Chapter 2: Problem 81
If \(f(x)=\sqrt{2 x-x^{2}}\) graph the following functions in the viewing rectangle \([-5,5]\) by \([-4,4] .\) How is each graph related to the graph in part (a)? (a) \(y=f(x)\) (b) \(y=f(2 x)\) (c) \(y=f\left(\frac{1}{2} x\right)\)
Short Answer
Expert verified
Each graph is a horizontal scaling of the original semi-circle by factors of \( \frac{1}{2} \) for (b) and 2 for (c).
Step by step solution
01
Understand the Basic Function
The original function is given as \( f(x) = \sqrt{2x - x^2} \). This function is defined where the expression inside the square root is non-negative, i.e., \( 2x - x^2 \geq 0 \). Solve for \( x \) to find the domain of \( f(x) \). This leads to \( x(2-x) \geq 0 \), meaning \( 0 \leq x \leq 2 \). The maximum point of this quadratic is at \( x = 1 \). So, the graph of \( f(x) \) is a semi-circle from \( x = 0 \) to \( x = 2 \), with a maximum point at \( x = 1 \).
02
Graphing the Original Function
Graph the function \( y = f(x) \) on the interval \([-5, 5]\) by \([-4, 4]\). Only values of \( x \) from \( 0 \) to \( 2 \) will contribute to this graph, showing a semi-circle arc between these points with the peak at \( x = 1 \) corresponding to \( y = 1 \).
03
Adjust the Function for Scaling Factor in x-axis for (b)
For part (b), graph the function \( y = f(2x) \). Substitute \( 2x \) for \( x \) in the original function: \( f(2x) = \sqrt{2(2x) - (2x)^2} = \sqrt{4x - 4x^2} \), resulting in \( f(2x) = \sqrt{4x(1-x)} \). The domain for this new function will be \( 0 \leq 2x \leq 2 \) or \( 0 \leq x \leq 1 \). Graphically, this compresses the semi-circle horizontally by a factor of 2.
04
Graph the Adjusted Function for Part (b)
On the viewing rectangle \([-5, 5]\) by \([-4, 4]\), plot the function \( y = f(2x) \) which will appear as a semi-circle from \( x = 0 \) to \( x = 1 \) with the same maximum height of \( 1 \) but "squished" twice as much horizontally compared to part (a).
05
Adjust the Function for Scaling Factor in x-axis for (c)
For part (c), graph the function \( y = f\left(\frac{1}{2}x\right) \). Substitute \( \frac{1}{2}x \) for \( x \) in the original function: \( f\left(\frac{1}{2}x\right) = \sqrt{2\left(\frac{1}{2}x\right) - \left(\frac{1}{2}x\right)^2} = \sqrt{x - \frac{1}{4}x^2} \). The domain of this function is \( 0 \leq \frac{1}{2}x \leq 2 \) or \( 0 \leq x \leq 4 \). Graphically, this expands the semi-circle horizontally by a factor of 2.
06
Graph the Adjusted Function for Part (c)
On the same viewing rectangle, plot \( y = f\left(\frac{1}{2}x\right) \), which will appear as a semi-circle from \( x = 0 \) to \( x = 4 \), stretching it twice as much in the horizontal direction compared to part (a), again reaching a maximum height of \( 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Functions
Graphing functions is a crucial skill in mathematics, as it allows us to visually represent and understand the behavior of equations. When graphing a function like the given \( f(x) = \sqrt{2x - x^2} \), we start by identifying the important features such as the **domain**, **range**, and any **symmetries**. These characteristics influence how the graph looks and behaves.
One practical way to graph functions is by using a viewing rectangle, where we specify the limits for the x-axis and y-axis. For instance, in this exercise, the viewing rectangle is \([-5,5]\) by \([-4,4]\). These boundaries help in focusing on the part of the graph that we are interested in analyzing. Plotting different versions of functions, such as \( f(2x) \) or \( f\left(\frac{1}{2}x\right) \), shows how transformations affect the graph's shape and size.
One practical way to graph functions is by using a viewing rectangle, where we specify the limits for the x-axis and y-axis. For instance, in this exercise, the viewing rectangle is \([-5,5]\) by \([-4,4]\). These boundaries help in focusing on the part of the graph that we are interested in analyzing. Plotting different versions of functions, such as \( f(2x) \) or \( f\left(\frac{1}{2}x\right) \), shows how transformations affect the graph's shape and size.
- **Horizontal Compression/Expansion**: Multiplying x by a factor affects the graph's width. If the factor is greater than 1, the function compresses. If less than 1, it expands.
- **Understanding Transformations**: Helps predict function behavior without plotting every time.
Domain and Range
The domain and range of a function give us crucial information about where the function is defined and what values it can take. For the function \( f(x) = \sqrt{2x - x^2} \), the domain is determined by the requirement that the expression inside the square root must be non-negative. This ensures that all calculations are valid since the square root of a negative number is not real.
To find the domain, solve the inequality \( 2x - x^2 \geq 0 \). Factor this as \( x(2-x) \geq 0 \), which leads us to the interval \( 0 \leq x \leq 2 \). This tells us that the only acceptable x-values are between 0 and 2, inclusive.
The range of the function comes from the values that \( \sqrt{2x - x^2} \) can output. As this is essentially the arc of a semi-circle, it spans from \( y = 0 \) to its peak at \( y = 1 \). Therefore, the range of \( f(x) \) is \( 0 \leq y \leq 1 \). Understanding the domain and range not only helps in graphing but also in solving real-world problems by defining the scope of a function’s applicability.
To find the domain, solve the inequality \( 2x - x^2 \geq 0 \). Factor this as \( x(2-x) \geq 0 \), which leads us to the interval \( 0 \leq x \leq 2 \). This tells us that the only acceptable x-values are between 0 and 2, inclusive.
The range of the function comes from the values that \( \sqrt{2x - x^2} \) can output. As this is essentially the arc of a semi-circle, it spans from \( y = 0 \) to its peak at \( y = 1 \). Therefore, the range of \( f(x) \) is \( 0 \leq y \leq 1 \). Understanding the domain and range not only helps in graphing but also in solving real-world problems by defining the scope of a function’s applicability.
Quadratic Functions
Quadratic functions are a fundamental type of polynomial that takes the standard form \( ax^2 + bx + c \). The given function, \( f(x) = \sqrt{2x - x^2} \), originally derives from a quadratic expression, \( 2x - x^2 \). Recognizing it in this form allows us to explore its properties and transformations more deeply.
In its quadratic form, \( 2x - x^2 \) can be rewritten to emphasize the parabola's shape: \( -(x^2 - 2x) \). The negative sign indicates that it opens downwards. Completing the square helps to identify the vertex and maximum value, crucial for graphing and transformations:
In its quadratic form, \( 2x - x^2 \) can be rewritten to emphasize the parabola's shape: \( -(x^2 - 2x) \). The negative sign indicates that it opens downwards. Completing the square helps to identify the vertex and maximum value, crucial for graphing and transformations:
- Vertex Formula: The vertex occurs at \( x = \frac{-b}{2a} \). Here, \( x = 1 \) gives the maximum point.
- Axis of Symmetry: Provides symmetry line important for graph perfection.