Chapter 5: Problem 27
Find the amplitude and period of the function, and sketch its graph. $$y=-\frac{1}{3} \cos \frac{1}{3} x$$
Short Answer
Expert verified
Amplitude: \( \frac{1}{3} \), Period: \( 6\pi \).
Step by step solution
01
Identify the Amplitude
The standard form of a cosine function is given by \[ y = a \cos(bx + c) + d \]. The amplitude of this function is determined by the absolute value of the coefficient \( a \). In this problem, \( a = -\frac{1}{3} \). Therefore, the amplitude is \( \left| -\frac{1}{3} \right| = \frac{1}{3} \).
02
Determine the Period
The period of the cosine function is found using the formula \( \frac{2\pi}{b} \), where \( b \) is the coefficient of \( x \). In this function, \( b = \frac{1}{3} \). Thus, the period is \[ \frac{2\pi}{\frac{1}{3}} = 6\pi \].
03
Sketch the Graph
To sketch the function \( y = -\frac{1}{3} \cos \frac{1}{3} x \), start by plotting one full period from \( 0 \) to \( 6\pi \). Begin at the maximum amplitude at \( x = 0 \), move to the minimum amplitude at \( x = 3\pi \), and return to the maximum at \( x = 6\pi \). The x-axis should be marked at intervals of \( \pi \) for proper scaling. The amplitude is \( \frac{1}{3} \), so the crests will be at \( y = \frac{1}{3} \) and the troughs will be at \( y = -\frac{1}{3} \). The graph is flipped vertically due to the negative amplitude.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
When we talk about the amplitude of a trigonometric function, we are essentially discussing the height of the wave created by the function. Specifically, in the context of a cosine function, amplitude measures how far the peaks and valleys of the wave are from the centerline, which is typically the x-axis.
Amplitude is always expressed as a positive value, derived from the coefficient in front of the cosine term. For the standard form of a cosine function, given as \( y = a \cos(bx + c) + d \), the amplitude is \( \left| a \right| \). Simply put, just take the absolute value of \( a \).
In the example function \( y = -\frac{1}{3} \cos \frac{1}{3}x \), the coefficient \( a \) is \( -\frac{1}{3} \). So, the amplitude is \( \left| -\frac{1}{3} \right| = \frac{1}{3} \). This tells us that the wave of the cosine function reaches \( \frac{1}{3} \) units above and below the x-axis. The negative sign indicates that the wave's direction is inverted.
Amplitude is always expressed as a positive value, derived from the coefficient in front of the cosine term. For the standard form of a cosine function, given as \( y = a \cos(bx + c) + d \), the amplitude is \( \left| a \right| \). Simply put, just take the absolute value of \( a \).
In the example function \( y = -\frac{1}{3} \cos \frac{1}{3}x \), the coefficient \( a \) is \( -\frac{1}{3} \). So, the amplitude is \( \left| -\frac{1}{3} \right| = \frac{1}{3} \). This tells us that the wave of the cosine function reaches \( \frac{1}{3} \) units above and below the x-axis. The negative sign indicates that the wave's direction is inverted.
Period of Functions
The term "period" in trigonometry refers to the distance over which a trigonometric function repeats its values. For periodic functions like the cosine function, the period is the length of one complete cycle of the wave.
In the equation \( y = a \cos(bx + c) + d \), the period can be calculated using the formula \( \frac{2\pi}{b} \), where \( b \) is the coefficient of \( x \). This formula tells us how long it takes for the wave to start repeating itself.
Let’s apply this to the function \( y = -\frac{1}{3} \cos \frac{1}{3}x \). Here, \( b \) is \( \frac{1}{3} \). Plugging this into the period formula, we get \( \frac{2\pi}{\frac{1}{3}} = 6\pi \). This means that the cosine function takes \( 6\pi \) units along the x-axis to complete one full oscillation and start over.
In the equation \( y = a \cos(bx + c) + d \), the period can be calculated using the formula \( \frac{2\pi}{b} \), where \( b \) is the coefficient of \( x \). This formula tells us how long it takes for the wave to start repeating itself.
Let’s apply this to the function \( y = -\frac{1}{3} \cos \frac{1}{3}x \). Here, \( b \) is \( \frac{1}{3} \). Plugging this into the period formula, we get \( \frac{2\pi}{\frac{1}{3}} = 6\pi \). This means that the cosine function takes \( 6\pi \) units along the x-axis to complete one full oscillation and start over.
Cosine Function
The cosine function is a fundamental trigonometric function that oscillates between -1 and 1. It describes the cosine of an angle in a right-angled triangle, but in the context of the Cartesian plane, it forms a wave-like pattern.
Written in its standard form as \( y = a \cos(bx + c) + d \), it illustrates several important attributes:
Written in its standard form as \( y = a \cos(bx + c) + d \), it illustrates several important attributes:
- Amplitude \( a \): How tall or short the wave is.
- Period: Determined by \( b \), as \( \frac{2\pi}{b} \), explaining how long it takes for the cycle to begin again.
- Vertical Shift \( d \): Moves the whole wave up or down.
- Phase Shift \( c \): Shifts the wave left or right along the x-axis.