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Find the domain of the function. $$g(x)=\sqrt{x^{2}-2 x-8}$$

Short Answer

Expert verified
The domain of \(g(x)\) is \(( -\infty, -2 ] \cup [ 4, \infty )\).

Step by step solution

01

Understand the Function Inside the Square Root

To find the domain of the function, we need to determine the values of \(x\) for which the expression inside the square root, \(x^2 - 2x - 8\), is greater than or equal to zero. This is because the square root function is only defined for non-negative numbers.
02

Solve the Inequality

We set up the inequality \(x^2 - 2x - 8 \geq 0\) and solve it. First, we find the roots of the quadratic equation \(x^2 - 2x - 8 = 0\) by factoring. The factors are \((x-4)(x+2) = 0\), giving the solutions \(x = 4\) and \(x = -2\).
03

Analyze the Intervals

Using these roots, we divide the number line into intervals: \((-\infty, -2)\), \([-2, 4]\), and \((4, \infty)\). We test each interval to see where the inequality holds. The expression \((x-4)(x+2)\) is positive for \(x \leq -2\) and \(x \geq 4\), and negative between those intervals.
04

Construct the Domain

Since the inequality holds at values where \(x \leq -2\) or \(x \geq 4\), the domain of \(g(x)\) is the union of these intervals: \(( -\infty, -2 ] \cup [ 4, \infty )\). The square brackets indicate that the endpoints are included since the inequality is non-strict (\(\geq\)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Inequalities
Understanding quadratic inequalities is vital when dealing with functions like \( g(x) = \sqrt{x^2 - 2x - 8} \). Here, the expression inside the square root must be non-negative; hence, we solve the inequality \( x^2 - 2x - 8 \geq 0 \).

A quadratic inequality involves expressions of the form \( ax^2 + bx + c \leq 0 \), \( ax^2 + bx + c \geq 0 \), and their strict forms. The solutions to these inequalities are generally found using the roots of the associated quadratic equation, which in our case are \(x = 4\) and \(x = -2\). These roots are found using techniques like factoring or the quadratic formula.

Once you have the roots, the number line can be divided into intervals. Each interval is tested to determine if it satisfies the inequality. For \( g(x) = \sqrt{x^2 - 2x - 8} \), the inequality holds true for \( x \leq -2 \) and \( x \geq 4 \), forming the basis of the domain for the function. Understanding how intervals work in relation to inequalities is crucial for finding function domains.
Square Root Functions
Square root functions are defined only for non-negative values. This limitation requires us to ensure that the expression under the square root, or "radicand," is zero or positive.

For the function \( g(x) = \sqrt{x^2 - 2x - 8} \), the radicand \( x^2 - 2x - 8 \) needs to be evaluated such that it meets this criterion. If \( x^2 - 2x - 8 \) turns out to be negative, \( g(x) \) cannot produce a real number. Hence, identifying the proper domain involves solving the inequality \( x^2 - 2x - 8 \geq 0 \).

When working with square root functions, always pay attention to the values that can turn the radicand negative. This is key in correctly identifying the domain. For \( g(x) \), the domain is \(( -\infty, -2 ] \cup [ 4, \infty )\), where these intervals guarantee that the radicand is non-negative, allowing the square root to produce real and valid outputs.
Factoring Quadratics
Factoring quadratics is a powerful technique when solving equations and inequalities. It helps in simplifying quadratic expressions into their linear components, making them easier to analyze.

For the quadratic expression \( x^2 - 2x - 8 = 0 \), we seek factors that multiply to \(-8\) and add up to \(-2\). These factors are \( (x-4) \) and \( (x+2) \), since \(-4\) and \(+2\) multiply to enter \(-8\) and sum to \(-2\).

By setting these factors equal to zero, we find the roots \(x = 4\) and \(x = -2\). These roots are critical for establishing intervals on the number line where the quadratic inequality holds. Factoring is often faster and more straightforward than using the quadratic formula for solving simple quadratics. However, it's important to always check your work. Incorrect factors can lead to wrong interval conclusions and, subsequently, an incorrect domain for functions like \( g(x) = \sqrt{x^2 - 2x - 8} \).

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Most popular questions from this chapter

DISCUSS: Solving an Equation for an Unknown Function In Exercises \(69-72\) of Section 2.7 you were asked to solve equations in which the unknowns are functions. Now that we know about inverses and the identity function (see Exercise 104 ), we can use algebra to solve such equations. For instance, to solve \(f \circ g=h\) for the unknown function \(f,\) we perform the following steps: \(f^{\circ} g=h \quad\) Problem: Solve for \(f\) \(f^{\circ} g^{\circ} g^{-1}=h^{\circ} g^{-1} \quad\) Compose with \(g^{-1}\) on the right \(f \circ I=h \cdot g^{-1} \quad \text { Because } g^{\circ} g^{-1}=I\) \(f=h e g^{-1} \quad\) Because \(f \circ I=f\) So the solution is \(f=h \circ g^{-1} .\) Use this technique to solve the equation \(f \circ g=h\) for the indicated unknown function. (a) Solve for \(f,\) where \(g(x)=2 x+1\) and \(h(x)=4 x^{2}+4 x+7.\) (b) Solve for \(q,\) where \(f(x)=3 x+5\) and \(h(x)=3 x^{2}+3 x+2.\)

Sketch the graph of each function. (a) \(f(x)=4 x-x^{2}\) (b) \(g(x)=\left|4 x-x^{2}\right|\)

DISCUSS: Even and Odd Power Functions What must be true about the integer \(n\) if the function $$ f(x)=x^{n} $$ is an even function? If it is an odd function? Why do you think the names "even" and "odd" were chosen for these function properties?

As a weather balloon is inflated, the thickness \(T\) of its rubber skin is related to the radius of the balloon by $$T(r)=\frac{0.5}{r^{2}}$$ where \(T\) and \(r\) are measured in centimeters. Graph the function \(T\) for values of \(r\) between 10 and \(100 .\)

DISCUSS DISCOVER: Minimizing a Distance When we seek a minimum or maximum value of a function, it is sometimes easier to work with a simpler function instead. (a) Suppose $$g(x)=\sqrt{f(x)}$$ where \(f(x) \geq 0\) for all \(x .\) Explain why the local minima and maxima of \(f\) and \(g\) occur at the same values of \(x .\) (b) Let \(g(x)\) be the distance between the point \((3,0)\) and the point \(\left(x, x^{2}\right)\) on the graph of the parabola \(y=x^{2}\) Express \(g\) as a function of \(x\) (c) Find the minimum value of the function \(g\) that you found in part (b). Use the principle described in part (a) to simplify your work.

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