) \) is \( 2\pi \). However, in transformations of this function, like in our exercise where \( y = 5 \csc(3x) \), the period is altered by the coefficient of x inside the function. It is calculated using: \[\text{Period} = \frac{2\pi}{B} \]where \( B \) represents the coefficient of \( x \). For \( y = 5 \csc(3x) \), substituting \( B = 3 \), we find the period to be \( \frac{2\pi}{3} \). This means every \( \frac{2\pi}{3} \) units, the pattern of the graph repeats, justifying its cyclical nature.
Vertical Asymptotes
Vertical asymptotes are lines that the graph of a function approaches but never touches or crosses. For functions like the cosecant, these occur where the function is undefined. In the case of the cosecant function, vertical asymptotes occur where the sine function is zero, as the cosecant is the reciprocal of sine.

For our specific function \( y = 5 \csc(3x) \), vertical asymptotes are determined by setting the argument of the sine function, \( 3x \), equal to integer multiples of \( \pi \) (zeroes of sine), yielding:\[3x = n\pi \ \Rightarrow \ x = \frac{n\pi}{3} \]where \( n \) is an integer. This calculation tells us the x-values where our graph approaches infinity. These asymptotes guide how we plot the cosecant curve, ensuring that it arches away sharply at these points.
  • These vertical asymptotes mark the points of discontinuity in the graph.
  • Knowing them helps anticipate the overall shape of the function as it weaves and dances around these invisible barriers.
  • They are a crucial part of understanding and sketching the function’s behavior over its period.
Observing how the function behaves near asymptotes can aid greatly in grasping the concept of infinity in mathematics.

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Most popular questions from this chapter

This exercise explores the effect of the inner function \(g\) on a composite function \(y=f(g(x))\) (a) Graph the function \(y=\sin \sqrt{x}\) using the viewing rectangle \([0,400]\) by \([-1.5,1.5]\). In what ways does this graph differ from the graph of the sine function? (b) Graph the function \(y=\sin \left(x^{2}\right)\) using the viewing rectangle \([-5,5]\) by \([-1.5,1.5]\). In what ways does this graph differ from the graph of the sine function?

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