/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Find a function whose graph is t... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a function whose graph is the given curve. The top half of the circle \(x^{2}+y^{2}=9\)

Short Answer

Expert verified
The function is \( y = \sqrt{9 - x^2} \).

Step by step solution

01

Identify the equation of the circle

The given equation represents a circle centered at the origin with radius 3. This is determined by comparing the equation with the standard circle equation \[ x^2 + y^2 = r^2 \] where the radius \(r\) is 3.
02

Solve for y

To find the equation of the curve representing the top half of the circle, we solve for \(y\) in terms of \(x\). Start with the equation \(x^2 + y^2 = 9\) and isolate \(y^2\):\[ y^2 = 9 - x^2 \]Then, take the square root of both sides:\[ y = \pm\sqrt{9 - x^2} \]
03

Choose the positive square root

Since the problem asks for the top half of the circle, use the positive square root. This is because the top half of the circle is when \(y\) is positive. So, the function is:\[ y = \sqrt{9 - x^2} \]
04

State the function

The function representing the top half of the circle \(x^2 + y^2 = 9\) is \[ y = \sqrt{9 - x^2} \]This function is defined for \(-3 \leq x \leq 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radius of a Circle
The radius of a circle is a fundamental concept in geometry, which determines the size of the circle. It is the distance from the center of the circle to any point on its circumference.
For any circle represented by the equation \(x^2 + y^2 = r^2\), the radius \(r\) can be directly obtained.
In our exercise, the circle is defined by the equation \(x^2 + y^2 = 9\). By comparing it with the standard form, we immediately find that the radius is 3, because \(r^2 = 9\) implies \(r = \sqrt{9} = 3\).
Understanding the radius helps to visualize the circle and understand its properties, like where its boundary lies based on its center.
Solving for y
Solving for \(y\) is a common step in rearranging equations to isolate a specific variable. This is particularly useful for converting an equation into a function that can be graphically represented.
In equations like \(x^2 + y^2 = 9\), solving for \(y\) involves rearranging terms to express \(y\) in terms of \(x\).
By subtracting \(x^2\) from each side, we have \(y^2 = 9 - x^2\). Taking the square root of both sides gives us \(y = \pm\sqrt{9 - x^2}\). The \(\pm\) symbol indicates that there are two potential values for \(y\) — one for the top half of the circle (positive) and one for the bottom half (negative).
Understanding this helps in situations where you need to determine one branch of a curve, such as the top half of a circle.
Graph of a Function
The graph of a function is a visual representation that showcases the relationship between its variables. When dealing with circles, or any other shape, transforming an equation into a function form enables graphing specific parts of the shape.
In the context of the original exercise, once we solve \(y = \sqrt{9 - x^2}\) for the top half of the circle, we now have a function that can be graphed on a coordinate plane.
Graphing this function, you'll see a semi-circle that rises from left to right as \(x\) moves from -3 to 3. This visually translates the abstract mathematical equation into a curve that can be understood and analyzed easily.
Domain of a Function
The domain of a function refers to all the possible values of \(x\) for which the function is defined. It is essential for determining how far left and right a function's graph extends in the coordinate plane.
For the function \(y = \sqrt{9 - x^2}\), the values under the square root, \(9 - x^2\), must be non-negative (i.e., greater than or equal to zero) for the function to be real and valid.
  • The inequality \(9 - x^2 \geq 0\) leads to \(-3 \leq x \leq 3\), meaning the domain of this function is all real numbers \(x\) from -3 to 3.

This ensures the function captures the shape we want — specifically, the top half of the circle corresponding to the original equation \(x^2 + y^2 = 9\). Understanding the domain helps confirm this part of the graph is plotted correctly.

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Most popular questions from this chapter

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