Chapter 3: Problem 32
Find all rational zeros of the polynomial, and write the polynomial in factored form. $$P(x)=2 x^{3}+7 x^{2}+4 x-4$$
Short Answer
Expert verified
The rational zero is \( x = 2 \); factored form: \( (x - 2)(2x^2 + 11x + 26) \).
Step by step solution
01
Identify Potential Rational Zeros
Use the Rational Root Theorem, which suggests that any rational zero of the polynomial must be a factor of the constant term divided by a factor of the leading coefficient. The constant term is -4, and the leading coefficient is 2. Therefore, the potential rational zeros are \( \pm 1, \pm 2, \pm 4, \pm \frac{1}{2} \).
02
Test Potential Zeros Using Synthetic Division
Test each potential zero by performing synthetic division or direct substitution into the polynomial. Start with \( x = 1 \):\[P(1) = 2(1)^3 + 7(1)^2 + 4(1) - 4 = 9 \]Since \( P(1) eq 0 \), \( x = 1 \) is not a root. Try \( x = -1 \):\[P(-1) = 2(-1)^3 + 7(-1)^2 + 4(-1) - 4 = -3 \]Since \( P(-1) eq 0 \), \( x = -1 \) is not a root. Continue testing other values.
03
Check Another Potential Zero
Test \( x = 2 \):\[P(2) = 2(2)^3 + 7(2)^2 + 4(2) - 4 = 0\]Since \( P(2) = 0 \), \( x = 2 \) is a root. Now use synthetic division with this root to reduce the polynomial.
04
Perform Synthetic Division with x = 2
Perform synthetic division of \( 2x^3 + 7x^2 + 4x - 4 \) by \( x - 2 \):\[\begin{array}{r|rrrr}2 & 2 & 7 & 4 & -4 \ & & 4 & 22 & 52 \\hline & 2 & 11 & 26 & 0 \\end{array}\]The quotient is \( 2x^2 + 11x + 26 \), which we now need to factor further or solve.
05
Factor the Quadratic Polynomial
Try factoring or solving the quadratic equation \( 2x^2 + 11x + 26 = 0 \) using the quadratic formula, since it does not factor neatly:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-11 \pm \sqrt{11^2 - 4(2)(26)}}{4} \]\[x = \frac{-11 \pm \sqrt{121 - 208}}{4}\]\[x = \frac{-11 \pm \sqrt{-87}}{4} \]Since the roots are not real, the quadratic does not contribute rational zeros.
06
Write the Factors of the Polynomial
Since we only found one rational root, \( x = 2 \), the polynomial in factored form using the found root and the remaining quadratic is:\[P(x) = (x - 2)(2x^2 + 11x + 26) \]
07
Final Conclusion
The only rational zero of the polynomial is \( x = 2 \), and the polynomial in factored form is \( (x - 2)(2x^2 + 11x + 26) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Zeros
Finding the zeros of a polynomial is an essential step in understanding its behavior. Polynomial zeros are the values of \( x \) for which the polynomial equals zero. In other words, these are the \( x \)-values at which the graph of the polynomial intersects the \( x \)-axis.
To find potential rational zeros, one useful tool is the Rational Root Theorem. This theorem states that any rational root of a polynomial, with integer coefficients, is of the form \( \pm \frac{p}{q} \). Here, \( p \) is a factor of the constant term (the term without \( x \)), and \( q \) is a factor of the leading coefficient (the coefficient of the highest power of \( x \)).
For the polynomial \( P(x) = 2x^3 + 7x^2 + 4x - 4 \):
To find potential rational zeros, one useful tool is the Rational Root Theorem. This theorem states that any rational root of a polynomial, with integer coefficients, is of the form \( \pm \frac{p}{q} \). Here, \( p \) is a factor of the constant term (the term without \( x \)), and \( q \) is a factor of the leading coefficient (the coefficient of the highest power of \( x \)).
For the polynomial \( P(x) = 2x^3 + 7x^2 + 4x - 4 \):
- The constant term is \(-4\).
- The leading coefficient is \(2\).
Synthetic Division
Synthetic division is a simplified form of polynomial division. It's a quick way to divide a polynomial by a binomial of the form \( x - c \). The method streamlines the division process, making it faster and less error-prone than long division.
To perform synthetic division, you follow these steps:
To perform synthetic division, you follow these steps:
- Arrange the polynomial's coefficients in descending order.
- Write down the root to be tested outside the division bracket.
- Bring down the first coefficient to the bottom row.
- Multiply this number by the root and place the result under the next coefficient.
- Add this result to the next coefficient, and repeat the steps for all coefficients.
- We start with coefficients \(2, 7, 4, -4\).
- After the process, if the last number is zero, \( x = 2 \) is indeed a root, and the bottom row gives the coefficients of the reduced polynomial.
Quadratic Formula
When confronted with a quadratic polynomial that doesn’t factor neatly, the quadratic formula is an invaluable solution method. This formula finds the zeros of any quadratic equation \( ax^2 + bx + c = 0 \). The quadratic formula is: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula computes the roots by evaluating the discriminant \( b^2 - 4ac \), which determines the nature of the roots:
This formula computes the roots by evaluating the discriminant \( b^2 - 4ac \), which determines the nature of the roots:
- If it’s positive, there are two distinct real roots.
- If zero, there's exactly one real root.
- If negative, the roots are complex and non-real.