/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Find the period, and graph the f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the period, and graph the function. $$y=2 \tan \frac{\pi}{2} x$$

Short Answer

Expert verified
The period of the function \(y=2 \tan \frac{\pi}{2} x\) is 2.

Step by step solution

01

Identify the Tangent Function

The given function is \(y = 2 \tan \frac{\pi}{2} x\). This is a transformation of the basic tangent function \(y = \tan x\).
02

Determine the Coefficient Inside the Tangent Function

The coefficient inside the function is \(\frac{\pi}{2}\). This coefficient affects the period of the tangent function.
03

Calculate the Period of the Transformed Tangent Function

The period of a basic tangent function \(y = \tan x\) is \(\pi\). The period of the function \(y = 2 \tan \frac{\pi}{2} x\) is calculated as \(\frac{\pi}{\text{multiplier}} = \frac{\pi}{\frac{\pi}{2}} = 2\).
04

Graph the Function

To graph \(y = 2 \tan \frac{\pi}{2} x\), plot the key features of the tangent function such as the vertical asymptotes and the points where the function passes through zero in one full period from \(-1\) to \(1\). Since the period is 2, there will be vertical asymptotes at \(x = -1\) and \(x = 1\), and the function will pass through zero at \(x = 0\). The amplitude (the 2 in the function) affects the slope of the tangent graph but not the period.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
The tangent function is one of the primary trigonometric functions, often denoted as \(y = \tan x\). Unlike sine and cosine, which have a wave-like appearance, the graph of the tangent function exhibits a series of repeating vertical asymptotes and sections that increase or decrease sharply. This happens because the tangent function is undefined whenever the cosine component in the denominator equals zero, leading to vertical asymptotes at these points.
To better understand the behavior of the tangent function, it's essential to note the following characteristics:
  • The tangent function has vertical asymptotes where it is undefined, occurring at \(x = \frac{\pi}{2} + n\pi\), where \(n\) is any integer.
  • It intercepts the x-axis at \(x = n\pi\), where the value of the function is zero.
  • Within a period of the tangent function, it transitions from negative infinity to positive infinity or vice versa, which gives it a distinct shape compared to sine and cosine.

This function is significant in trigonometry, calculus, and various applications because it relates angles to the ratio of opposite to adjacent sides in right triangles.
Period of Trigonometric Functions
The period of a trigonometric function refers to the length of the interval over which the function completes one full cycle before repeating itself. Each trigonometric function has a distinct period, affecting how its graph appears over the x-axis.
For the basic function \(y = \tan x\), the period is \(\pi\). This means that after every \(\pi\) interval, the tangent function's graph looks the same.
When transformations occur, such as scaling the x-variable, the period of the function is altered. The formula to calculate the new period for a tangent function \(y = \tan(bx)\) is:
  • New period = \(\frac{\pi}{b}\)
In the exercise's function \(y = 2 \tan \frac{\pi}{2} x\), the multiplier is \(\frac{\pi}{2}\), resulting in a period of \(2\) calculated as \( \frac{\pi}{\frac{\pi}{2}} = 2\).
This change in period affects how frequently the graph repeats its cycle over the interval.
Graphing Trigonometric Functions
Graphing trigonometric functions involves mapping the unique features of the functions, such as their periodicity and asymptotic behavior. For tangent functions, this includes plotting vertical asymptotes, zeros, and the slope dictated by any amplitude changes.
To graph \(y = 2 \tan \frac{\pi}{2} x\), recognize the following key features of the graph:
  • Vertical asymptotes appear where the function is undefined. For this tangent function, asymptotes are at \(x = -1\) and \(x = 1\).
  • The zeros of the function occur at \(x = 0\), where the function crosses the x-axis.
  • Amplitudes influence the steepness of the curve, but not the period. The coefficient 2 in the function affects the rapidity of the increase or decrease of the tangent graph.

Begin by plotting the zeros and asymptotes, then sketch the increasing or decreasing sections according to the function's behavior. Keep in mind the period and amplitude adjustments when visualizing the final graph.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Alternating current is produced when an armature rotates about its axis in a magnetic field, as shown in the figure. Generators A and B rotate counterclockwise at 60 Hz (cycles per second) and each generator produces a maximum of 50 V. The voltage for each generator is modeled by $$E_{\mathrm{A}}=50 \sin (120 \pi t) \quad E_{\mathrm{B}}=50 \sin \left(120 \pi t-\frac{5 \pi}{4}\right)$$ (a) Find the voltage phase for each generator, and find the phase difference. (b) Are the generators producing voltage in phase? Through what angle should the armature in the second generator be rotated counterclockwise in order that the two generators produce voltage in phase?

Blood Pressure Each time your heart beats, your blood pressure first increases and then decreases as the heart rests between beats. The maximum and minimum blood pressures are called the systolic and diastolic pressures, respectively. Your blood pressure reading is written as systolic/diastolic. A reading of \(120 / 80\) is considered normal. A certain person's blood pressure is modeled by the function $$ p(t)=115+25 \sin (160 \pi t) $$ where \(p(t)\) is the pressure in \(\mathrm{mmHg}\) (millimeters of mercury), at time \(t\) measured in minutes. (a) Find the period of \(p\) (b) Find the number of heartbeats per minute. (c) Graph the function \(p\) (d) Find the blood pressure reading. How does this compare to normal blood pressure?

For each sine curve find the amplitude, period, phase, and horizontal shift. $$y=8 \sin 4\left(t+\frac{\pi}{12}\right)$$

A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one complete revolution every 20 s, find an equation that gives the height above the ground of a person on the Ferris wheel as a function of time. (Figure cant copy)

The terminal point \(P(x, y)\) determined by a real number \(t\) is given. Find \(\sin t\) \(\cos t,\) and \(\tan t.\) $$\left(-\frac{1}{2}, \frac{\sqrt{3}}{2}\right)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.